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Ingy döt Net 2023-07-01 11:58:00 -04:00
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Task/Doomsday-rule/ALGOL-68/doomsday-rule.alg Normal file
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BEGIN # find the day of the week of dates using John Conway's Doomsday rule #
# returns the day of the week (Sunday = 0, Monday = 1,...) for the date #
# specified by ccyy, mm and dd #
PROC dow = ( INT ccyy, mm, dd )INT:
BEGIN
INT doomsday = ( # Tuesday # 2
+ ( 5 * ( ccyy MOD 4 ) )
+ ( 4 * ( ccyy MOD 100 ) )
+ ( 6 * ( ccyy MOD 400 ) )
)
MOD 7;
BOOL is leap year = ccyy MOD 4 = 0
AND ( ccyy MOD 100 /= 0 OR ccyy MOD 400 = 0 );
INT anchor day = CASE mm
IN IF is leap year THEN 4 ELSE 3 FI
, IF is leap year THEN 1 ELSE 7 FI
, 7, 4, 2, 6, 4, 1, 5, 3, 7, 5
ESAC;
( doomsday + ( dd - anchor day ) ) MOD 7
END # dow # ;
BEGIN # task test cases #
# prints a test date and its day of the week #
PROC test dow = ( INT ccyy, mm, dd )VOID:
BEGIN
[]CHAR digit = "0123456789"[ AT 0 ];
[]STRING day name =
[]STRING( "Sunday", "Monday", "Tuesday", "Wednesday"
, "Thursday", "Friday", "Saturday"
)[ AT 0 ];
print( ( whole( ccyy, 0 )
, "-", digit[ mm OVER 10 ], digit[ mm MOD 10 ]
, "-", digit[ dd OVER 10 ], digit[ dd MOD 10 ]
, ": ", day name[ dow( ccyy, mm, dd ) ]
, newline
)
)
END # test dow # ;
test dow( 1800, 1, 6 );
test dow( 1875, 3, 29 );
test dow( 1915, 12, 7 );
test dow( 1970, 12, 23 );
test dow( 2043, 5, 14 );
test dow( 2077, 2, 12 );
test dow( 2101, 4, 2 );
test dow( 2022, 6, 19 )
END
END