Another update from ingydotnet^djgoku

This commit is contained in:
Ingy döt Net 2015-11-18 06:14:39 +00:00
parent 91df62d461
commit 948b86eafa
7604 changed files with 108452 additions and 22726 deletions

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/*REXX program cuts rectangles into two symmetric pieces, the rectangles are */
/*────────────────────────────── cut along unit dimensions and may be rotated.*/
numeric digits 20 /*be able to handle some big integers. */
parse arg N .; if N=='' then N=10 /*N not specified? Then use default.*/
dir.=0; dir.0.1=-1; dir.1.0=-1; dir.2.1=1; dir.3.0=1 /*four directions*/
do y=2 to N; say /*calculate rectangles up to size NxN.*/
do x=1 for y; if x//2 & y//2 then iterate /*not if both X&Y odd.*/
_=solve(y,x,1); _=right(_,max(10,length(_))) /*align the output. */
say right(y,9) "x" right(x,2) 'rectangle can be cut' _ "way"s(_)'.'
end /*x*/
end /*y*/
exit /*stick a fork in it, we're all done. */
/*──────────────────────────────────S subroutine──────────────────────────────*/
s: if arg(1)=1 then return arg(3); return word(arg(2) 's',1) /*pluralizer.*/
/*──────────────────────────────────SOLVE subroutine──────────────────────────*/
solve: procedure expose # dir. @. h len next. w
parse arg hh 1 h,ww 1 w,recur; @.=0 /*get args; zero rectangle coördinates.*/
if h//2 then do; t=w; w=h; h=t; if h//2 then return 0
end
if w==1 then return 1
if w==2 then return h
if h==2 then return w /* % is REXX's integer division. */
cy = h%2; cx=w%2 /*cut the [XY] rectangle in half. */
len = (h+1) * (w+1) - 1 /*extend the area of the rectangle. */
next.0=-1; next.1=-w-1; next.2=1; next.3=w+1 /*direction and distance.*/
if recur then #=0
do x=cx+1 to w-1; t=x+cy*(w+1)
@.t=1; _=len-t; @._=1; call walk cy-1,x
end /*x*/
#=#+1
if h==w then #=#+# /*double the count of rectangle cuts. */
else if w//2==0 & recur then call solve w,h,0
return #
/*──────────────────────────────────WALK subroutine───────────────────────────*/
walk: procedure expose # dir. @. h len next. w; parse arg y,x
if y==h | x==0 | x==w | y==0 then do; #=#=2; return; end
t=x + y*(w+1); @.t=@.t+1; _=len-t
@._=@._+1
do j=0 for 4; _ = t+next.j /*try four directions.*/
if @._==0 then call walk y+dir.j.0, x+dir.j.1
end /*j*/
@.t=@.t-1
_=len-t; @._=@._-1
return

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/*REXX program cuts rectangles into two symmetric pieces, the rectangles are */
/*────────────────────────────── cut along unit dimensions and may be rotated.*/
numeric digits 20 /*be able to handle some big integers. */
parse arg N .; if N=='' then N=10 /*N not specified? Then use default.*/
dir.=0; dir.0.1=-1; dir.1.0=-1; dir.2.1=1; dir.3.0=1 /*four directions*/
do y=2 to N; say /*calculate rectangles up to size NxN.*/
do x=1 for y; if x//2 & y//2 then iterate /*not if both X&Y odd.*/
_=solve(y,x,1); _=right(_,max(10,length(_))) /*align the output. */
say right(y,9) "x" right(x,2) 'rectangle can be cut' _ "way"s(_)'.'
end /*x*/
end /*y*/
exit /*stick a fork in it, we're all done. */
/*──────────────────────────────────S subroutine──────────────────────────────*/
s: if arg(1)=1 then return arg(3); return word(arg(2) 's',1) /*pluralizer.*/
/*──────────────────────────────────SOLVE subroutine──────────────────────────*/
solve: procedure expose # dir. @. h len next. w
parse arg hh 1 h,ww 1 w,recur; @.=0 /*get args; zero rectangle coördinates.*/
if h//2 then do; parse value w h w with t w h; if h//2 then return 0
end
if w==1 then return 1
if w==2 then return h
if h==2 then return w /* % is REXX's integer division. */
cy = h%2; cx=w%2 /*cut the [XY] rectangle in half. */
len = (h+1) * (w+1) - 1 /*extend the area of the rectangle. */
next.0=-1; next.1=-w-1; next.2=1; next.3=w+1 /*direction and distance.*/
if recur then #=0
do x=cx+1 to w-1; t=x+cy*(w+1)
@.t=1; _=len-t; @._=1; call walk cy-1,x
end /*x*/
#=#+1
if h==w then #=#+# /*double the count of rectangle cuts. */
else if w//2==0 & recur then call solve w,h,0
return #
/*──────────────────────────────────WALK subroutine───────────────────────────*/
walk: procedure expose # dir. @. h len next. w; parse arg y,x
if y==h then do; #=#+2; return; end /* ◄──┐ REXX short circuit. */
if x==0 then do; #=#+2; return; end /* ◄──┤ " " " */
if x==w then do; #=#+2; return; end /* ◄──┤ " " " */
if y==0 then do; #=#+2; return; end /* ◄──┤ " " " */
t=x + y*(w+1); @.t=@.t+1; _=len-t /* │ ordered by most likely ►───┐ */
@._=@._+1 /* └─────────────────────────────┘ */
do j=0 for 4; _ = t+next.j /*try four directions.*/
if @._==0 then do
yn=y+dir.j.0; xn=x+dir.j.1
if yn==h then do; #=#+2; iterate; end
if xn==0 then do; #=#+2; iterate; end
if xn==w then do; #=#+2; iterate; end
if yn==0 then do; #=#+2; iterate; end
call walk yn, xn
end
end /*j*/
@.t=@.t-1
_=len-t; @._=@._-1
return

