Add tasks for all the new languages

This commit is contained in:
Tina Müller 2016-12-05 23:44:36 +01:00
parent 9dc3c2bb62
commit bba7bfd280
13208 changed files with 134745 additions and 0 deletions

View file

@ -0,0 +1,311 @@
PROGRAM 24SOLVE
LABEL 98,99,2540,2550,2560
! possible brackets
CONST NBRACKETS=11,ST_CONST$="+-*/^("
DIM D[4],PERM[24,4]
DIM BRAKETS$[NBRACKETS]
DIM OP$[3]
DIM STACK$[50]
PROCEDURE COMPATTA_STACK
IF NS>1 THEN
R=1
WHILE R<NS DO
IF INSTR(ST_CONST$,STACK$[R])=0 AND INSTR(ST_CONST$,STACK$[R+1])=0 THEN
FOR R1=R TO NS-1 DO
STACK$[R1]=STACK$[R1+1]
END FOR
NS=NS-1
END IF
R=R+1
END WHILE
END IF
END PROCEDURE
PROCEDURE CALC_ARITM
L=NS1
WHILE L<=NS2 DO
IF STACK$[L]="^" THEN
IF L>=NS2 THEN GOTO 99 END IF
N1#=VAL(STACK$[L-1]) N2#=VAL(STACK$[L+1]) NOP=NOP-1
IF STACK$[L]="^" THEN
RI#=N1#^N2#
END IF
STACK$[L-1]=STR$(RI#)
N=L
WHILE N<=NS2-2 DO
STACK$[N]=STACK$[N+2]
N=N+1
END WHILE
NS2=NS2-2
L=NS1-1
END IF
L=L+1
END WHILE
L=NS1
WHILE L<=NS2 DO
IF STACK$[L]="*" OR STACK$[L]="/" THEN
IF L>=NS2 THEN GOTO 99 END IF
N1#=VAL(STACK$[L-1]) N2#=VAL(STACK$[L+1]) NOP=NOP-1
IF STACK$[L]="*" THEN
RI#=N1#*N2#
ELSE
IF N2#<>0 THEN RI#=N1#/N2# ELSE NERR=6 RI#=0 END IF
END IF
STACK$[L-1]=STR$(RI#)
N=L
WHILE N<=NS2-2 DO
STACK$[N]=STACK$[N+2]
N=N+1
END WHILE
NS2=NS2-2
L=NS1-1
END IF
L=L+1
END WHILE
L=NS1
WHILE L<=NS2 DO
IF STACK$[L]="+" OR STACK$[L]="-" THEN
EXIT IF L>=NS2
N1#=VAL(STACK$[L-1]) N2#=VAL(STACK$[L+1]) NOP=NOP-1
IF STACK$[L]="+" THEN RI#=N1#+N2# ELSE RI#=N1#-N2# END IF
STACK$[L-1]=STR$(RI#)
N=L
WHILE N<=NS2-2 DO
STACK$[N]=STACK$[N+2]
N=N+1
END WHILE
NS2=NS2-2
L=NS1-1
END IF
L=L+1
END WHILE
99:
IF NOP<2 THEN ! precedenza tra gli operatori
DB#=VAL(STACK$[NS1])
ELSE
IF NOP<3 THEN
DB#=VAL(STACK$[NS1+2])
ELSE
DB#=VAL(STACK$[NS1+4])
END IF
END IF
END PROCEDURE
PROCEDURE SVOLGI_PAR
NPA=NPA-1
FOR J=NS TO 1 STEP -1 DO
EXIT IF STACK$[J]="("
END FOR
IF J=0 THEN
NS1=1 NS2=NS CALC_ARITM NERR=7
ELSE
FOR R=J TO NS-1 DO
STACK$[R]=STACK$[R+1]
END FOR
NS1=J NS2=NS-1 CALC_ARITM
IF NS1=2 THEN
NS1=1 STACK$[1]=STACK$[2]
END IF
NS=NS1
COMPATTA_STACK
END IF
END PROCEDURE
PROCEDURE MYEVAL(EXPRESSION$,DB#,NERR->DB#,NERR)
NOP=0 NPA=0 NS=1 K$="" NERR=0
STACK$[1]="@" ! init stack
FOR W=1 TO LEN(EXPRESSION$) DO
LOOP
CODE=ASC(MID$(EXPRESSION$,W,1))
IF (CODE>=48 AND CODE<=57) OR CODE=46 THEN
K$=K$+CHR$(CODE)
W=W+1 IF W>LEN(EXPRESSION$) THEN GOTO 98 END IF
ELSE
EXIT IF K$=""
IF NS>1 OR (NS=1 AND STACK$[1]<>"@") THEN NS=NS+1 END IF
IF FLAG=0 THEN
STACK$[NS]=K$
ELSE
STACK$[NS]=STR$(VAL(K$)*FLAG)
END IF
K$="" FLAG=0
EXIT
END IF
END LOOP
IF CODE=43 THEN K$="+" END IF
IF CODE=45 THEN K$="-" END IF
IF CODE=42 THEN K$="*" END IF
IF CODE=47 THEN K$="/" END IF
IF CODE=94 THEN K$="^" END IF
CASE CODE OF
43,45,42,47,94-> ! +-*/^
