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Ingy döt Net 2023-07-01 11:58:00 -04:00
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/*REXX program solves the closest pair of points problem (in two dimensions). */
parse arg N LO HI seed . /*obtain optional arguments from the CL*/
if N=='' | N=="," then N= 100 /*Not specified? Then use the default.*/
if LO=='' | LO=="," then LO= 0 /* " " " " " " */
if HI=='' | HI=="," then HI= 20000 /* " " " " " " */
if datatype(seed, 'W') then call random ,,seed /*seed for RANDOM (BIF) repeatability.*/
w= length(HI); w= w + (w//2==0) /*W: for aligning the output columns.*/
/*╔══════════════════════╗*/ do j=1 for N /*generate N random points*/
/*║ generate N points. ║*/ @x.j= random(LO, HI) /* " a " X */
/*╚══════════════════════╝*/ @y.j= random(LO, HI) /* " a " Y */
end /*j*/ /*X & Y make the point.*/
A= 1; B= 2 /* [↓] MIND is actually the squared */
minD= (@x.A - @x.B)**2 + (@y.A - @y.B)**2 /* distance between the 1st two points.*/
/* [↓] use of XJ & YJ speed things up.*/
do j=1 for N-1; xj= @x.j; yj= @y.j /*find min distance between a point ···*/
do k=j+1 for N-j-1 /* ··· and all other (higher) points. */
sd= (xj - @x.k)**2 + (yj - @y.k)**2 /*compute squared distance from points.*/
if sd<minD then parse value sd j k with minD A B
end /*k*/ /* [↑] needn't take SQRT of SD (yet).*/
end /*j*/ /* [↑] when done, A & B are the points*/
$= 'For ' N " points, the minimum distance between the two points: "
say $ center("x", w, '')" " center('y', w, "") ' is: ' sqrt( abs(minD)) / 1
say left('', length($) - 1) "["right(@x.A, w)',' right(@y.A, w)"]"
say left('', length($) - 1) "["right(@x.B, w)',' right(@y.B, w)"]"
exit 0 /*stick a fork in it, we're all done. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
sqrt: procedure; parse arg x; if x=0 then return 0; d=digits(); m.=9; numeric form; h=d+6
numeric digits; parse value format(x,2,1,,0) 'E0' with g 'E' _ .; g= g *.5'e'_ % 2
do j=0 while h>9; m.j= h; h= h % 2 + 1; end /*j*/
do k=j+5 to 0 by -1; numeric digits m.k; g= (g+x/g)*.5; end /*k*/; return g