10 lines
182 B
Python
10 lines
182 B
Python
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import re
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def lookandsay(str):
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return re.sub(r'(.)\1*', lambda m: str(len(m.group(0))) + m.group(1), str)
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num = "1"
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for i in range(10):
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print num
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num = lookandsay(num)
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