Data update

This commit is contained in:
Ingy döt Net 2026-02-01 16:33:20 -08:00
parent 5150844a7d
commit 4bb20c9b71
7735 changed files with 38060 additions and 199180 deletions

View file

@ -2,29 +2,18 @@ BEGIN
# find the numbers the string 123456789 ( with "+/-" optionally inserted #
# before each digit ) can generate #
# experimentation shows that the largest hundred numbers that can be #
# generated are are greater than or equal to 56795 #
# as we can't declare an array with bounds -123456789 : 123456789 in #
# Algol 68G, we use -60000 : 60000 and keep counts for the top hundred #
PR read "sort.incl.a68" PR # include sorting utilities #
INT max number = 60 000;
[ - max number : max number ]STRING solutions;
[ - max number : max number ]INT count;
FOR i FROM LWB solutions TO UPB solutions DO solutions[ i ] := ""; count[ i ] := 0 OD;
# calculate the numbers we can generate and the strings leading to them #
# as noted by other solutions, at most 13122 (2*3^8) can be generated #
# calculate the numbers ( up to max number ) we can generate and the strings leading to them #
# also determine the largest numbers we can generate #
[ 100 ]INT largest;
[ 100 ]INT largest count;
INT impossible number = - 999 999 999;
FOR i FROM LWB largest TO UPB largest DO
largest [ i ] := impossible number;
largest count[ i ] := 0
OD;
INT max expr = 2 * 3^8;
[ 1 : max expr ]INT value;
[ 1 : max expr ]STRING expression;
INT expr pos := 0;
[ 1 : 18 ]CHAR sum string := ".1.2.3.4.5.6.7.8.9";
[]CHAR sign char = []CHAR( "-", " ", "+" )[ AT -1 ];
# we don't distinguish between strings starting "+1" and starting " 1" #
FOR s1 FROM -1 TO 0 DO
FOR s1 FROM -1 TO 0 DO # we don't distinguish between strings starting "+1" and starting " 1" #
sum string[ 1 ] := sign char[ s1 ];
FOR s2 FROM -1 TO 1 DO
sum string[ 3 ] := sign char[ s2 ];
@ -52,28 +41,10 @@ BEGIN
IF s7 = 0 THEN part *:= 10 +:= 7 * SIGN part ELSE number +:= part; part := 7 * s7 FI;
IF s8 = 0 THEN part *:= 10 +:= 8 * SIGN part ELSE number +:= part; part := 8 * s8 FI;
IF s9 = 0 THEN part *:= 10 +:= 9 * SIGN part ELSE number +:= part; part := 9 * s9 FI;
number +:= part;
IF number >= LWB solutions AND number <= UPB solutions THEN
solutions[ number ] +:= ";" + sum string;
count [ number ] +:= 1
FI;
BOOL inserted := FALSE;
FOR l pos FROM LWB largest TO UPB largest WHILE NOT inserted DO
IF number > largest[ l pos ] THEN
# found a new larger number #
FOR m pos FROM UPB largest BY -1 TO l pos + 1 DO
largest [ m pos ] := largest [ m pos - 1 ];
largest count[ m pos ] := largest count[ m pos - 1 ]
OD;
largest [ l pos ] := number;
largest count[ l pos ] := 1;
inserted := TRUE
ELIF number = largest[ l pos ] THEN
# have another way of generating this number #
largest count[ l pos ] +:= 1;
inserted := TRUE
FI
OD
number +:= part;
expr pos +:= 1;
expression[ expr pos ] := sum string;
value[ expr pos ] := number
OD
OD
OD
@ -85,45 +56,66 @@ BEGIN
OD;
# show the solutions for 100 #
print( ( "100 has ", whole( count[ 100 ], 0 ), " solutions:" ) );
STRING s := solutions[ 100 ];
FOR s pos FROM LWB s TO UPB s DO
