RosettaCodeData/Task/Binary-strings/E/binary-strings-6.e

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2013-04-10 16:57:12 -07:00
? bstr1(1, 2)
# value: [2]
? bstr.replace(0, bstr.size(), bstr2, 1, 3)
? bstr
# value: [2, 3].diverge()