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Ingy döt Net 2023-07-01 11:58:00 -04:00
parent 7387c8f97b
commit cb5bb5e222
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---
from: http://rosettacode.org/wiki/Modular_inverse

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From [http://en.wikipedia.org/wiki/Modular_multiplicative_inverse Wikipedia]:
In [[wp:modular arithmetic|modular arithmetic]], &nbsp; the '''modular multiplicative inverse''' of an [[integer]] &nbsp; <big> ''a'' </big> &nbsp; [[wp:modular arithmetic|modulo]] &nbsp; <big> ''m'' </big> &nbsp; is an integer &nbsp; <big> ''x'' </big> &nbsp; such that
::<math>a\,x \equiv 1 \pmod{m}.</math>
Or in other words, such that:
::<math>\exists k \in\Z,\qquad a\, x = 1 + k\,m</math>
It can be shown that such an inverse exists &nbsp; if and only if &nbsp; <big> ''a'' </big> &nbsp; and &nbsp; <big> ''m'' </big> &nbsp; are [[wp:coprime|coprime]], &nbsp; but we will ignore this for this task.
;Task:
Either by implementing the algorithm, by using a dedicated library or by using a built-in function in
your language, &nbsp; compute the modular inverse of &nbsp; 42 modulo 2017.
<br><br>

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F mul_inv(=a, =b)
V b0 = b
V x0 = 0
V x1 = 1
I b == 1 {R 1}
L a > 1
V q = a I/ b
(a, b) = (b, a % b)
(x0, x1) = (x1 - q * x0, x0)
I x1 < 0 {x1 += b0}
R x1
print(mul_inv(42, 2017))

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\ return "extended gcd" of a and b; The result satisfies the equation:
\ a*x + b*y = gcd(a,b)
: n:xgcd \ a b -- gcd x y
dup 0 n:= if
1 swap \ -- a 1 0
else
tuck n:/mod
-rot recurse
tuck 4 roll
n:* n:neg n:+
then ;
\ Return modular inverse of n modulo mod, or null if it doesn't exist (n and mod
\ not coprime):
: n:invmod \ n mod -- invmod
dup >r
n:xgcd rot 1 n:= not if
2drop null
else
drop dup 0 n:< if r@ n:+ then
then
rdrop ;
42 2017 n:invmod . cr bye

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BEGIN
PROC modular inverse = (INT a, m) INT :
BEGIN
PROC extended gcd = (INT x, y) []INT :
CO
Algol 68 allows us to return three INTs in several ways. A [3]INT
is used here but it could just as well be a STRUCT.
CO
BEGIN
INT v := 1, a := 1, u := 0, b := 0, g := x, w := y;
WHILE w>0
DO
INT q := g % w, t := a - q * u;
a := u; u := t;
t := b - q * v;
b := v; v := t;
t := g - q * w;
g := w; w := t
OD;
a PLUSAB (a < 0 | u | 0);
(a, b, g)
END;
[] INT egcd = extended gcd (a, m);
(egcd[3] > 1 | 0 | egcd[1] MOD m)
END;
printf (($"42 ^ -1 (mod 2017) = ", g(0)$, modular inverse (42, 2017)))
CO
Note that if ϕ(m) is known, then a^-1 = a^(ϕ(m)-1) mod m which
allows an alternative implementation in terms of modular
exponentiation but, in general, this requires the factorization of
m. If m is prime the factorization is trivial and ϕ(m) = m-1.
2017 is prime which may, or may not, be ironic within the context
of the Rosetta Code conditions.
CO
END

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REM Modular inverse
E = 42
T = 2017
GOSUB CalcModInv:
PRINT ModInv
END
CalcModInv:
REM Increments E Step times until Bal is greater than T
REM Repeats until Bal = 1 (MOD = 1) and returns Count
REM Bal will not be greater than T + E
D = 0
IF E < T THEN
Bal = E
Count = 1
Loop:
Step = T - Bal
Step = Step / E
Step = Step + 1
REM So ... Step = (T - Bal) / E + 1
StepTimesE = Step * E
Bal = Bal + StepTimesE
Count = Count + Step
Bal = Bal - T
IF Bal <> 1 THEN Loop:
D = Count
ENDIF
ModInv = D
RETURN

