September 2017 Update
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14570 changed files with 153136 additions and 63871 deletions
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sequence items = {
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{"map", 9, 150, 1},
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{"compass", 13, 35, 1},
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{"water", 153, 200, 2},
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{"sandwich", 50, 60, 2},
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{"glucose", 15, 60, 2},
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{"tin", 68, 45, 3},
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{"banana", 27, 60, 3},
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{"apple", 39, 40, 3},
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{"cheese", 23, 30, 1},
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{"beer", 52, 10, 3},
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{"suntan cream", 11, 70, 1},
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{"camera", 32, 30, 1},
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{"T-shirt", 24, 15, 2},
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{"trousers", 48, 10, 2},
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{"umbrella", 73, 40, 1},
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{"waterproof trousers", 42, 70, 1},
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{"waterproof overclothes",43, 75, 1},
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{"note-case", 22, 80, 1},
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{"sunglasses", 7, 20, 1},
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{"towel", 18, 12, 2},
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{"socks", 4, 50, 1},
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{"book", 30, 10, 2},
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};
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sequence {names,weights,points,counts} = columnize(items)
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constant n = length(items)
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function knapsack(int w)
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int v
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-- m is the achievable points matrix:
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-- Note that Phix uses 1-based indexes, so m[1][1]
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-- actually holds points for 0 items of weight 0,
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-- and m[n+1][w+1] is for n items at weight w.
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seq m = repeat(repeat(0,w+1),n+1)
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for i=1 to n do
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for j=1 to w+1 do -- (0 to w really)
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m[i+1][j] = m[i][j]
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for k=1 to counts[i] do
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if k*weights[i]>j-1 then
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exit
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end if
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v = m[i][j-k*weights[i]]+k*points[i]
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if v>m[i+1][j] then
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m[i+1][j] = v
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end if
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end for
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end for
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end for
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seq s = repeat(0,n)
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int j = w+1 -- (w -> 0 really)
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for i=n+1 to 2 by -1 do -- (n to 1 really)
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v = m[i][j]
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int k = 0
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while v!=m[i-1][j]+k*points[i-1] do
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s[i-1] += 1
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j -= weights[i-1]
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k += 1
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end while
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end for
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return s
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end function
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int tc = 0, tw = 0, tv = 0
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seq s = knapsack(400)
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for i=1 to n do
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int si = s[i]
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if si then
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printf(1,"%-22s %5d %5d %5d\n", {names[i], si, si*weights[i], si*points[i]})
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tc += si
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tw += si*weights[i]
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tv += si*points[i]
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end if
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end for
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printf(1,"%-22s %5d %5d %5d\n", {"count, weight, points:", tc, tw, tv})
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