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/*REXX program cuts rectangles into two symmetric pieces, the rectangles*/
/*──────────────────── are cut along unit dimensions and may be rotated.*/
numeric digits 20 /*be able to handle big integers.*/
parse arg N .; if N=='' then N=10 /*N not specified? Use default.*/
dir.=0; dir.0.1=-1; dir.1.0=-1; dir.2.1=1; dir.3.0=1 /*directions.*/
do y=2 to N; say /*calculate rectangles up to NxN.*/
do x=1 for y; if x//2 & y//2 then iterate /*not if both odd.*/
_=solve(y,x,1); _=right(_,max(10,length(_))) /*align the output*/
say right(y,9) "x" right(x,2) 'rectangle can be cut' _ "way"s(_)'.'
end /*x*/
end /*y*/
exit /*stick a fork in it, we're done.*/
/*──────────────────────────────────S subroutine────────────────────────*/
s: if arg(1)=1 then return arg(3); return word(arg(2) 's',1) /*plurals*/
/*──────────────────────────────────SOLVE subroutine────────────────────*/
solve: procedure expose # dir. @. h len next. w
parse arg hh 1 h,ww 1 w,recur; @.=0 /*zero the rectangle coördinates.*/
if h//2 then do; t=w; w=h; h=t
if h//2 then return 0
end
if w==1 then return 1
if w==2 then return h
if h==2 then return w
cy = h%2; cx=w%2 /*cut the [XY] rectangle in half.*/
len = (h+1) * (w+1) - 1 /*extended area of the rectangle.*/
next.0=-1; next.1=-w-1; next.2=1; next.3=w+1 /*direction distance.*/
if recur then #=0
do x=cx+1 to w-1; t=x+cy*(w+1)
@.t=1; _=len-t; @._=1; call walk cy-1,x
end /*x*/
#=#+1
if h==w then #=#+# /*double count of rectangle cuts.*/
else if w//2==0 & recur then call solve w,h,0
return #
/*──────────────────────────────────WALK subroutine─────────────────────*/
walk: procedure expose # dir. @. h len next. w; parse arg y,x
if y==h then do; #=#+2; return; end /* ◄──┐ REXX short circuit.*/
if x==0 then do; #=#+2; return; end /* ◄──┤ " " " */
if x==w then do; #=#+2; return; end /* ◄──┤ " " " */
if y==0 then do; #=#+2; return; end /* ◄──┤ " " " */
t=x + y*(w+1); @.t=@.t+1; _=len-t /* │ ordered by most likely►─┐*/
@._=@._+1 /* └─────────────────────────┘*/
do j=0 for 4; _ = t+next.j /*try 4 directions*/
if @._==0 then call walk y+dir.j.0, x+dir.j.1
end /*j*/
@.t=@.t-1
_=len-t; @._=@._-1
return