11 lines
212 B
Ruby
11 lines
212 B
Ruby
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def nthroot(n, a, precision = 1e-5)
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x = Float(a)
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begin
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prev = x
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x = ((n - 1) * prev + a / (prev ** (n - 1))) / n
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end while (prev - x).abs > precision
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x
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end
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p nthroot(5,34) # => 2.02439745849989
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