IF s[ s pos ] = ";" THEN print( ( newline, " " ) )
ELIF s[ s pos ] /= " " THEN print( ( s[ s pos ] ) )
INT count 100 := 0;
FOR x pos FROM LWB value TO UPB value DO
IF value[ x pos ] = 100 THEN count 100 +:= 1 FI
OD;
print( ( "100 has ", whole( count 100, 0 ), " solutions:", newline ) );
FOR x pos FROM LWB value TO UPB value DO
IF value[ x pos ] = 100 THEN
print( ( " " ) );
STRING s = expression[ x pos ];
FOR s pos FROM LWB s TO UPB s DO IF s[ s pos ] /= " " THEN print( ( s[ s pos ] ) ) FI OD;
print( ( newline ) )
FI
OD;
print( ( newline ) );
QUICKSORT value; # sort the values (the expressions will now be out of order) #
# find the number with the most solutions #
INT max solutions := 0;
INT number with max := LWB count - 1;
FOR n FROM 0 TO max number DO
IF count[ n ] > max solutions THEN
max solutions := count[ n ];
number with max := n
INT this count := 1, max count := 1, max count value := value[ LWB value ];
FOR v pos FROM LWB value + 1 TO UPB value DO
IF value[ v pos ] = value[ v pos - 1 ] THEN
this count +:= 1
ELSE
IF this count > max count AND value[ v pos - 1 ] >= 0 THEN
max count := this count;
max count value := value[ v pos - 1 ]
FI;
this count := 1
FI
OD;
FOR n FROM LWB largest count TO UPB largest count DO
IF largest count[ n ] > max solutions THEN
max solutions := largest count[ n ];
number with max := largest[ n ]
FI
OD;
print( ( whole( number with max, 0 ), " has the maximum number of solutions: " ) );
print( ( whole( max solutions, 0 ), newline ) );
# find the smallest positive number that has no solutions #
BOOL have solutions := TRUE;
FOR n FROM 0 TO max number
WHILE IF NOT ( have solutions := count[ n ] > 0 )
THEN print( ( whole( n, 0 ), " is the lowest positive number with no solutions", newline ) )
FI;
have solutions
DO SKIP OD;
IF have solutions
THEN print( ( "All positive numbers up to ", whole( max number, 0 ), " have solutions", newline ) )
IF this count > max count THEN
# the final value has the maximum count #
max count := this count;
max count value := value[ UPB value ]
FI;
print( ( whole( max count value, 0 ), " has the maximum number of solutions: " ) );
print( ( whole( max count, 0 ), newline ) );
# find the smallest positive number that has no solutions #
BOOL have solution := TRUE;
INT missing value := 1;
FOR v pos FROM LWB value TO UPB value WHILE have solution DO
IF value[ v pos ] > 0 THEN
IF value[ v pos ] /= value[ v pos - 1 ] THEN
have solution := value[ v pos ] = missing value;
IF have solution THEN
missing value +:= 1
FI
FI
FI
OD;
print( ( whole( missing value, 0 ), " is the lowest positive number with no solutions", newline ) );
# show the ten largest numbers that can be generated #
print( ( "The 10 largest numbers that can be generated are:", newline ) );
FOR t pos FROM 1 TO 10 DO
print( ( " ", whole( largest[ t pos ], 0 ) ) )
INT shown := 0;
FOR v pos FROM UPB value - 1 BY -1 TO LWB value WHILE shown < 10 DO
IF value[ v pos ] /= value[ v pos + 1 ] THEN
print( ( " ", whole( value[ v pos + 1 ], 0 ) ) );
shown +:= 1
FI
OD;
print( ( newline ) )