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(*
Using the algorithm described at
https://en.wikipedia.org/w/index.php?title=Extended_Euclidean_algorithm&oldid=1135569411#Modular_integers
*)
#include "share/atspre_staload.hats"
fn {tk : tkind}
division_with_nonnegative_remainder
(n : g0int tk, d : g0int tk,
(* q and r are called by reference, and start out
uninitialized. *)
q : &g0int tk? >> g0int tk,
r : &g0int tk? >> g0int tk)
: void =
let
(* The C optimizer most likely will reduce these these two
divisions to just one. They are simply synonyms for C '/' and
'%', and perform division that rounds the quotient towards
zero. *)
val q0 = g0int_div (n, d)
val r0 = g0int_mod (n, d)
in
(* The following calculation results in 'floor division', if the
divisor is positive, or 'ceiling division', if the divisor is
negative. This choice of method results in the remainder never
being negative. *)
if isgtez n || iseqz r0 then
(q := q0; r := r0)
else if isltz d then
(q := succ q0; r := r0 - d)
else
(q := pred q0; r := r0 + d)
end
fn {tk : tkind}
inverse (a : g0int tk, n : g0int tk) : Option_vt (g0int tk) =
let
typedef integer = g0int tk
fun
loop (t : integer, newt : integer,
r : integer, newr : integer) : Option_vt integer =
if iseqz newr then
begin
if r > g0i2i 1 then
None_vt ()
else if t < g0i2i 0 then
Some_vt (t + n)
else
Some_vt t
end
else
let
(* These become C variables. *)
var quotient : g0int tk?
var remainder : g0int tk?
(* Show the type AT COMPILE TIME. *)
prval _ = $showtype quotient
prval _ = $showtype remainder
val () =
division_with_nonnegative_remainder
(r, newr, quotient, remainder)
(* THE TYPES WILL HAVE CHANGED, because the storage is
initialized by the call to
division_with_nonnegative_remainder. *)
prval _ = $showtype quotient
prval _ = $showtype remainder
val t = newt
and newt = t - (quotient * newt)
and r = newr
and newr = remainder
in
loop (t, newt, r, newr)
end
in
loop (g0i2i 0, g0i2i 1, n, a)
end
implement
main0 () =
case+ inverse (42LL, 2017LL) of
| ~ None_vt () => println! "There is no inverse."
| ~ Some_vt value => println! value

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(*
Using the algorithm described at
https://en.wikipedia.org/w/index.php?title=Extended_Euclidean_algorithm&oldid=1135569411#Modular_integers
*)
#include "share/atspre_staload.hats"
fn {tk : tkind}
division_with_nonnegative_remainder
(n : g0int tk, d : g0int tk,
(* q and r are called by reference, and start out
uninitialized. *)
q : &g0int tk? >> g0int tk,
r : &g0int tk? >> g0int tk)
: void =
let
(* The C optimizer most likely will reduce these these two
divisions to just one. They are simply synonyms for C '/' and
'%', and perform division that rounds the quotient towards
zero. *)
val q0 = g0int_div (n, d)
val r0 = g0int_mod (n, d)
in
(* The following calculation results in 'floor division', if the
divisor is positive, or 'ceiling division', if the divisor is
negative. This choice of method results in the remainder never
being negative. *)
if isgtez n || iseqz r0 then
(q := q0; r := r0)
else if isltz d then
(q := succ q0; r := r0 - d)
else
(q := pred q0; r := r0 + d)
end
fn {tk : tkind}
inverse (a : g0int tk, n : g0int tk,
inverse_exists : &bool? >> bool exists,
inverse_value : &g0int tk? >> opt (g0int tk, exists))
: #[exists: bool] void =
let
typedef integer = g0int tk
fun
loop (t : integer, newt : integer,
r : integer, newr : integer,
inverse_exists : &bool? >> bool exists,
inverse_value : &g0int tk? >> opt (g0int tk, exists))
: #[exists: bool] void =
if iseqz newr then
begin
if r > g0i2i 1 then
let
val () = inverse_exists := false
prval () = opt_none inverse_value
in
end
else if t < g0i2i 0 then
let
val () = inverse_exists := true
val () = inverse_value := t + n
prval () = opt_some inverse_value
in
end
else
let
val () = inverse_exists := true
val () = inverse_value := t
prval () = opt_some inverse_value
in
end
end
else
let
(* These become C variables. *)
var quotient : g0int tk?
var remainder : g0int tk?
val () =
division_with_nonnegative_remainder
(r, newr, quotient, remainder)
val t = newt
and newt = t - (quotient * newt)
and r = newr
and newr = remainder
in
loop (t, newt, r, newr, inverse_exists, inverse_value)
end
in
loop (g0i2i 0, g0i2i 1, n, a, inverse_exists, inverse_value)
end
implement
main0 () =
let
var inverse_exists : bool?
var inverse_value : llint?
in
inverse (42LL, 2017LL, inverse_exists, inverse_value);
if inverse_exists then
let
prval () = opt_unsome inverse_value
in
println! inverse_value
end
else
let
prval () = opt_unnone inverse_value
in
println! "There is no inverse."
end
end

