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Ingy döt Net 2023-07-01 11:58:00 -04:00
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I = (P) ->
# The cryptic name "I" follows the problem description;
# it returns a function that computes a moving average
# of successive values over the period P, using closure
# variables to maintain state.
cq = circular_queue(P)
num_elems = 0
sum = 0
SMA = (n) ->
sum += n
if num_elems < P
cq.add(n)
num_elems += 1
sum / num_elems
else
old = cq.replace(n)
sum -= old
sum / P
circular_queue = (n) ->
# queue that only ever stores up to n values;
# Caller shouldn't call replace until n values
# have been added.
i = 0
arr = []
add: (elem) ->
arr.push elem
replace: (elem) ->
# return value whose age is "n"
old_val = arr[i]
arr[i] = elem
i = (i + 1) % n
old_val
# The output of the code below should convince you that
# calling I multiple times returns functions with independent
# state.
sma3 = I(3)
sma7 = I(7)
sma11 = I(11)
for i in [1..10]
console.log i, sma3(i), sma7(i), sma11(i)