View file

@ -1,12 +0,0 @@
package Sum_To is
generic
with procedure Callback(Str: String; Int: Integer);
procedure Eval;
generic
Number: Integer;
with function Print_If(Sum, Number: Integer) return Boolean;
procedure Print(S: String; Sum: Integer);
end Sum_To;

View file

@ -1,40 +0,0 @@
with Ada.Text_IO, Ada.Containers.Ordered_Maps;
package body Sum_To is
procedure Eval is
procedure Rec_Eval(Str: String; Previous, Current, Next: Integer) is
Next_Image: String := Integer'Image(Next);
-- Next_Image(1) holds a blank, Next_Image(2) a digit
function Sign(N: Integer) return Integer is
(if N<0 then -1 elsif N>0 then 1 else 0);
begin
if Next = 10 then -- end of recursion
Callback(Str, Previous+Current);
else -- Next < 10
Rec_Eval(Str & Next_Image(2), -- concatenate current and Next
Previous, Sign(Current)*(10*abs(Current)+Next), Next+1);
Rec_Eval(Str & "+" & Next_Image(2), -- add Next
Previous+Current, Next, Next+1);
Rec_Eval(Str & "-" & Next_Image(2), -- subtract Next
Previous+Current, -Next, Next+1);
end if;
end Rec_Eval;
begin -- Eval
Rec_Eval("1", 0, 1, 2); -- unary "+", followed by "1"
Rec_Eval("-1", 0, -1, 2); -- unary "-", followed by "1"
end Eval;
procedure Print(S: String; Sum: Integer) is
-- print solution (S,N), if N=Number
begin
if Print_If(Sum, Number) then
Ada.Text_IO.Put_Line(Integer'Image(Sum) & " = " & S & ";");
end if;
end Print;
end Sum_To;

View file

@ -1,10 +0,0 @@
with Sum_To;
procedure Sum_To_100 is
procedure Print_100 is new Sum_To.Print(100, "=");
procedure Eval_100 is new Sum_To.Eval(Print_100);
begin
Eval_100;
end Sum_To_100;

View file

@ -1,67 +0,0 @@
with Sum_To, Ada.Containers.Ordered_Maps, Ada.Text_IO;
use Ada.Text_IO;
procedure Three_Others is
package Num_Maps is new Ada.Containers.Ordered_Maps
(Key_Type => Integer, Element_Type => Positive);
use Num_Maps;
Map: Num_Maps.Map;
-- global Map stores how often a sum did occur
procedure Insert_Solution(S: String; Sum: Integer) is
-- inserts a solution into global Map
use Num_Maps;
-- use type Num_Maps.Cursor;
Position: Cursor := Map.Find(Sum);
begin
if Position = No_Element then -- first solutions for Sum
Map.Insert(Key => Sum, New_Item => 1); -- counter is 1
else -- increase counter for Sum
Map.Replace_Element(Position => Position,
New_Item => (Element(Position))+1);
end if;
end Insert_Solution;
procedure Generate_Map is new Sum_To.Eval(Insert_Solution);
Current: Cursor; -- Points into Map
Sum: Integer; -- current Sum of interest
Max: Natural;
begin
Generate_Map;
-- find Sum >= 0 with maximum number of solutions
Max := 0; -- number of solutions for Sum (so far, none)
Current := Map.Ceiling(0); -- first element in Map with Sum >= 0
while Has_Element(Current) loop
if Element(Current) > Max then
Max := Element(Current); -- the maximum of solutions, so far
Sum := Key(Current); -- the Sum with Max solutions
end if;
Next(Current);
end loop;
Put_Line("Most frequent result:" & Integer'Image(Sum));
Put_Line("Frequency of" & Integer'Image(Sum) & ":" &
Integer'Image(Max));
New_Line;
-- find smallest Sum >= 0 with no solution
Sum := 0;
while Map.Find(Sum) /= No_Element loop
Sum := Sum + 1;
end loop;
Put_Line("Smallest nonnegative impossible sum:" & Integer'Image(Sum));
New_Line;
-- find ten highest numbers with a solution
Current := Map.Last; -- highest element in Map with a solution
Put_Line("Highest sum:" & Integer'Image(Key(Current)));
Put("Next nine:");
for I in 1 .. 9 loop -- 9 steps backward
Previous(Current);
Put(Integer'Image(Key(Current)));
end loop;
New_Line;
end Three_others;

