This commit is contained in:
Ingy döt Net 2013-04-10 16:57:12 -07:00
parent 518da4a923
commit 764da6cbbb
6144 changed files with 83610 additions and 11 deletions

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The general idea behind an executable library is to create a library that when used as a library does one thing; but has the ability to be run directly via command line. Thus the API comes with a CLI in the very same source code file.
'''Task detail'''
* Create a library/module/dll/shared object/... for a programming language that contains a function/method called hailstone that is a function taking a positive integer and returns the [[Hailstone sequence]] for that number.
* The library, when executed directly should satisfy the remaining requirements of the [[Hailstone sequence]] task:
:: 2. Use the routine to show that the hailstone sequence for the number 27 has 112 elements starting with 27, 82, 41, 124 and ending with 8, 4, 2, 1
:: 3. Show the number less than 100,000 which has the longest hailstone sequence together with that sequences length.
* Create a second executable to calculate the following:
** Use the libraries hailstone function, in the standard manner, (or document how this use deviates from standard use of a library), together with extra code in this executable, to find the hailstone length returned most often for 1 ≤ n < 100,000.
* Explain any extra setup/run steps needed to complete the task.
'''Notes:'''
* It is assumed that for a language that overwhelmingly ships in a compiled form, such as C, the library must also be an executable and the compiled user of that library is to do so without changing the compiled library. I.e. the compile tool-chain is assumed ''not'' to be present in the runtime environment.
* Interpreters are present in the runtime environment.

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package Parameter is
X: Natural := 0;
Y: Natural;
end Parameter;

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with Ada.Text_IO, Parameter, Hailstones;
procedure Hailstone is
-- if Parameter.X > 0, the length of Hailstone(Parameter.X)
-- is computed and written into Parameter.Y
-- if Parameter.X = 0, Hailstone(27) and N <= 100_000 with maximal
-- Hailstone(N) are computed and printed.
procedure Show_Sequence(N: Natural) is
Seq: Hailstones.Integer_Sequence := Hailstones.Create_Sequence(N);
begin
Ada.Text_IO.Put("Hailstone(" & Integer'Image(N) & " ) = (");
if Seq'Length < 8 then
for I in Seq'First .. Seq'Last-1 loop
Ada.Text_IO.Put(Integer'Image(Seq(I)) & ",");
end loop;
else
for I in Seq'First .. Seq'First+3 loop
Ada.Text_IO.Put(Integer'Image(Seq(I)) & ",");
end loop;
Ada.Text_IO.Put(" ...,");
for I in Seq'Last-3 .. Seq'Last-1 loop
Ada.Text_IO.Put(Integer'Image(Seq(I)) &",");
end loop;
end if;
Ada.Text_IO.Put_Line(Integer'Image(Seq(Seq'Last)) & " ); Length: " &
Integer'Image(seq'Length));
end Show_Sequence;
begin
if Parameter.X>0 then
Parameter.Y := Hailstones.Create_Sequence(Parameter.X)'Length;
else
Show_Sequence(27);
declare
Longest: Natural := 0;
Longest_Length: Natural := 0;
begin
for I in 2 .. 100_000 loop
if Hailstones.Create_Sequence(I)'Length > Longest_Length then
Longest := I;
Longest_Length := Hailstones.Create_Sequence(I)'Length;
end if;
end loop;
Ada.Text_IO.Put("Longest<=100_000: ");
Show_Sequence(Longest);
end;
end if;
end Hailstone;

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procedure Hailstone;