IF MID$(EXPRESSION$,W+1,1)="-" THEN FLAG=-1 W=W+1 END IF
IF INSTR(ST_CONST$,STACK$[NS])<>0 THEN
NERR=5
ELSE
NS=NS+1 STACK$[NS]=K$ NOP=NOP+1
IF NOP>=2 THEN
FOR J=NS TO 1 STEP -1 DO
IF STACK$[J]<>"(" THEN GOTO 2540 END IF
IF J<NS-2 THEN GOTO 2550 ELSE GOTO 2560 END IF
2540: END FOR
2550: NS1=J+1 NS2=NS CALC_ARITM
NS=NS2 STACK$[NS]=K$
REGISTRO_X#=VAL(STACK$[NS-1])
END IF
END IF
2560: END ->
40-> ! (
IF NS>1 OR (NS=1 AND STACK$[1]<>"@") THEN NS=NS+1 END IF
STACK$[NS]="(" NPA=NPA+1
IF MID$(EXPRESSION$,W+1,1)="-" THEN FLAG=-1 W=W+1 END IF
END ->
41-> ! )
SVOLGI_PAR
IF NERR=7 THEN
NERR=0 NOP=0 NPA=0 NS=1
ELSE
IF NERR=0 OR NERR=1 THEN
DB#=VAL(STACK$[NS])
REGISTRO_X#=DB#
ELSE
NOP=0 NPA=0 NS=1
END IF
END IF
END ->
OTHERWISE
NERR=8
END CASE
K$=""
END FOR
98:
IF K$<>"" THEN
IF NS>1 OR (NS=1 AND STACK$[1]<>"@") THEN NS=NS+1 END IF
IF FLAG=0 THEN STACK$[NS]=K$ ELSE STACK$[NS]=STR$(VAL(K$)*FLAG) END IF
END IF
IF INSTR(ST_CONST$,STACK$[NS])<>0 THEN
NERR=6
ELSE
WHILE NPA<>0 DO
SVOLGI_PAR
END WHILE
IF NERR<>7 THEN NS1=1 NS2=NS CALCARITM END IF
END IF
NS=1 NOP=0 NPA=0
END PROCEDURE
BEGIN
PRINT(CHR$(12);) ! CLS
! possible brackets
DATA("4#4#4#4")
DATA("(4#4)#4#4")
DATA("4#(4#4)#4")
DATA("4#4#(4#4)")
DATA("(4#4)#(4#4)")
DATA("(4#4#4)#4")
DATA("4#(4#4#4)")
DATA("((4#4)#4)#4")
DATA("(4#(4#4))#4")
DATA("4#((4#4)#4)")
DATA("4#(4#(4#4))")
FOR I=1 TO NBRACKETS DO
READ(BRAKETS$[I])
END FOR
INPUT("ENTER 4 DIGITS: ",A$)
ND=0
FOR I=1 TO LEN(A$) DO
C$=MID$(A$,I,1)
IF INSTR("123456789",C$)>0 THEN
ND=ND+1
D[ND]=VAL(C$)
END IF
END FOR
! precompute permutations. dumb way.
NPERM=1*2*3*4
N=0
FOR I=1 TO 4 DO
FOR J=1 TO 4 DO
FOR K=1 TO 4 DO
FOR L=1 TO 4 DO
! valid permutation (no dupes)
IF I<>J AND I<>K AND I<>L AND J<>K AND J<>L AND K<>L THEN
N=N+1
! actually,we can as well permute given digits
PERM[N,1]=D[I]
PERM[N,2]=D[J]
PERM[N,3]=D[K]
PERM[N,4]=D[L]
END IF
END FOR
END FOR
END FOR
END FOR
! operations: full search
COUNT=0
OPS$="+-*/"
FOR OP1=1 TO 4 DO
OP$[1]=MID$(OPS$,OP1,1)
FOR OP2=1 TO 4 DO
OP$[2]=MID$(OPS$,OP2,1)
FOR OP3=1 TO 4 DO
OP$[3]=MID$(OPS$,OP3,1)
! substitute all brackets
FOR T=1 TO NBRACKETS DO
TMPL$=BRAKETS$[T]
! now,substitute all digits: permutations.
FOR P=1 TO NPERM DO
RES$=""
NOP=0
ND=0
FOR I=1 TO LEN(TMPL$) DO
C$=MID$(TMPL$,I,1)
CASE C$ OF
"#"-> ! operations
NOP=NOP+1
RES$=RES$+OP$[NOP]
END ->
"4"-> ! digits
ND=NOP+1
RES$=RES$+MID$(STR$(PERM[P,ND]),2)
END ->
OTHERWISE ! brackets goes here
RES$=RES$+C$
END CASE
END FOR
! eval here
MY_EVAL(RES$,DB#,NERR->DB#,NERR)
IF DB#=24 AND NERR=0 THEN
PRINT("24=";RES$)
COUNT=COUNT+1
END IF
END FOR
END FOR
END FOR
END FOR
END FOR
IF COUNT=0 THEN
PRINT("If you see this, probably task cannot be solved with these digits")
ELSE
PRINT("Total=";COUNT)
END IF
END PROGRAM