View file

@ -29,7 +29,6 @@ void main() {
writeln(value);
comment("Show the ten highest numbers that can be expressed");
const int n = stat.countSum.keys.length;
auto sums = stat.countSum.keys;
sums.sort!"a>b"
.take(10)

View file

@ -1,10 +1,6 @@
ADD = 0
SUB = 1
nexpr = 13122 - 1
len f[] nexpr + 1
arrbase f[] 0
#
func evaluate code .
fastfunc evaluate code .
power = 1
for k = 9 downto 1
numb += power * k
@ -24,21 +20,21 @@ func evaluate code .
.
return value
.
proc init .
nexpr = 13122 - 1
len f[] nexpr + 1
arrbase f[] 0
fastproc .
for i = 0 to nexpr
f[i] = evaluate i
.
.
init
proc out code .
a = 19683
b = 6561
for k = 1 to 9
h = code mod a div b
if h = ADD
if k > 1
s$ &= "+"
.
if k > 1 : s$ &= "+"
elif h = SUB
s$ &= "-"
.
@ -48,55 +44,55 @@ proc out code .
.
print evaluate code & " = " & s$
.
#
print "Show all solutions that sum to 100\n"
for i = 0 to nexpr
if f[i] = 100
out i
.
proc .
for i = 0 to nexpr : if f[i] = 100 : out i
.
#
print "\nShow the sum that has the maximum number of solutions\n"
for i = 0 to nexpr
test = f[i]
if test > 0
ntest = 0
for j = 0 to nexpr
if f[j] = test
ntest += 1
global best nbest .
fastproc .
for i = 0 to nexpr
test = f[i]
if test > 0
ntest = 0
for j = 0 to nexpr
if f[j] = test : ntest += 1
.
if ntest > nbest
best = test
nbest = ntest
.
.
if ntest > nbest
best = test
nbest = ntest
.
.
.
print best & " has " & nbest & " solutions"
#
print "\nShow the lowest positive number that can't be expressed\n"
for i = 0 to 123456789
for j = 0 to nexpr
if i = f[j]
break 1
proc .
for i = 0 to 123456789
for j = 0 to nexpr
if i = f[j] : break 1
.
if j > nexpr : break 1
.
if j > nexpr
break 1
.
print i
.
print i
print "\nShow the ten highest numbers that can be expressed\n"
limit = 123456789 + 1
for i = 1 to 10
best = 0
for j = 0 to nexpr
test = f[j]
if test < limit and test > best
best = test
proc .
limit = 123456789 + 1
for i = 1 to 10
best = 0
for j = 0 to nexpr
test = f[j]
if test < limit and test > best
best = test
.
.
.
for j = 0 to nexpr
if f[j] = best
out j
for j = 0 to nexpr
if f[j] = best : out j
.
limit = best
.
limit = best
.

View file

@ -1,21 +1,22 @@
defmodule Sum do
def to(val) do
generate
generate()
|> Enum.map(&{eval(&1), &1})
|> Enum.filter(fn {v, _s} -> v==val end)
|> Enum.each(&IO.inspect &1)
end
def max_solve do
generate
generate()
|> Enum.group_by(&eval &1)
|> Enum.filter_map(fn {k,_} -> k>=0 end, fn {k,v} -> {length(v),k} end)
|> Enum.filter(fn {k,_} -> k>=0 end)
|> Enum.map(fn {k,v} -> {length(v),k} end)
|> Enum.max
|> fn {len,sum} -> IO.puts "sum of #{sum} has the maximum number of solutions : #{len}" end.()
end
def min_solve do
solve = generate |> Enum.group_by(&eval &1)
solve = generate() |> Enum.group_by(&eval &1)
Stream.iterate(1, &(&1+1))
|> Enum.find(fn n -> solve[n]==nil end)
|> fn sum -> IO.puts "lowest positive sum that can't be expressed : #{sum}" end.()
@ -23,7 +24,7 @@ defmodule Sum do
def highest_sums(n\\10) do
IO.puts "highest sums :"
generate
generate()
|> Enum.map(&eval &1)
|> Enum.uniq
|> Enum.sort_by(fn sum -> -sum end)