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with Hailstone, Parameter, Ada.Text_IO;
procedure Hailstone_Test is
Counts: array (1 .. 100_000) of Natural := (others => 0);
Max_Count: Natural := 0;
Most_Common: Positive := Counts'First;
Length: Natural renames Parameter.Y;
Sample: Natural := 0;
begin
for I in Counts'Range loop
Parameter.X := I;
Hailstone; -- compute the length of Hailstone(I)
Counts(Length) := Counts(Length)+1;
end loop;
for I in Counts'Range loop
if Counts(I) > Max_Count then
Max_Count := Counts(I);
Most_Common := I;
end if;
end loop;
Ada.Text_IO.Put_Line("Most frequent length:"
& Integer'Image(Most_Common)
& ";" & Integer'Image(Max_Count)
& " sequences of that length.");
for I in Counts'Range loop
Parameter.X := I;
Hailstone; -- compute the length of Hailstone(I)
if Length = Most_Common then
Sample := I;
exit;
end if;
end loop;
Ada.Text_IO.Put_Line("The first such sequence: Hailstone("
& Integer'Image(Sample) & " ).");
end Hailstone_Test;

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#NoEnv
SetBatchLines, -1
; Check if we're executed directly:
If (A_LineFile = A_ScriptFullPath){
h27 := hailstone(27)
MsgBox % "Length of hailstone 27: " (m := h27.MaxIndex()) "`nStarts with "
. h27[1] ", " h27[2] ", " h27[3] ", " h27[4]
. "`nEnds with "
. h27[m-3] ", " h27[m-2] ", " h27[m-1] ", " h27[m]
Loop 100000
{
h := hailstone(A_Index)
If (h.MaxIndex() > m)
m := h.MaxIndex(), longest := A_Index
}
MsgBox % "Longest hailstone is that of " longest " with a length of " m "!"
}
hailstone(n){
out := [n]
Loop
n := n & 1 ? n*3+1 : n//2, out.insert(n)
until n=1
return out
}

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#NoEnv
#Include %A_ScriptDir%\hailstone.ahk
SetBatchLines -1
col := Object(), highestCount := 0
Loop 100000
{
length := hailstone(A_Index).MaxIndex()
if not col[length]
col[length] := 0
col[length]++
}
for length, count in col
if (count > highestCount)
highestCount := count, highestN := length
MsgBox % "the most common length was " highestN "; it occurred " highestCount " times."

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seqlen% = FNhailstone(27)
PRINT "Sequence length for 27 is "; seqlen%
maxlen% = 0
FOR number% = 2 TO 100000
seqlen% = FNhailstone(number%)
IF seqlen% > maxlen% THEN
maxlen% = seqlen%
maxnum% = number%
ENDIF
NEXT
PRINT "The number with the longest hailstone sequence is " ; maxnum%
PRINT "Its sequence length is " ; maxlen%
END
DEF FNhailstone(N%)
LOCAL L%
WHILE N% <> 1
IF N% AND 1 THEN N% = 3 * N% + 1 ELSE N% DIV= 2
L% += 1
ENDWHILE
= L% + 1

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INSTALL "HAILSTONE"
DIM freq%(351)
FOR number% = 2 TO 100000
seqlen% = FNhailstone(number%)
freq%(seqlen%) += 1
NEXT
max% = 0
FOR i% = 0 TO 351
IF freq%(i%) > max% THEN
max% = freq%(i%)
mostcommon% = i%
ENDIF
NEXT
PRINT "The most common sequence length is " ; mostcommon%
PRINT "It occurs " ; max% " times"
END

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#ifndef HAILSTONE
#define HAILSTONE
long hailstone(long, long**);
void free_sequence(long *);
#endif/*HAILSTONE*/

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#include <stdio.h>
#include <stdlib.h>
long hailstone(long n, long **seq)
{
long len = 0, buf_len = 4;
if (seq)
*seq = malloc(sizeof(long) * buf_len);
while (1) {
if (seq) {
if (len >= buf_len) {
buf_len *= 2;
*seq = realloc(*seq, sizeof(long) * buf_len);
}
(*seq)[len] = n;
}
len ++;
if (n == 1) break;
if (n & 1) n = 3 * n + 1;
else n >>= 1;
}
return len;
}
void free_sequence(long * s) { free(s); }
const char my_interp[] __attribute__((section(".interp"))) = "/lib/ld-linux.so.2";
/* "ld-linux.so.2" should be whatever you use on your platform */
int hail_main() /* entry point when running along, see compiler command line */
{
long i, *seq;
long len = hailstone(27, &seq);
printf("27 has %ld numbers in sequence:\n", len);
for (i = 0; i < len; i++) {
printf("%ld ", seq[i]);
}
printf("\n");
free_sequence(seq);
exit(0);
}