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# syntax: GAWK -f MODULAR_INVERSE.AWK
# converted from C
BEGIN {
printf("%s\n",mod_inv(42,2017))
exit(0)
}
function mod_inv(a,b, b0,t,q,x0,x1) {
b0 = b
x0 = 0
x1 = 1
if (b == 1) {
return(1)
}
while (a > 1) {
q = int(a / b)
t = b
b = int(a % b)
a = t
t = x0
x0 = x1 - q * x0
x1 = t
}
if (x1 < 0) {
x1 += b0
}
return(x1)
}

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INT FUNC ModInverse(INT a,b)
INT t,nt,r,nr,q,tmp
IF b<0 THEN b=-b FI
IF a<0 THEN a=b-(-a MOD b) FI
t=0 nt=1
r=b nr=a MOD b
WHILE nr#0
DO
q=r/nr
tmp=nt nt=t-q*nt t=tmp
tmp=nr nr=r-q*nr r=tmp
OD
IF r>1 THEN
RETURN (-1)
FI
IF t<0 THEN
t==+b
FI
RETURN (t)
PROC Test(INT a,b)
INT res
res=ModInverse(a,b)
IF res>=0 THEN
PrintF("%I MODINV %I=%I%E",a,b,res)
ELSE
PrintF("%I MODINV %I has no result%E",a,b)
FI
RETURN
PROC Main()
Test(42,2017)
Test(40,1)
Test(52,-217)
Test(-486,217)
Test(40,2018)
RETURN

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with Ada.Text_IO;use Ada.Text_IO;
procedure modular_inverse is
-- inv_mod calculates the inverse of a mod n. We should have n>0 and, at the end, the contract is a*Result=1 mod n
-- If this is false then we raise an exception (don't forget the -gnata option when you compile
function inv_mod (a : Integer; n : Positive) return Integer with post=> (a * inv_mod'Result) mod n = 1 is
-- To calculate the inverse we do as if we would calculate the GCD with the Euclid extended algorithm
-- (but we just keep the coefficient on a)
function inverse (a, b, u, v : Integer) return Integer is
(if b=0 then u else inverse (b, a mod b, v, u-(v*a)/b));
begin
return inverse (a, n, 1, 0);
end inv_mod;
begin
-- This will output -48 (which is correct)
Put_Line (inv_mod (42,2017)'img);
-- The further line will raise an exception since the GCD will not be 1
Put_Line (inv_mod (42,77)'img);
exception when others => Put_Line ("The inverse doesn't exist.");
end modular_inverse;

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modInverse: function [a,b][
if b = 1 -> return 1
b0: b x0: 0 x1: 1
z: a
while [z > 1][
q: z / b t: b
b: z % b z: t
t: x0 x0: x1 - q * x0
x1: t
]
(x1 < 0) ? -> x1 + b0
-> x1
]
print modInverse 42 2017

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MsgBox, % ModInv(42, 2017)
ModInv(a, b) {
if (b = 1)
return 1
b0 := b, x0 := 0, x1 :=1
while (a > 1) {
q := a // b
, t := b
, b := Mod(a, b)
, a := t
, t := x0
, x0 := x1 - q * x0
, x1 := t
}
if (x1 < 0)
x1 += b0
return x1
}

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print multInv(42, 2017)
end
function multInv(a,b)
x0 = 0
b0 = b
multInv = 1
if b = 1 then return
while a > 1
q = a / b
t = b
b = a mod b
a = t
t = x0
x0 = multInv - q * x0
multInv = int(t)
end while
if multInv < 0 then return multInv + b0
end function

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get "libhdr"
let mulinv(a, b) =
b<0 -> mulinv(a, -b),
a<0 -> mulinv(b - (-a rem b), b),
valof
$( let t, nt, r, nr = 0, 1, b, a rem b
until nr = 0
$( let tmp, q = ?, r / nr
tmp := nt ; nt := t - q*nt ; t := tmp
tmp := nr ; nr := r - q*nr ; r := tmp
$)
resultis r>1 -> -1,
t<0 -> t + b,
t
$)
let show(a, b) be
$( let mi = mulinv(a, b)
test mi>=0
do writef("%N, %N -> %N*N", a, b, mi)
or writef("%N, %N -> no inverse*N", a, b)
$)
let start() be
$( show(42, 2017)
show(40, 1)
show(52, -217)
show(-486, 217)
show(40, 2018)
$)

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@echo off
setlocal enabledelayedexpansion
%== Calls the "function" ==%
call :ModInv 42 2017 result
echo !result!
call :ModInv 40 1 result
echo !result!
call :ModInv 52 -217 result
echo !result!
call :ModInv -486 217 result
echo !result!
call :ModInv 40 2018 result
echo !result!
pause>nul
exit /b 0
%== The "function" ==%
:ModInv
set a=%1
set b=%2
if !b! lss 0 (set /a b=-b)
if !a! lss 0 (set /a a=b - ^(-a %% b^))
set t=0&set nt=1&set r=!b!&set /a nr=a%%b
:while_loop
if !nr! neq 0 (
set /a q=r/nr
set /a tmp=nt
set /a nt=t - ^(q*nt^)
set /a t=tmp
set /a tmp=nr
set /a nr=r - ^(q*nr^)
set /a r=tmp
goto while_loop
)
if !r! gtr 1 (set %3=-1&goto :EOF)
if !t! lss 0 set /a t+=b
set %3=!t!
goto :EOF