View file

@ -1,4 +1,6 @@
//
// Using FutureBasic 7.0.34, July 2025 R.W.
//
// Sum to 100 solutions
//
// Using 123456789 digits so the resulting

View file

@ -1,86 +1,81 @@
(phixonline)-->
<span style="color: #008080;">with</span> <span style="color: #000000;">javascript_semantics</span>
<span style="color: #008080;">enum</span> <span style="color: #000000;">SUB</span><span style="color: #0000FF;">=-</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">NOP</span><span style="color: #0000FF;">=</span><span style="color: #000000;">0</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">ADD</span><span style="color: #0000FF;">=</span><span style="color: #000000;">1</span>
with javascript_semantics
enum SUB=-1, NOP=0, ADD=1
<span style="color: #008080;">function</span> <span style="color: #000000;">evaluate</span><span style="color: #0000FF;">(</span><span style="color: #004080;">sequence</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">)</span>
<span style="color: #004080;">integer</span> <span style="color: #000000;">res</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">0</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">tmp</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">0</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">op</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">ADD</span>
<span style="color: #008080;">for</span> <span style="color: #000000;">i</span><span style="color: #0000FF;">=</span><span style="color: #000000;">1</span> <span style="color: #008080;">to</span> <span style="color: #7060A8;">length</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">do</span>
<span style="color: #008080;">if</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">i</span><span style="color: #0000FF;">]=</span><span style="color: #000000;">NOP</span> <span style="color: #008080;">then</span>
<span style="color: #000000;">tmp</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">tmp</span><span style="color: #0000FF;">*</span><span style="color: #000000;">10</span><span style="color: #0000FF;">+</span><span style="color: #000000;">i</span>
<span style="color: #008080;">else</span>
<span style="color: #000000;">res</span> <span style="color: #0000FF;">+=</span> <span style="color: #000000;">op</span><span style="color: #0000FF;">*</span><span style="color: #000000;">tmp</span>
<span style="color: #000000;">tmp</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">i</span>
<span style="color: #000000;">op</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">i</span><span style="color: #0000FF;">]</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">for</span>
<span style="color: #008080;">return</span> <span style="color: #000000;">res</span> <span style="color: #0000FF;">+</span> <span style="color: #000000;">op</span><span style="color: #0000FF;">*</span><span style="color: #000000;">tmp</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
function evaluate(sequence s)
integer res = 0, tmp = 0, op = ADD
for i=1 to length(s) do
if s[i]=NOP then
tmp = tmp*10+i
else
res += op*tmp
tmp = i
op = s[i]
end if
end for
return res + op*tmp
end function
<span style="color: #008080;">procedure</span> <span style="color: #000000;">show</span><span style="color: #0000FF;">(</span><span style="color: #004080;">sequence</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">)</span>
<span style="color: #004080;">string</span> <span style="color: #000000;">res</span> <span style="color: #0000FF;">=</span> <span style="color: #008000;">""</span>
<span style="color: #008080;">for</span> <span style="color: #000000;">i</span><span style="color: #0000FF;">=</span><span style="color: #000000;">1</span> <span style="color: #008080;">to</span> <span style="color: #7060A8;">length</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">do</span>
<span style="color: #008080;">if</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">i</span><span style="color: #0000FF;">]!=</span><span style="color: #000000;">NOP</span> <span style="color: #008080;">then</span>
<span style="color: #000000;">res</span> <span style="color: #0000FF;">&=</span> <span style="color: #008000;">','</span><span style="color: #0000FF;">-</span><span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">i</span><span style="color: #0000FF;">]</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #000000;">res</span> <span style="color: #0000FF;">&=</span> <span style="color: #008000;">'0'</span><span style="color: #0000FF;">+</span><span style="color: #000000;">i</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">for</span>