View file

@ -0,0 +1,111 @@
;; use task [[RPN_to_infix_conversion#EchoLisp]] to print results
(define (rpn->string rpn)
(if (vector? rpn)
(infix->string (rpn->infix rpn))
"😥 Not found"))
(string-delimiter "")
(define OPS #(* + - // )) ;; use float division
(define-syntax-rule (commutative? op) (or (= op *) (= op +)))
;; ---------------------------------
;; calc rpn -> num value or #f if bad rpn
;; rpn is a vector of ops or numbers
;; ----------------------------------
(define (calc rpn)
(define S (stack 'S))
(for ((token rpn))
(if (procedure? token)
(let [(op2 (pop S)) (op1 (pop S))]
(if (and op1 op2)
(push S (apply token (list op1 op2)))
(push S #f))) ;; not-well formed
(push S token ))
#:break (not (stack-top S)))
(if (= 1 (stack-length S)) (pop S) #f))
;; check for legal rpn -> #f if not legal
(define (rpn? rpn)
(define S (stack 'S))
(for ((token rpn))
(if (procedure? token)
(push S (and (pop S) (pop S)))
(push S token ))
#:break (not (stack-top S)))
(stack-top S))
;; --------------------------------------
;; build-rpn : push next rpn op or number
;; dleft is number of not used digits
;; ---------------------------------------
(define count 0)
(define (build-rpn into: rpn depth maxdepth digits ops dleft target &hit )
(define cmpop #f)
(cond
;; tooo long
[(> (++ count) 200_000) (set-box! &hit 'not-found)]
;; stop on first hit
[(unbox &hit) &hit]
;; partial rpn must be legal
[(not (rpn? rpn)) #f]
;; eval rpn if complete
[(> depth maxdepth)
(when (= target (calc rpn)) (set-box! &hit rpn))]
;; else, add a digit to rpn
[else
[when (< depth maxdepth) ;; digits anywhere except last
(for [(d digits) (i 10)]
#:continue (zero? d)
(vector-set! digits i 0) ;; mark used
(vector-set! rpn depth d)
(build-rpn rpn (1+ depth) maxdepth digits ops (1- dleft) target &hit)
(vector-set! digits i d)) ;; mark unused
] ;; add digit
;; or, add an op
;; ops anywhere except positions 0,1
[when (and (> depth 1) (<= (+ depth dleft) maxdepth));; cutter : must use all digits
(set! cmpop
(and (number? [rpn (1- depth)])
(number? [rpn (- depth 2)])
(> [rpn (1- depth)] [rpn (- depth 2)])))
(for [(op ops)]
#:continue (and cmpop (commutative? op)) ;; cutter : 3 4 + === 4 3 +
(vector-set! rpn depth op)
(build-rpn rpn (1+ depth) maxdepth digits ops dleft target &hit)
(vector-set! rpn depth 0))] ;; add op
] ; add something to rpn vector
)) ; build-rpn
;;------------------------
;;gen24 : num random numbers
;;------------------------
(define (gen24 num maxrange)
(->> (append (range 1 maxrange)(range 1 maxrange)) shuffle (take num)))
;;-------------------------------------------
;; try-rpn : sets starter values for build-rpn
;;-------------------------------------------
(define (try-rpn digits target)
(set! digits (list-sort > digits)) ;; seems to accelerate things
(define rpn (make-vector (1- (* 2 (length digits)))))
(define &hit (box #f))
(set! count 0)
(build-rpn rpn starter-depth: 0
max-depth: (1- (vector-length rpn))
(list->vector digits)
OPS
remaining-digits: (length digits)
target &hit )
(writeln target '= (rpn->string (unbox &hit)) 'tries= count))
;; -------------------------------
;; (task numdigits target maxrange)
;; --------------------------------
(define (task (numdigits 4) (target 24) (maxrange 10))
(define digits (gen24 numdigits maxrange))
(writeln digits '→ target)
(try-rpn digits target))

