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1
Task/Bernoulli-numbers/Sidef/bernoulli-numbers-1.sidef
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Task/Bernoulli-numbers/Sidef/bernoulli-numbers-1.sidef
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@ -0,0 +1 @@
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say bernoulli(42).as_frac #=> 1520097643918070802691/1806
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14
Task/Bernoulli-numbers/Sidef/bernoulli-numbers-2.sidef
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Task/Bernoulli-numbers/Sidef/bernoulli-numbers-2.sidef
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func bernoulli_number(n) is cached {
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n.is_one && return 1/2
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n.is_odd && return 0
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1 - sum(^n, {|k|
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binomial(n,k) * __FUNC__(k) / (n - k + 1)
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})
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}
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for n in (0..60) {
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var Bn = bernoulli_number(n) || next
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printf("B(%2d) = %44s / %s\n", n, Bn.nude)
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}
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Task/Bernoulli-numbers/Sidef/bernoulli-numbers-3.sidef
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Task/Bernoulli-numbers/Sidef/bernoulli-numbers-3.sidef
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func ramanujan_bernoulli_number(n) is cached {
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return 1/2 if n.is_one
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return 0 if n.is_odd
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((n%6 == 4 ? -1/2 : 1) * (n+3)/3 - sum(1 .. (n - n%6)/6, {|k|
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binomial(n+3, n - 6*k) * __FUNC__(n - 6*k)
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})) / binomial(n+3, n)
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}
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15
Task/Bernoulli-numbers/Sidef/bernoulli-numbers-4.sidef
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Task/Bernoulli-numbers/Sidef/bernoulli-numbers-4.sidef
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@ -0,0 +1,15 @@
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func bernoulli_number_from_zeta(n) {
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n.is_zero && return 1
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n.is_one && return 1/2
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n.is_odd && return 0
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var log2B = (log(4*Num.tau*n)/2 + n*log(n) - n*log(Num.tau) - n)/log(2)
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local Num!PREC = *(int(n + log2B) + (n <= 90 ? 18 : 0))
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var K = 2*(n! / Num.tau**n)
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var d = n.divisors.grep {|k| is_prime(k+1) }.prod {|k| k+1 }
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var z = ceil((K*d).root(n-1)).primes.prod {|p| 1 - p.float**(-n) }
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(-1)**(n/2 + 1) * int(ceil(d*K / z)) / d
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}
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Task/Bernoulli-numbers/Sidef/bernoulli-numbers-5.sidef
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Task/Bernoulli-numbers/Sidef/bernoulli-numbers-5.sidef
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func bernoulli_print {
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var a = []
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for m in (0..60) {
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a << 1/(m+1)
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for j in (1..m -> flip) {
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(a[j-1] -= a[j]) *= j
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}
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a[0] || next
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printf("B(%2d) = %44s / %s\n", m, a[0].nude)
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}
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}
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bernoulli_print()
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