<span style="color: #7060A8;">printf</span><span style="color: #0000FF;">(</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #008000;">"%s = %d\n"</span><span style="color: #0000FF;">,{</span><span style="color: #000000;">res</span><span style="color: #0000FF;">,</span><span style="color: #000000;">evaluate</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">)})</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">procedure</span>
procedure show(sequence s)
string res = ""
for i=1 to length(s) do
if s[i]!=NOP then
res &= ','-s[i]
end if
res &= '0'+i
end for
printf(1,"%s = %d\n",{res,evaluate(s)})
end procedure
<span style="color: #000080;font-style:italic;">-- Logically this intersperses -/nop/+ between each digit, but you do not actually need the digit.</span>
<span style="color: #004080;">sequence</span> <span style="color: #000000;">s</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">repeat</span><span style="color: #0000FF;">(</span><span style="color: #000000;">SUB</span><span style="color: #0000FF;">,</span><span style="color: #000000;">9</span><span style="color: #0000FF;">)</span> <span style="color: #000080;font-style:italic;">-- (==&gt; ..nop+add*8)</span>
-- Logically this intersperses -/nop/+ between each digit, but you do not actually need the digit.
sequence s = repeat(SUB,9) -- (==> ..nop+add*8)
<span style="color: #004080;">bool</span> <span style="color: #000000;">done</span> <span style="color: #0000FF;">=</span> <span style="color: #004600;">false</span>
<span style="color: #004080;">integer</span> <span style="color: #000000;">maxl</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">0</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">maxr</span>
<span style="color: #004080;">integer</span> <span style="color: #000000;">count</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">0</span>
<span style="color: #008080;">while</span> <span style="color: #008080;">not</span> <span style="color: #000000;">done</span> <span style="color: #008080;">do</span>
<span style="color: #000000;">count</span> <span style="color: #0000FF;">+=</span> <span style="color: #000000;">1</span>
<span style="color: #004080;">integer</span> <span style="color: #000000;">r</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">evaluate</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">),</span> <span style="color: #000000;">k</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">getd_index</span><span style="color: #0000FF;">(</span><span style="color: #000000;">r</span><span style="color: #0000FF;">)</span>
<span style="color: #004080;">sequence</span> <span style="color: #000000;">solns</span> <span style="color: #0000FF;">=</span> <span style="color: #008080;">iff</span><span style="color: #0000FF;">(</span><span style="color: #000000;">k</span><span style="color: #0000FF;">=</span><span style="color: #000000;">0</span><span style="color: #0000FF;">?{}:</span><span style="color: #7060A8;">deep_copy</span><span style="color: #0000FF;">(</span><span style="color: #7060A8;">getd_by_index</span><span style="color: #0000FF;">(</span><span style="color: #000000;">k</span><span style="color: #0000FF;">)))</span>
<span style="color: #000000;">solns</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">append</span><span style="color: #0000FF;">(</span><span style="color: #000000;">solns</span><span style="color: #0000FF;">,</span><span style="color: #7060A8;">deep_copy</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">))</span>
<span style="color: #7060A8;">setd</span><span style="color: #0000FF;">(</span><span style="color: #000000;">r</span><span style="color: #0000FF;">,</span><span style="color: #000000;">solns</span><span style="color: #0000FF;">)</span>
<span style="color: #008080;">if</span> <span style="color: #000000;">r</span><span style="color: #0000FF;">></span><span style="color: #000000;">0</span> <span style="color: #008080;">and</span> <span style="color: #000000;">maxl</span><span style="color: #0000FF;"><</span><span style="color: #7060A8;">length</span><span style="color: #0000FF;">(</span><span style="color: #000000;">solns</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">then</span>