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( ( mod-inv
= a b b0 x0 x1 q
. !arg:(?a.?b)
& ( !b:1
| (!b.0.1):(?b0.?x0.?x1)
& whl
' ( !a:>1
& div$(!a.!b):?q
& (!b.mod$(!a.!b)):(?a.?b)
& (!x1+-1*!q*!x0.!x0):(?x0.?x1)
)
& (!x:>0|!x1+!b0)
)
)
& out$(mod-inv$(42.2017))
};

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#include <iostream>
int mul_inv(int a, int b)
{
int b0 = b, t, q;
int x0 = 0, x1 = 1;
if (b == 1) return 1;
while (a > 1) {
q = a / b;
t = b, b = a % b, a = t;
t = x0, x0 = x1 - q * x0, x1 = t;
}
if (x1 < 0) x1 += b0;
return x1;
}
int main(void) {
std::cout << mul_inv(42, 2017) << std::endl;
return 0;
}

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#include <iostream>
short ObtainMultiplicativeInverse(int a, int b, int s0 = 1, int s1 = 0)
{
return b==0? s0: ObtainMultiplicativeInverse(b, a%b, s1, s0 - s1*(a/b));
}
int main(int argc, char* argv[])
{
std::cout << ObtainMultiplicativeInverse(42, 2017) << std::endl;
return 0;
}

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public class Program
{
static void Main()
{
System.Console.WriteLine(42.ModInverse(2017));
}
}
public static class IntExtensions
{
public static int ModInverse(this int a, int m)
{
if (m == 1) return 0;
int m0 = m;
(int x, int y) = (1, 0);
while (a > 1) {
int q = a / m;
(a, m) = (m, a % m);
(x, y) = (y, x - q * y);
}
return x < 0 ? x + m0 : x;
}
}

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#include <stdio.h>
int mul_inv(int a, int b)
{
int b0 = b, t, q;
int x0 = 0, x1 = 1;
if (b == 1) return 1;
while (a > 1) {
q = a / b;
t = b, b = a % b, a = t;
t = x0, x0 = x1 - q * x0, x1 = t;
}
if (x1 < 0) x1 += b0;
return x1;
}
int main(void) {
printf("%d\n", mul_inv(42, 2017));
return 0;
}

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#include <stdio.h>
int mul_inv(int a, int b)
{
int t, nt, r, nr, q, tmp;
if (b < 0) b = -b;
if (a < 0) a = b - (-a % b);
t = 0; nt = 1; r = b; nr = a % b;
while (nr != 0) {
q = r/nr;
tmp = nt; nt = t - q*nt; t = tmp;
tmp = nr; nr = r - q*nr; r = tmp;
}
if (r > 1) return -1; /* No inverse */
if (t < 0) t += b;
return t;
}
int main(void) {
printf("%d\n", mul_inv(42, 2017));
printf("%d\n", mul_inv(40, 1));
printf("%d\n", mul_inv(52, -217)); /* Pari semantics for negative modulus */
printf("%d\n", mul_inv(-486, 217));
printf("%d\n", mul_inv(40, 2018));
return 0;
}

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mul_inv = proc (a, b: int) returns (int) signals (no_inverse)
if b<0 then b := -b end
if a<0 then a := b - (-a // b) end
t: int := 0
nt: int := 1
r: int := b
nr: int := a // b
while nr ~= 0 do
q: int := r / nr
t, nt := nt, t - q*nt
r, nr := nr, r - q*nr
end
if r>1 then signal no_inverse end
if t<0 then t := t+b end
return(t)
end mul_inv
start_up = proc ()
pair = struct[a, b: int]
tests: sequence[pair] := sequence[pair]$
[pair${a: 42, b: 2017},
pair${a: 40, b: 1},
pair${a: 52, b: -217},
pair${a: -486, b: 217},
pair${a: 40, b: 2018}]
po: stream := stream$primary_output()
for test: pair in sequence[pair]$elements(tests) do
stream$puts(po, int$unparse(test.a) || ", "
|| int$unparse(test.b) || " -> ")
stream$putl(po, int$unparse(mul_inv(test.a, test.b)))
except when no_inverse:
stream$putl(po, "no modular inverse")
end
end
end start_up

