RosettaCodeData/Task/Floyds-triangle/Python/floyds-triangle-2.py

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Python
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2013-04-10 21:29:02 -07:00
def floyd(rowcount=5):
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return [list(range(i * (i - 1) // 2 + 1, i * (i + 1) // 2 + 1))
for i in range(1, rowcount + 1)]