2023-07-01 11:58:00 -04:00
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-- MAXScript : Babbage problem : N.H.
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posInt = 1
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while posInt < 1000000 do
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2026-02-01 16:33:20 -08:00
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(
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if (matchPattern((posInt * posInt) as string) pattern: "*269696") then exit
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posInt += 1
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)
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2023-07-01 11:58:00 -04:00
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Print "The smallest number whose square ends in 269696 is " + ((posInt) as string)
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Print "Its square is " + (((pow posInt 2) as integer) as string)
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