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10 CLS
20 CALL modularinverse(42, 2017)
30 CALL modularinverse(40, 1)
40 END
50 SUB modularinverse(e,t)
60 d = 0
70 IF e < t THEN
80 b = e
90 c = 1
100 WHILE b > 1
110 s = INT(((t-b)/e)+1)
120 b = b+s*e
130 c = c+s
140 b = b-t
150 WEND
160 d = c
170 ENDIF
180 m = d
190 PRINT m
200 END SUB

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(ns test-p.core
(:require [clojure.math.numeric-tower :as math]))
(defn extended-gcd
"The extended Euclidean algorithm--using Clojure code from RosettaCode for Extended Eucliean
(see http://en.wikipedia.orwiki/Extended_Euclidean_algorithm)
Returns a list containing the GCD and the Bézout coefficients
corresponding to the inputs with the result: gcd followed by bezout coefficients "
[a b]
(cond (zero? a) [(math/abs b) 0 1]
(zero? b) [(math/abs a) 1 0]
:else (loop [s 0
s0 1
t 1
t0 0
r (math/abs b)
r0 (math/abs a)]
(if (zero? r)
[r0 s0 t0]
(let [q (quot r0 r)]
(recur (- s0 (* q s)) s
(- t0 (* q t)) t
(- r0 (* q r)) r))))))
(defn mul_inv
" Get inverse using extended gcd. Extended GCD returns
gcd followed by bezout coefficients. We want the 1st coefficients
(i.e. second of extend-gcd result). We compute mod base so result
is between 0..(base-1) "
[a b]
(let [b (if (neg? b) (- b) b)
a (if (neg? a) (- b (mod (- a) b)) a)
egcd (extended-gcd a b)]
(if (= (first egcd) 1)
(mod (second egcd) b)
(str "No inverse since gcd is: " (first egcd)))))
(println (mul_inv 42 2017))
(println (mul_inv 40 1))
(println (mul_inv 52 -217))
(println (mul_inv -486 217))
(println (mul_inv 40 2018))

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0010 FUNC mulinv#(a#,b#) CLOSED
0020 IF b#<0 THEN b#:=-b#
0030 IF a#<0 THEN a#:=b#-(-a# MOD b#)
0040 t#:=0;nt#:=1;r#:=b#;nr#:=a# MOD b#
0050 WHILE nr#<>0 DO
0060 q#:=r# DIV nr#
0070 tmp#:=nt#;nt#:=t#-q#*nt#;t#:=tmp#
0080 tmp#:=nr#;nr#:=r#-q#*nr#;r#:=tmp#
0090 ENDWHILE
0100 IF r#>1 THEN RETURN -1
0110 IF t#<0 THEN t#:+b#
0120 RETURN t#
0130 ENDFUNC mulinv#
0140 //
0150 WHILE NOT EOD DO
0160 READ a#,b#
0170 PRINT a#,", ",b#," -> ",mulinv#(a#,b#)
0180 ENDWHILE
0190 END
0200 //
0210 DATA 42,2017,40,1,52,-217,-486,217,40,2018

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;;
;; Calculates the GCD of a and b based on the Extended Euclidean Algorithm. The function also returns
;; the Bézout coefficients s and t, such that gcd(a, b) = as + bt.
;;
;; The algorithm is described on page http://en.wikipedia.org/wiki/Extended_Euclidean_algorithm#Iterative_method_2
;;
(defun egcd (a b)
(do ((r (cons b a) (cons (- (cdr r) (* (car r) q)) (car r))) ; (r+1 r) i.e. the latest is first.
(s (cons 0 1) (cons (- (cdr s) (* (car s) q)) (car s))) ; (s+1 s)
(u (cons 1 0) (cons (- (cdr u) (* (car u) q)) (car u))) ; (t+1 t)
(q nil))
((zerop (car r)) (values (cdr r) (cdr s) (cdr u))) ; exit when r+1 = 0 and return r s t
(setq q (floor (/ (cdr r) (car r)))))) ; inside loop; calculate the q
;;
;; Calculates the inverse module for a = 1 (mod m).
;;
;; Note: The inverse is only defined when a and m are coprimes, i.e. gcd(a, m) = 1.”
;;
(defun invmod (a m)
(multiple-value-bind (r s k) (egcd a m)
(unless (= 1 r) (error "invmod: Values ~a and ~a are not coprimes." a m))
s))

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include "cowgol.coh";
sub mulinv(a: int32, b: int32): (t: int32) is
if b<0 then b := -b; end if;
if a<0 then a := b - (-a % b); end if;
t := 0;
var nt: int32 := 1;
var r := b;
var nr := a % b;
while nr != 0 loop
var q := r / nr;
var tmp := nt; nt := t - q*nt; t := tmp;
tmp := nr; nr := r - q*nr; r := tmp;
end loop;
if r>1 then t := -1;
elseif t<0 then t := t + b;
end if;
end sub;
record Pair is
a: int32;
b: int32;
end record;
var data: Pair[] := {
{42, 2017},
{40, 1},
{52, -217},
{-486, 217},
{40, 2018}
};
var i: @indexof data := 0;
while i < @sizeof data loop
print_i32(data[i].a as uint32);
print(", ");
print_i32(data[i].b as uint32);
print(" -> ");
var mi := mulinv(data[i].a, data[i].b);
if mi<0
then print("no inverse");
else print_i32(mi as uint32);
end if;
print_nl();
i := i + 1;
end loop;

