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10 HOME
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100 N = 27
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110 GOSUB 400"HAILSTONE
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120 DEF FN L(I) = E(I + 4 * (I < 0))
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130IFL=112AND(S(0)=27ANDS(1)=82ANDS(2)=41ANDS(3)=124)AND(FNL(M-3)=8ANDFNL(M-2)=4ANDFNL(M-1)=2ANDFNL(M)=1)THENPRINT"THE HAILSTONE SEQUENCE FOR THE NUMBER 27 HAS 112 ELEMENTS STARTING WITH 27, 82, 41, 124 AND ENDING WITH 8, 4, 2, 1"
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140 PRINT
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150 V = PEEK(37) + 1
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200 N = 1
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210 GOSUB 400"HAILSTONE
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220 MN = 1
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230 ML = L
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240 FOR I = 2 TO 99999
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250 N = I
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260 GOSUB 400"HAILSTONE
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270 IFL>MLTHENMN=I:ML=L:VTABV:HTAB1:PRINT "THE NUMBER " MN " HAS A HAILSTONE SEQUENCE LENGTH OF "L" WHICH IS THE LONGEST HAILSTONE SEQUENCE OF NUMBERS LESS THAN ";:Y=PEEK(37)+1:X=PEEK(36)+1
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280 IF Y THEN VTAB Y : HTAB X : PRINTI+1;
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290 NEXT I
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300 END
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400 M = 0
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410 FOR L = 1 TO 1E38
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420 IF L < 5 THEN S(L-1) = N
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430 M = (M + 1) * (M < 3)
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440 E(M) = N
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450 IF N = 1 THEN RETURN
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460 EVEN = INT(N/2)=N/2
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470 IF EVEN THEN N=N/2
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480 IF NOT EVEN THEN N = (3 * N) + 1
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490 NEXT L : STOP
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