Data update

Task/Arithmetic-derivative/MiniScript/arithmetic-derivative.mini

@@ -0,0 +1,43 @@
+lagarias = function (n) // Lagarias arithmetic derivative
+   if n < 0 then
+       return -lagarias (-n)
+   else if n == 0 or n == 1 then
+       return 0
+   else
+       smallPf = function (j, k) // Smallest prime factor
+           if j % k == 0 then
+               return k
+           else
+               return smallPf (j, k + 1)
+           end if
+       end function
+       f = smallPf (n, 2)
+       q = floor (n / f)
+       if q == 1 then
+           return 1
+       else
+           return q * lagarias (f) + f * lagarias (q)
+       end if
+   end if
+end function
+fmt6 = function (n) // return a 6 character string representation of n
+    s = str( n )
+    if s.len > 5 then
+        return s
+    else
+        return ( " " * ( 6 - s.len ) ) + s
+    end if
+end function
+ad = ""
+for n in range( -99, 100 )
+    ad = ad + " " + fmt6( lagarias (n) )
+    if n % 10 == 0 then
+        print( ad )
+        ad = ""
+    end if
+end for
+print()
+for n in range( 1, 17 )    // 18, 19 and 20 would overflow ????? TODO: check
+    m = 10 ^ n
+    print( "D(" + str(m) + ") / 7 = " + str( floor (lagarias (m) / 7) ) )
+end for