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let e = 42
let t = 2017
gosub modularinverse
end
sub modularinverse
let d = 0
if e < t then
let b = e
let c = 1
do
let s = int(((t - b) / e) + 1)
let b = b + s * e
let c = c + s
let b = b - t
loop b <> 1
let d = c
endif
let m = d
print m
return

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def modinv(a0, m0)
return 1 if m0 == 1
a, m = a0, m0
x0, inv = 0, 1
while a > 1
inv -= (a // m) * x0
a, m = m, a % m
x0, inv = inv, x0
end
inv += m0 if inv < 0
inv
end

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T modInverse(T)(T a, T b) pure nothrow {
if (b == 1)
return 1;
T b0 = b,
x0 = 0,
x1 = 1;
while (a > 1) {
immutable q = a / b;
auto t = b;
b = a % b;
a = t;
t = x0;
x0 = x1 - q * x0;
x1 = t;
}
return (x1 < 0) ? (x1 + b0) : x1;
}
void main() {
import std.stdio;
writeln(modInverse(42, 2017));
}

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dc -e "[m=]P?dsm[a=]P?dsa1sv[dsb~rsqlbrldlqlv*-lvsdsvd0<x]dsxxldd[dlmr+]sx0>xdla*lm%[p]sx1=x"

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proc mulinv(int a, b) int:
int t, nt, r, nr, q, tmp;
if b<0 then b := -b fi;
if a<0 then a := b - (-a % b) fi;
t := 0; nt := 1; r := b; nr := a % b;
while nr /= 0 do
q := r / nr;
tmp := nt; nt := t - q*nt; t := tmp;
tmp := nr; nr := r - q*nr; r := tmp
od;
if r>1 then -1
elif t<0 then t+b
else t
fi
corp
proc show(int a, b) void:
int mi;
mi := mulinv(a, b);
if mi>=0
then writeln(a:5, ", ", b:5, " -> ", mi:5)
else writeln(a:5, ", ", b:5, " -> no inverse")
fi
corp
proc main() void:
show(42, 2017);
show(40, 1);
show(52, -217);
show(-486, 217);
show(40, 2018)
corp

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PROGRAM MOD_INV
!$INTEGER
PROCEDURE MUL_INV(A,B->T)
LOCAL NT,R,NR,Q,TMP
IF B<0 THEN B=-B
IF A<0 THEN A=B-(-A MOD B)
T=0 NT=1 R=B NR=A MOD B
WHILE NR<>0 DO
Q=R DIV NR
TMP=NT NT=T-Q*NT T=TMP
TMP=NR NR=R-Q*NR R=TMP
END WHILE
IF (R>1) THEN T=-1 EXIT PROCEDURE ! NO INVERSE
IF (T<0) THEN T+=B
END PROCEDURE
BEGIN
MUL_INV(42,2017->T) PRINT(T)
MUL_INV(40,1->T) PRINT(T)
MUL_INV(52,-217->T) PRINT(T) ! pari semantics for negative modulus
MUL_INV(-486,217->T) PRINT(T)
MUL_INV(40,2018->T) PRINT(T)
END PROGRAM

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proc mod_inv a b . x1 .
b0 = b
x1 = 1
if b = 1
break 1
.
while a > 1
q = a div b
t = b
b = a mod b
a = t
t = x0
x0 = x1 - q * x0
x1 = t
.
if x1 < 0
x1 += b0
.
.
call mod_inv 42 2017 r
print r

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(lib 'math) ;; for egcd = extended gcd
(define (mod-inv x m)
(define-values (g inv q) (egcd x m))
(unless (= 1 g) (error 'not-coprimes (list x m) ))
(if (< inv 0) (+ m inv) inv))
(mod-inv 42 2017) → 1969
(mod-inv 42 666)
🔴 error: not-coprimes (42 666)

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defmodule Modular do
def extended_gcd(a, b) do
{last_remainder, last_x} = extended_gcd(abs(a), abs(b), 1, 0, 0, 1)
{last_remainder, last_x * (if a < 0, do: -1, else: 1)}
end
defp extended_gcd(last_remainder, 0, last_x, _, _, _), do: {last_remainder, last_x}
defp extended_gcd(last_remainder, remainder, last_x, x, last_y, y) do
quotient = div(last_remainder, remainder)
remainder2 = rem(last_remainder, remainder)
extended_gcd(remainder, remainder2, x, last_x - quotient*x, y, last_y - quotient*y)
end
def inverse(e, et) do
{g, x} = extended_gcd(e, et)
if g != 1, do: raise "The maths are broken!"
rem(x+et, et)
end
end
IO.puts Modular.inverse(42,2017)