<span style="color: #000000;">maxl</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">length</span><span style="color: #0000FF;">(</span><span style="color: #000000;">solns</span><span style="color: #0000FF;">)</span>
<span style="color: #000000;">maxr</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">r</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #008080;">for</span> <span style="color: #000000;">i</span><span style="color: #0000FF;">=</span><span style="color: #7060A8;">length</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">to</span> <span style="color: #000000;">1</span> <span style="color: #008080;">by</span> <span style="color: #0000FF;">-</span><span style="color: #000000;">1</span> <span style="color: #008080;">do</span>
<span style="color: #008080;">if</span> <span style="color: #000000;">i</span><span style="color: #0000FF;">=</span><span style="color: #000000;">1</span> <span style="color: #008080;">and</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">i</span><span style="color: #0000FF;">]=</span><span style="color: #000000;">NOP</span> <span style="color: #008080;">then</span>
<span style="color: #000000;">done</span> <span style="color: #0000FF;">=</span> <span style="color: #004600;">true</span>
<span style="color: #008080;">exit</span>
<span style="color: #008080;">elsif</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">i</span><span style="color: #0000FF;">]!=</span><span style="color: #000000;">ADD</span> <span style="color: #008080;">then</span>
<span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">i</span><span style="color: #0000FF;">]</span> <span style="color: #0000FF;">+=</span> <span style="color: #000000;">1</span>
<span style="color: #008080;">exit</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">i</span><span style="color: #0000FF;">]</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">SUB</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">for</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">while</span>
bool done = false
integer maxl = 0, maxr, count = 0
while not done do
count += 1
integer r = evaluate(s), k = getd_index(r)
sequence solns = iff(k=0?{}:deep_copy(getd_by_index(k)))
solns = append(solns,deep_copy(s))
setd(r,solns)
if r>0 and maxl<length(solns) then
maxl = length(solns)
maxr = r
end if
for i=length(s) to 1 by -1 do
if i=1 and s[i]=NOP then
done = true
exit
elsif s[i]!=ADD then
s[i] += 1
exit
end if
s[i] = SUB
end for
end while
<span style="color: #7060A8;">printf</span><span style="color: #0000FF;">(</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #008000;">"%d solutions considered (dictionary size: %d)\n"</span><span style="color: #0000FF;">,{</span><span style="color: #000000;">count</span><span style="color: #0000FF;">,</span><span style="color: #7060A8;">dict_size</span><span style="color: #0000FF;">()})</span>
printf(1,"%d solutions considered (dictionary size: %d)\n",{count,dict_size()})
<span style="color: #004080;">sequence</span> <span style="color: #000000;">s100</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">getd</span><span style="color: #0000FF;">(</span><span style="color: #000000;">100</span><span style="color: #0000FF;">)</span>
<span style="color: #7060A8;">printf</span><span style="color: #0000FF;">(</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #008000;">"There are %d sums to 100:\n"</span><span style="color: #0000FF;">,{</span><span style="color: #7060A8;">length</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s100</span><span style="color: #0000FF;">)})</span>
<span style="color: #7060A8;">papply</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s100</span><span style="color: #0000FF;">,</span><span style="color: #000000;">show</span><span style="color: #0000FF;">)</span>
sequence s100 = getd(100)
printf(1,"There are %d sums to 100:\n",{length(s100)})
papply(s100,show)
<span style="color: #7060A8;">printf</span><span style="color: #0000FF;">(</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #008000;">"The positive sum of %d has the maximum number of solutions: %d\n"</span><span style="color: #0000FF;">,{</span><span style="color: #000000;">maxr</span><span style="color: #0000FF;">,</span><span style="color: #000000;">maxl</span><span style="color: #0000FF;">})</span>
printf(1,"The positive sum of %d has the maximum number of solutions: %d\n",{maxr,maxl})
<span style="color: #004080;">integer</span> <span style="color: #000000;">prev</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">0</span>
