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Ingy döt Net 2023-07-01 11:58:00 -04:00
parent 7387c8f97b
commit cb5bb5e222
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Public Function incr(astring As String) As String
'simple function to increment a number string
incr = CStr(CLng(astring) + 1)
End Function

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Public Function Lincr(astring As String) As String
'increment a number string, of whatever length
'calls function "increment" or "decrement"
Dim result As String
'see if it is a negative number
If left$(astring, 1) = "-" Then
'negative x: decrease |x| by 1, then add "-"
'(except if the result is zero)
result = decrement(Mid$(astring, 2))
If result <> "0" Then result = "-" & result
Else
'0 or positive x: increase x by 1
If left$(astring, 1) = "+" Then 'allow a + before the number
result = increment(Mid$(astring, 2))
Else
result = increment(astring)
End If
End If
Lincr = result
End Function
Public Function increment(astring) As String
Dim result As String
'increment a string representing a positive number
'does not work with negative numbers
carry = 1
L = Len(astring)
result = ""
For j = L To 1 Step -1
digit = Val(Mid$(astring, j, 1)) + carry
If digit > 9 Then
digit = digit - 10
carry = 1
Else
carry = 0
End If
result = CStr(digit) & result
Next
If carry = 1 Then result = CStr(carry) & result
increment = result
End Function
Public Function decrement(astring) As String
Dim result As String
'decrement a string representing a positive number
'does not work with zero or negative numbers
borrow = 1
L = Len(astring)
result = ""
For j = L To 1 Step -1
digit = Val(Mid$(astring, j, 1)) - borrow
If digit < 0 Then
digit = digit + 10
borrow = 1
Else
borrow = 0
End If
result = CStr(digit) & result
Next
'remove leading zero, if necessary
If (Len(result) > 1) And (left$(result, 1) = "0") Then result = Mid$(result, 2)
decrement = result
End Function