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// Calculate the inverse of a (mod m)
// See here for eea specs:
// https://en.wikipedia.org/wiki/Extended_Euclidean_algorithm
let modInv m a =
let rec eea t t' r r' =
match r' with
| 0 -> t
| _ ->
let div = r/r'
eea t' (t - div * t') r' (r - div * r')
(m + eea 0 1 m a) % m

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@ -0,0 +1,2 @@
USE: math.functions
42 2017 mod-inv

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@ -0,0 +1,10 @@
: invmod { a m | v b c -- inv }
m to v
1 to c
0 to b
begin a
while v a / >r
c b s>d c s>d r@ 1 m*/ d- d>s to c to b
a v s>d a s>d r> 1 m*/ d- d>s to a to v
repeat b m mod dup to b 0<
if m b + else b then ;

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@ -0,0 +1,18 @@
: modinv ( a m - inv)
dup 1- \ a m (m != 1)?
if \ a m
tuck 1 0 \ m0 a m 1 0
begin \ m0 a m inv x0
2>r over 1 > \ m0 a m (a > 1)? R: inv x0
while \ m0 a m R: inv x0
tuck /mod \ m0 m (a mod m) (a/m) R: inv x0
r> tuck * \ m0 a' m' x0 (a/m)*x0 R: inv
r> swap - \ m0 a' m' x0 (inv-q) R:
repeat \ m0 a' m' inv' x0'
2drop \ m0 R: inv x0
2r> drop \ m0 inv R:
dup 0< \ m0 inv (inv < 0)?
if over + then \ m0 (inv + m0)
then \ x inv'
nip \ inv
;

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@ -0,0 +1,38 @@
program modular_inverse_task
implicit none
write (*,*) inverse (42, 2017)
contains
! Returns -1 if there is no inverse. I assume n > 0. The algorithm
! is described at
! https://en.wikipedia.org/w/index.php?title=Extended_Euclidean_algorithm&oldid=1135569411#Modular_integers
function inverse (a, n) result (inverse_value)
integer, intent(in) :: a, n
integer :: inverse_value
integer :: t, newt
integer :: r, newr
integer :: quotient, remainder, tmp
if (n <= 0) error stop
t = 0; newt = 1
r = n; newr = a
do while (newr /= 0)
remainder = modulo (r, newr) ! Floor division.
quotient = (r - remainder) / newr
tmp = newt; newt = t - (quotient * newt); t = tmp
r = newr; newr = remainder
end do
if (r > 1) then
inverse_value = -1
else if (t < 0) then
inverse_value = t + n
else
inverse_value = t
end if
end function inverse
end program modular_inverse_task

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' version 10-07-2018
' compile with: fbc -s console
Type ext_euclid
Dim As Integer a, b
End Type
' "Table method" aka "The Magic Box"
Function magic_box(x As Integer, y As Integer) As ext_euclid
Dim As Integer a(1 To 128), b(1 To 128), d(1 To 128), k(1 To 128)
a(1) = 1 : b(1) = 0 : d(1) = x
a(2) = 0 : b(2) = 1 : d(2) = y : k(2) = x \ y
Dim As Integer i = 2
While Abs(d(i)) <> 1
i += 1
a(i) = a(i -2) - k(i -1) * a(i -1)
b(i) = b(i -2) - k(i -1) * b(i -1)
d(i) = d(i -2) Mod d(i -1)
k(i) = d(i -1) \ d(i)
'Print a(i),b(i),d(i),k(i)
If d(i -1) Mod d(i) = 0 Then Exit While
Wend
If d(i) = -1 Then ' -1 * (ab + by) = -1 * -1 ==> -ab -by = 1
a(i) = -a(i)
b(i) = -b(i)
End If
Function = Type( a(i), b(i) )
End Function
' ------=< MAIN >=------
Dim As Integer x, y, gcd
Dim As ext_euclid result
Do
Read x, y
If x = 0 AndAlso y = 0 Then Exit Do
result = magic_box(x, y)
With result
gcd = .a * x + .b * y
Print "a * "; Str(x); " + b * "; Str(y);
Print " = GCD("; Str(x); ", "; Str(y); ") ="; gcd
If gcd > 1 Then
Print "No solution, numbers are not coprime"
Else
Print "a = "; .a; ", b = ";.b
Print "The Modular inverse of "; x; " modulo "; y; " = ";
While .a < 0 : .a += IIf(y > 0, y, -y) : Wend
Print .a
'Print "The Modular inverse of "; y; " modulo "; x; " = ";
'While .b < 0 : .b += IIf(x > 0, x, -x) : Wend
'Print .b
End if
End With
Print
Loop
Data 42, 2017
Data 40, 1
Data 52, -217
Data -486, 217
Data 40, 2018
Data 0, 0
' empty keyboard buffer
While Inkey <> "" : Wend
Print : Print "hit any key to end program"
Sleep
End