<span style="color: #008080;">function</span> <span style="color: #000000;">missing</span><span style="color: #0000FF;">(</span><span style="color: #004080;">integer</span> <span style="color: #000000;">key</span><span style="color: #0000FF;">,</span> <span style="color: #004080;">sequence</span> <span style="color: #000080;font-style:italic;">/*data*/</span><span style="color: #0000FF;">,</span> <span style="color: #004080;">integer</span> <span style="color: #000080;font-style:italic;">/*pkey*/</span><span style="color: #0000FF;">,</span> <span style="color: #004080;">object</span> <span style="color: #000080;font-style:italic;">/*user_data=-2*/</span><span style="color: #0000FF;">)</span>
<span style="color: #008080;">if</span> <span style="color: #000000;">key</span><span style="color: #0000FF;">!=</span><span style="color: #000000;">prev</span><span style="color: #0000FF;">+</span><span style="color: #000000;">1</span> <span style="color: #008080;">then</span>
<span style="color: #008080;">return</span> <span style="color: #000000;">0</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #000000;">prev</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">key</span>
<span style="color: #008080;">return</span> <span style="color: #000000;">1</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #7060A8;">traverse_dict_partial_key</span><span style="color: #0000FF;">(</span><span style="color: #000000;">missing</span><span style="color: #0000FF;">,</span><span style="color: #000000;">1</span><span style="color: #0000FF;">)</span>
<span style="color: #7060A8;">printf</span><span style="color: #0000FF;">(</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #008000;">"The lowest positive sum that cannot be expressed: %d\n"</span><span style="color: #0000FF;">,{</span><span style="color: #000000;">prev</span><span style="color: #0000FF;">+</span><span style="color: #000000;">1</span><span style="color: #0000FF;">})</span>
integer prev = 0
function missing(integer key, sequence /*data*/, integer /*pkey*/, object /*user_data=-2*/)
if key!=prev+1 then
return 0
end if
prev = key
return 1
end function
traverse_dict_partial_key(missing,1)
printf(1,"The lowest positive sum that cannot be expressed: %d\n",{prev+1})
<span style="color: #004080;">sequence</span> <span style="color: #000000;">highest</span> <span style="color: #0000FF;">=</span> <span style="color: #0000FF;">{}</span>
<span style="color: #008080;">function</span> <span style="color: #000000;">top10</span><span style="color: #0000FF;">(</span><span style="color: #004080;">integer</span> <span style="color: #000000;">key</span><span style="color: #0000FF;">,</span> <span style="color: #004080;">sequence</span> <span style="color: #000080;font-style:italic;">/*data*/</span><span style="color: #0000FF;">,</span> <span style="color: #004080;">object</span> <span style="color: #000080;font-style:italic;">/*user_data*/</span><span style="color: #0000FF;">)</span>
<span style="color: #000000;">highest</span> <span style="color: #0000FF;">&=</span> <span style="color: #000000;">key</span>
<span style="color: #008080;">return</span> <span style="color: #7060A8;">length</span><span style="color: #0000FF;">(</span><span style="color: #000000;">highest</span><span style="color: #0000FF;">)<</span><span style="color: #000000;">10</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #000080;font-style:italic;">--DEV named params on builtins need pre-loading...:
--traverse_dict(top10,rev:=1)</span>
<span style="color: #7060A8;">traverse_dict</span><span style="color: #0000FF;">(</span><span style="color: #000000;">top10</span><span style="color: #0000FF;">,</span><span style="color: #000000;">0</span><span style="color: #0000FF;">,</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #004600;">true</span><span style="color: #0000FF;">)</span>
<span style="color: #7060A8;">printf</span><span style="color: #0000FF;">(</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #008000;">"The 10 highest sums: %v\n"</span><span style="color: #0000FF;">,{</span><span style="color: #000000;">highest</span><span style="color: #0000FF;">})</span>
<!--
sequence highest = {}
function top10(integer key, sequence /*data*/, object /*user_data*/)
highest &= key
return length(highest)<10
end function
traverse_dict(top10,rev:=1)
printf(1,"The 10 highest sums: %v\n",{highest})