View file

@ -0,0 +1,121 @@
--
-- 24_game_solve.exw
-- =================
--
-- Write a function that given four digits subject to the rules of the 24 game, computes an expression to solve the game if possible.
-- Show examples of solutions generated by the function
--
-- The following 5 parse expressions are possible.
-- Obviously numbers 1234 represent 24 permutations from
-- {1,2,3,4} to {4,3,2,1} of indexes to the real numbers.
-- Likewise "+-*" is like "123" representing 64 combinations
-- from {1,1,1} to {4,4,4} of indexes to "+-*/".
-- Both will be replaced if/when the strings get printed.
--
constant OPS = "+-*/"
constant expressions = {"1+(2-(3*4))",
"1+((2-3)*4)",
"(1+2)-(3*4)",
"(1+(2-3))*4",
"((1+2)-3)*4"} -- (equivalent to "1+2-3*4")
--TODO: I'm sure there is a simple (recursive) way to programatically
-- generate the above (for n=2..9) but I'm not seeing it yet...
-- The above represented as three sequential operations (the result gets
-- left in <(map)1>, ie vars[perms[operations[i][3][1]]] aka vars[lhs]):
constant operations = {{{3,'*',4},{2,'-',3},{1,'+',2}}, --3*=4; 2-=3; 1+=2
{{2,'-',3},{2,'*',4},{1,'+',2}}, --2-=3; 2*=4; 1+=2
{{1,'+',2},{3,'*',4},{1,'-',3}}, --1+=2; 3*=4; 1-=3
{{2,'-',3},{1,'+',2},{1,'*',4}}, --2-=3; 1+=2; 1*=4
{{1,'+',2},{1,'-',3},{1,'*',4}}} --1+=2; 1-=3; 1*=4
--TODO: ... and likewise for parsing "expressions" to yield "operations".
function evalopset(sequence opset, sequence perms, sequence ops, sequence vars)
-- invoked 5*24*64 = 7680 times, to try all possible expressions/vars/operators
-- (btw, vars is copy-on-write, like all parameters not explicitly returned, so
-- we can safely re-use it without clobbering the callee version.)
integer lhs,op,rhs
atom inf
for i=1 to length(opset) do
{lhs,op,rhs} = opset[i]
lhs = perms[lhs]
op = ops[find(op,OPS)]
rhs = perms[rhs]
if op='+' then
vars[lhs] += vars[rhs]
elsif op='-' then
vars[lhs] -= vars[rhs]
elsif op='*' then
vars[lhs] *= vars[rhs]
elsif op='/' then
if vars[rhs]=0 then inf = 1e300*1e300 return inf end if
vars[lhs] /= vars[rhs]
end if
end for
return vars[lhs]
end function
integer nSolutions
sequence xSolutions
procedure success(string expr, sequence perms, sequence ops, sequence vars, atom r)
integer ch
for i=1 to length(expr) do
ch = expr[i]
if ch>='1' and ch<='9' then
expr[i] = vars[perms[ch-'0']]+'0'
else
ch = find(ch,OPS)
if ch then
expr[i] = ops[ch]
end if
end if
end for
if not find(expr,xSolutions) then
-- avoid duplicates for eg {1,1,2,7} because this has found
-- the "same" solution but with the 1st and 2nd 1s swapped,
-- and likewise whenever an operator is used more than once.
printf(1,"success: %s = %s\n",{expr,sprint(r)})
nSolutions += 1
xSolutions = append(xSolutions,expr)
end if
end procedure
procedure tryperms(sequence perms, sequence ops, sequence vars)
atom r
for i=1 to length(operations) do
-- 5 parse expressions
r = evalopset(operations[i], perms, ops, vars)
if r=24 then
success(expressions[i], perms, ops, vars, r)
end if
end for
end procedure
include builtins/factorial.e
include builtins/permute.e
procedure tryops(sequence ops, sequence vars)
for p=1 to factorial(4) do
-- 24 var permutations
tryperms(permute(p,{1,2,3,4}),ops, vars)
end for
end procedure
global procedure solve24(sequence vars)
nSolutions = 0
xSolutions = {}
for op1=1 to 4 do
for op2=1 to 4 do
for op3=1 to 4 do
-- 64 operator combinations
tryops({OPS[op1],OPS[op2],OPS[op3]},vars)
end for
end for
end for
printf(1,"\n%d solutions\n",{nSolutions})
end procedure
solve24({1,1,2,7})
if getc(0) then end if