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#include <stdio.h>
#include "hailstone.h"
int main()
{
long i, longest, longest_i, len;
longest = 0;
for (i = 1; i < 100000; i++) {
len = hailstone(i, 0);
if (len > longest) {
longest_i = i;
longest = len;
}
}
printf("Longest sequence at %ld, length %ld\n", longest_i, longest);
return 0;
}

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package Hailstone;
sub seq {
my $x = shift;
$x == 1 ? (1) : ($x & 1)? ($x, seq($x * 3 + 1))
: ($x, seq($x / 2))
}
my %cache = (1 => 1);
sub len {
my $x = shift;
$cache{$x} //= 1 + (
$x & 1 ? len($x * 3 + 1)
: len($x / 2))
}
unless (caller) {
for (1 .. 100_000) {
my $l = len($_);
($m, $len) = ($_, $l) if $l > $len;
}
print "seq of 27 - $cache{27} elements: @{[seq(27)]}\n";
print "Longest sequence is for $m: $len\n";
}
1;

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use Hailstone;
use strict;
use warnings;
my %seqs;
for (1 .. 100_000) {
$seqs{Hailstone::len($_)}++;
}
my ($most_frequent) = sort {$seqs{$b} <=> $seqs{$a}} keys %seqs;
print "Most frequent length: $most_frequent ($seqs{$most_frequent} occurrences)\n";

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#!/usr/bin/picolisp /usr/lib/picolisp/lib.l
(de hailstone (N)
(make
(until (= 1 (link N))
(setq N
(if (bit? 1 N)
(inc (* N 3))
(/ N 2) ) ) ) ) )
(de hailtest ()
(let L (hailstone 27)
(test 112 (length L))
(test (27 82 41 124) (head 4 L))
(test (8 4 2 1) (tail 4 L)) )
(let N (maxi '((N) (length (hailstone N))) (range 1 100000))
(test 77031 N)
(test 351 (length (hailstone N))) )
(println 'OK)
(bye) )

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#!/usr/bin/picolisp /usr/lib/picolisp/lib.l
(load "hailstone.l")
(let Len NIL
(for N 100000
(accu 'Len (length (hailstone N)) 1) )
(let M (maxi cdr Len)
(prinl "The hailstone length returned most often is " (car M))
(prinl "It is returned " (cdr M) " times") ) )
(bye)

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def hailstone(n):
seq = [n]
while n>1:
n = 3*n + 1 if n & 1 else n//2
seq.append(n)
return seq
if __name__ == '__main__':
h = hailstone(27)
assert len(h)==112 and h[:4]==[27, 82, 41, 124] and h[-4:]==[8, 4, 2, 1]
print("Maximum length %i was found for hailstone(%i) for numbers <100,000" %
max((len(hailstone(i)), i) for i in range(1,100000)))

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from collections import Counter
def function_length_frequency(func, hrange):
return Counter(len(func(n)) for n in hrange).most_common()
if __name__ == '__main__':
from executable_hailstone_library import hailstone
upto = 100000
hlen, freq = function_length_frequency(hailstone, range(1, upto))[0]
print("The length of hailstone sequence that is most common for\n"
"hailstone(n) where 1<=n<%i, is %i. It occurs %i times."
% (upto, hlen, freq))

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/*REXX program returns the hailstone (Collatz) sequence for any integer.*/
numeric digits 20 /*ensure enough digits for mult. */
parse arg n 1 s /*N & S assigned to the first arg*/
do while n\==1 /*loop while N isn't unity. */
if n//2 then n=n*3+1 /*if N is odd, calc: 3*n +1 */
else n=n%2 /* " " " even, perform fast ÷ */
s=s n /*build a sequence list (append).*/
end /*while*/
return s

