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24
Task/Substring/BASIC/substring-1.basic
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24
Task/Substring/BASIC/substring-1.basic
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DIM baseString AS STRING, subString AS STRING, findString AS STRING
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DIM m AS INTEGER, n AS INTEGER
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baseString = "abcdefghijklmnopqrstuvwxyz"
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n = 12
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m = 5
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' starting from n characters in and of m length;
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subString = MID$(baseString, n, m)
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PRINT subString
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' starting from n characters in, up to the end of the string;
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subString = MID$(baseString, n)
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PRINT subString
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' whole string minus last character;
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subString = LEFT$(baseString, LEN(baseString) - 1)
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PRINT subString
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' starting from a known character within the string and of m length;
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' starting from a known substring within the string and of m length.
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findString = "pq"
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subString = MID$(baseString, INSTR(baseString, findString), m)
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PRINT subString
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13
Task/Substring/BASIC/substring-2.basic
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13
Task/Substring/BASIC/substring-2.basic
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10 LET A$="abcdefghijklmnopqrstuvwxyz"
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15 LET n=10: LET m=7
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20 PRINT A$(n TO n+m-1)
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30 PRINT A$(n TO )
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40 PRINT A$( TO LEN (A$)-1)
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50 FOR i=1 TO LEN (A$)
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60 IF A$(i)="g" THEN PRINT A$(i TO i+m-1): LET i=LEN (A$): GO TO 70
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70 NEXT i
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80 LET B$="ijk"
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90 FOR i=1 TO LEN (A$)-LEN (B$)+1
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100 IF A$(i TO i+LEN (B$)-1)=B$ THEN PRINT A$(i TO i+m-1): LET i=LEN (A$)-LEN (B$)+1: GO TO 110
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110 NEXT i
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120 STOP
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