View file

@ -0,0 +1,32 @@
var formats = [
'((%d %s %d) %s %d) %s %d',
'(%d %s (%d %s %d)) %s %d',
'(%d %s %d) %s (%d %s %d)',
'%d %s ((%d %s %d) %s %d)',
'%d %s (%d %s (%d %s %d))',
];
var op = %w( + - * / );
var operators = op.map { |a| op.map {|b| op.map {|c| "#{a} #{b} #{c}" } } }.flatten;
loop {
var input = Sys.scanln("Enter four integers or 'q' to exit: ");
input == 'q' && break;
input ~~ /^\h*[1-9]\h+[1-9]\h+[1-9]\h+[1-9]\h*$/ || (
say "Invalid input!"; next;
);
var n = input.split.map{.to_i};
var numbers = n.permute;
formats.each { |format|
numbers.each { |n|
operators.each { |operator|
var o = operator.split;
var str = (format % (n[0],o[0],n[1],o[1],n[2],o[2],n[3]));
eval(str) == 24 && say str;
}
}
}
}

View file

@ -0,0 +1,57 @@
var formats = [
{|a,b,c|
Hash.new(
func => {|d,e,f,g| ((d.$a(e)).$b(f)).$c(g) },
format => "((%d #{a} %d) #{b} %d) #{c} %d"
)
},
{|a,b,c|
Hash.new(
func => {|d,e,f,g| (d.$a((e.$b(f)))).$c(g) },
format => "(%d #{a} (%d #{b} %d)) #{c} %d",
)
},
{|a,b,c|
Hash.new(
func => {|d,e,f,g| (d.$a(e)).$b(f.$c(g)) },
format => "(%d #{a} %d) #{b} (%d #{c} %d)",
)
},
{|a,b,c|
Hash.new(
func => {|d,e,f,g| (d.$a(e)).$b(f.$c(g)) },
format => "(%d #{a} %d) #{b} (%d #{c} %d)",
)
},
{|a,b,c|
Hash.new(
func => {|d,e,f,g| d.$a(e.$b(f.$c(g))) },
format => "%d #{a} (%d #{b} (%d #{c} %d))",
)
},
];
var op = %w( + - * / );
var blocks = op.map { |a| op.map { |b| op.map { |c| formats.map { |format|
format(a,b,c)
}}}}.flatten;
loop {
var input = Sys.scanln("Enter four integers or 'q' to exit: ");
input == 'q' && break;
input ~~ /^\h*[1-9]\h+[1-9]\h+[1-9]\h+[1-9]\h*$/ || (
say "Invalid input!"; next;
);
var n = input.split.map{.to_num};
var numbers = n.permute;
blocks.each { |block|
numbers.each { |n|
if (block{:func}.call(n...) == 24) {
say (block{:format} % (n...));
}
}
}
}