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/*REXX pgm tests a number and a range for hailstone (Collatz) sequences.*/
parse arg x .; if x=='' then x=27 /*get the optional first argument*/
$=hailstone(x) /*═════════════task 2════════════*/
#=words($) /*number of numbers in sequence. */
say x 'has a hailstone sequence of' # 'and starts with: ' subword($,1,4),
' and ends with:' subword($,#-3)
say
w=0; do j=1 for 99999 /*═════════════task 3════════════*/
$=hailstone(j); #=words($) /*obtain the hailstone sequence. */
if #<=w then iterate /*Not big 'nuff? Then keep going.*/
bigJ=j; w=# /*remember what # has biggest HS.*/
end /*j*/
say '(between 199,999) ' bigJ 'has the longest hailstone sequence:' w
/*stick a fork in it, we're done.*/

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/*REXX pgm finds the most common (popular) hailstone sequence length. */
parse arg z .; if z=='' then z=99999 /*get the optional first argument*/
!.=0
w=0; do j=1 for z /*═════════════task 4════════════*/
#=words(hailstone(j)) /*obtain hailstone sequence count*/
!.# = !.# + 1 /*add unity to popularity count. */
end /*j*/
occ=0; p=0
do k=1 for z
if !.k>occ then do; occ=!.k; p=k; end
end /*p*/
say '(between 1'z") " p,
' is the most common hailstone sequence length (with' occ "occurrences)."
/*stick a fork in it, we're done.*/

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# hailstone.rb
module Hailstone
module_function
def hailstone n
seq = [n]
until n == 1
n = (n.even?) ? (n / 2) : (3 * n + 1)
seq << n
end
seq
end
end
if __FILE__ == $0
include Hailstone
# for n = 27, show sequence length and first and last 4 elements
hs27 = hailstone 27
p [hs27.length, hs27[0..3], hs27[-4..-1]]
# find the longest sequence among n less than 100,000
n, len = (1 ... 100_000) .collect {|n|
[n, hailstone(n).length]} .max_by {|n, len| len}
puts "#{n} has a hailstone sequence length of #{len}"
puts "the largest number in that sequence is #{hailstone(n).max}"
end

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# hsfreq.rb
require 'hailstone'
h = Hash.new(0)
last = 99_999
(1..last).each {|n| h[Hailstone.hailstone(n).length] += 1}
length, count = h.max_by {|length, count| count}
puts "Given the hailstone sequences from 1 to #{last},"
puts "the most common sequence length is #{length},"
puts "with #{count} such sequences."

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### In the file hailstone.tcl ###
package provide hailstone 1.0
proc hailstone n {
while 1 {
lappend seq $n
if {$n == 1} {return $seq}
set n [expr {$n & 1 ? $n*3+1 : $n/2}]
}
}
# If directly executed, run demo code
if {[info script] eq $::argv0} {
set h27 [hailstone 27]
puts "h27 len=[llength $h27]"
puts "head4 = [lrange $h27 0 3]"
puts "tail4 = [lrange $h27 end-3 end]"
set maxlen [set max 0]
for {set i 1} {$i<100000} {incr i} {
set l [llength [hailstone $i]]
if {$l>$maxlen} {set maxlen $l;set max $i}
}
puts "max is $max, with length $maxlen"
}

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pkg_mkIndex .

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#!/usr/bin/tclsh8.6
package require Tcl 8.6 ;# For [lsort -stride] option
lappend auto_path . ;# Or wherever it is located
package require hailstone 1.0
# Construct a histogram of length frequencies
set histogram {}
for {set n 1} {$n < 100000} {incr n} {
dict incr histogram [llength [hailstone $n]]
}
# Identify the most common length by sorting...
set sortedHist [lsort -decreasing -stride 2 -index 1 $histogram]
lassign $sortedHist mostCommonLength freq
puts "most common length is $mostCommonLength, with frequency $freq"