RosettaCodeData/Task/Fibonacci-sequence/Haskell/fibonacci-sequence-18.hs

2 lines
78 B
Haskell
Raw Permalink Normal View History

2018-06-22 20:57:24 +00:00
g (n,(a,b)) = (2*n,(2*a*b-a*a,a*a+b*b)) -- iterate g (1,(1,1)) ; a is nth