View file

@ -0,0 +1,172 @@
import Darwin
import Foundation
var solution = ""
println("24 Game")
println("Generating 4 digits...")
func randomDigits() -> [Int] {
var result = [Int]()
for i in 0 ..< 4 {
result.append(Int(arc4random_uniform(9)+1))
}
return result
}
// Choose 4 digits
let digits = randomDigits()
print("Make 24 using these digits : ")
for digit in digits {
print("\(digit) ")
}
println()
// get input from operator
var input = NSString(data:NSFileHandle.fileHandleWithStandardInput().availableData, encoding:NSUTF8StringEncoding)!
var enteredDigits = [Double]()
var enteredOperations = [Character]()
let inputString = input as String
// store input in the appropriate table
for character in inputString {
switch character {
case "1", "2", "3", "4", "5", "6", "7", "8", "9":
let digit = String(character)
enteredDigits.append(Double(digit.toInt()!))
case "+", "-", "*", "/":
enteredOperations.append(character)
case "\n":
println()
default:
println("Invalid expression")
}
}
// check value of expression provided by the operator
var value = 0.0
if enteredDigits.count == 4 && enteredOperations.count == 3 {
value = enteredDigits[0]
for (i, operation) in enumerate(enteredOperations) {
switch operation {
case "+":
value = value + enteredDigits[i+1]
case "-":
value = value - enteredDigits[i+1]
case "*":
value = value * enteredDigits[i+1]
case "/":
value = value / enteredDigits[i+1]
default:
println("This message should never happen!")
}
}
}
func evaluate(dPerm: [Double], oPerm: [String]) -> Bool {
var value = 0.0
if dPerm.count == 4 && oPerm.count == 3 {
value = dPerm[0]
for (i, operation) in enumerate(oPerm) {
switch operation {
case "+":
value = value + dPerm[i+1]
case "-":
value = value - dPerm[i+1]
case "*":
value = value * dPerm[i+1]
case "/":
value = value / dPerm[i+1]
default:
println("This message should never happen!")
}
}
}
return (abs(24 - value) < 0.001)
}
func isSolvable(inout digits: [Double]) -> Bool {
var result = false
var dPerms = [[Double]]()
permute(&digits, &dPerms, 0)
let total = 4 * 4 * 4
var oPerms = [[String]]()
permuteOperators(&oPerms, 4, total)
for dig in dPerms {
for opr in oPerms {
var expression = ""
if evaluate(dig, opr) {
for digit in dig {
expression += "\(digit)"
}
for oper in opr {
expression += oper
}
solution = beautify(expression)
result = true
}
}
}
return result
}
func permute(inout lst: [Double], inout res: [[Double]], k: Int) -> Void {
for i in k ..< lst.count {
swap(&lst[i], &lst[k])
permute(&lst, &res, k + 1)
swap(&lst[k], &lst[i])
}
if k == lst.count {
res.append(lst)
}
}
// n=4, total=64, npow=16
func permuteOperators(inout res: [[String]], n: Int, total: Int) -> Void {
let posOperations = ["+", "-", "*", "/"]
let npow = n * n
for i in 0 ..< total {
res.append([posOperations[(i / npow)], posOperations[((i % npow) / n)], posOperations[(i % n)]])
}
}
func beautify(infix: String) -> String {
let newString = infix as NSString
var solution = ""
solution += newString.substringWithRange(NSMakeRange(0, 1))
solution += newString.substringWithRange(NSMakeRange(12, 1))
solution += newString.substringWithRange(NSMakeRange(3, 1))
solution += newString.substringWithRange(NSMakeRange(13, 1))
solution += newString.substringWithRange(NSMakeRange(6, 1))
solution += newString.substringWithRange(NSMakeRange(14, 1))
solution += newString.substringWithRange(NSMakeRange(9, 1))
return solution
}
if value != 24 {
println("The value of the provided expression is \(value) instead of 24!")
if isSolvable(&enteredDigits) {
println("A possible solution could have been " + solution)
} else {
println("Anyway, there was no known solution to this one.")
}
} else {
println("Congratulations, you found a solution!")
}

