RosettaCodeData/Task/FizzBuzz/XPath-2.0/fizzbuzz-2.xpath

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2016-12-05 23:44:36 +01:00
for $n in 1 to 100 return
($n, 'Fizz', 'Buzz', 'FizzBuzz')[number(($n mod 3) = 0) + number(($n mod 5) = 0)*2 + 1]