RosettaCodeData/Task/Substring/11l/substring.11l

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2023-07-01 11:58:00 -04:00
V s = abcdefgh
V n = 2
V m = 3
V char = d
V chars = cd
print(s[n - 1 .+ m]) // starting from n=2 characters in and m=3 in length
print(s[n - 1 ..]) // starting from n characters in, up to the end of the string
print(s[0 .< (len)-1]) // whole string minus last character
print(s[s.index(char) .+ m]) // starting from a known character char="d" within the string and of m length
print(s[s.index(chars) .+ m]) // starting from a known substring chars="cd" within the string and of m length