View file

@ -0,0 +1,40 @@
# Generate a stream of the permutations of the input array.
def permutations:
if length == 0 then []
else
. as $in | range(0;length) | . as $i
| ($in|del(.[$i])|permutations)
| [$in[$i]] + .
end ;
# Generate a stream of arrays of length n,
# with members drawn from the input array.
def take(n):
length as $l |
if n == 1 then range(0;$l) as $i | [ .[$i] ]
else take(n-1) + take(1)
end;
# Emit an array with elements that alternate between those in the input array and those in short,
# starting with the former, and using nothing if "short" is too too short.
def intersperse(short):
. as $in
| reduce range(0;length) as $i
([]; . + [ $in[$i], (short[$i] // empty) ]);
# Emit a stream of all the nested triplet groupings of the input array elements,
# e.g. [1,2,3,4,5] =>
# [1,2,[3,4,5]]
# [[1,2,3],4,5]
#
def triples:
. as $in
| if length == 3 then .
elif length == 1 then $in[0]
elif length < 3 then empty
else
(range(0; (length-1) / 2) * 2 + 1) as $i
| ($in[0:$i] | triples) as $head
| ($in[$i+1:] | triples) as $tail
| [$head, $in[$i], $tail]
end;

View file

@ -0,0 +1,23 @@
# Evaluate the input, which must be a number or a triple: [x, op, y]
def eval:
if type == "array" then
.[1] as $op
| if .[0] == null or .[2] == null then null
else
(.[0] | eval) as $left | (.[2] | eval) as $right
| if $left == null or $right == null then null
elif $op == "+" then $left + $right
elif $op == "-" then $left - $right
elif $op == "*" then $left * $right
elif $op == "/" then
if $right == 0 then null
else $left / $right
end
else "invalid arithmetic operator: \($op)" | error
end
end
else .
end;
def pp:
"\(.)" | explode | map([.] | implode | if . == "," then " " elif . == "\"" then "" else . end) | join("");

View file

@ -0,0 +1,21 @@
def OPERATORS: ["+", "-", "*", "/"];
# Input: an array of 4 digits
# o: an array of 3 operators
# Output: a stream
def EXPRESSIONS(o):
intersperse( o ) | triples;
def solve(objective):
length as $length
| [ (OPERATORS | take($length-1)) as $poperators
| permutations | EXPRESSIONS($poperators)
| select( eval == objective)
] as $answers
| if $answers|length > 3 then "That was too easy. I found \($answers|length) answers, e.g. \($answers[0] | pp)"
elif $answers|length > 1 then $answers[] | pp
else "You lose! There are no solutions."
end
;
solve(24), "Please try again."

View file

@ -0,0 +1,16 @@
$ jq -r -f Solve.jq
[1,2,3,4]
That was too easy. I found 242 answers, e.g. [4 * [1 + [2 + 3]]]
Please try again.
[1,2,3,40,1]
That was too easy. I found 636 answers, e.g. [[[1 / 2] * 40] + [3 + 1]]
Please try again.
[3,8,9]
That was too easy. I found 8 answers, e.g. [[8 / 3] * 9]
Please try again.
[4,5,6]
You lose! There are no solutions.
Please try again.
[1,2,3,4,5,6]
That was too easy. I found 197926 answers, e.g. [[2 * [1 + 4]] + [3 + [5 + 6]]]
Please try again.