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@ -0,0 +1 @@
println[modInverse[42, 2017]]

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@ -0,0 +1,12 @@
import integers.egcd
def modinv( a, m ) =
val (g, x, _) = egcd( a, m )
if g != 1 then error( a + ' and ' + m + ' not coprime' )
val res = x % m
if res < 0 then res + m else res
println( modinv(42, 2017) )

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@ -0,0 +1,27 @@
10 ' Modular inverse
20 LET E% = 42
30 LET T% = 2017
40 GOSUB 1000
50 PRINT MODINV%
60 END
990 ' increments e stp (step) times until bal is greater than t
992 ' repeats until bal = 1 (mod = 1) and returns count
994 ' bal will not be greater than t + e
1000 LET D% = 0
1010 IF E% >= T% THEN GOTO 1140
1020 LET BAL% = E%
1025 ' At least one iteration is necessary
1030 LET STP% = ((T% - BAL%) \ E%) + 1
1040 LET BAL% = BAL% + STP% * E%
1050 LET COUNT% = 1 + STP%
1060 LET BAL% = BAL% - T%
1070 WHILE BAL% <> 1
1080 LET STP% = ((T% - BAL%) \ E%) + 1
1090 LET BAL% = BAL% + STP% * E%
1100 LET COUNT% = COUNT% + STP%
1110 LET BAL% = BAL% - T%
1120 WEND
1130 LET D% = COUNT%
1140 LET MODINV% = D%
1150 RETURN

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@ -0,0 +1,13 @@
package main
import (
"fmt"
"math/big"
)
func main() {
a := big.NewInt(42)
m := big.NewInt(2017)
k := new(big.Int).ModInverse(a, m)
fmt.Println(k)
}

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-- Given a and m, return Just x such that ax = 1 mod m.
-- If there is no such x return Nothing.
modInv :: Int -> Int -> Maybe Int
modInv a m
| 1 == g = Just (mkPos i)
| otherwise = Nothing
where
(i, _, g) = gcdExt a m
mkPos x
| x < 0 = x + m
| otherwise = x
-- Extended Euclidean algorithm.
-- Given non-negative a and b, return x, y and g
-- such that ax + by = g, where g = gcd(a,b).
-- Note that x or y may be negative.
gcdExt :: Int -> Int -> (Int, Int, Int)
gcdExt a 0 = (1, 0, a)
gcdExt a b =
let (q, r) = a `quotRem` b
(s, t, g) = gcdExt b r
in (t, s - q * t, g)
main :: IO ()
main = mapM_ print [2 `modInv` 4, 42 `modInv` 2017]

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@ -0,0 +1,18 @@
100 PRINT MODINV(42,2017)
120 DEF MODINV(A,B)
130 LET B=ABS(B)
140 IF A<0 THEN LET A=B-MOD(-A,B)
150 LET T=0:LET NT=1:LET R=B:LET NR=MOD(A,B)
160 DO WHILE NR<>0
170 LET Q=INT(R/NR)
180 LET TMP=NT:LET NT=T-Q*NT:LET T=TMP
190 LET TMP=NR:LET NR=R-Q*NR:LET R=TMP
200 LOOP
210 IF R>1 THEN
220 LET MODINV=-1
230 ELSE IF T<0 THEN
240 LET MODINV=T+B
250 ELSE
260 LET MODINV=T
270 END IF
280 END DEF

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procedure main(args)
a := integer(args[1]) | 42
b := integer(args[2]) | 2017
write(mul_inv(a,b))
end
procedure mul_inv(a,b)
if b == 1 then return 1
(b0 := b, x0 := 0, x1 := 1)
while a > 1 do {
q := a/b
(t := b, b := a%b, a := t)
(t := x0, x0 := x1-q*x0, x1 := t)
}
return if (x1 > 0) then x1 else x1+b0
end

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@ -0,0 +1,19 @@
link numbers
procedure main(args)
a := integer(args[1]) | 42
b := integer(args[2]) | 2017
write(mul_inv(a,b))
end
procedure mul_inv(a,b)
if b == 1 then return 1
if gcd(a,b) ~= 1 then return "not coprime"
(b0 := b, x0 := 0, x1 := 1)
while a > 1 do {
q := a/b
(t := b, b := a%b, a := t)
(t := x0, x0 := x1-q*x0, x1 := t)
}
return if (x1 > 0) then x1 else x1+b0
end

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@ -0,0 +1 @@
modInv =: dyad def 'x y&|@^ <: 5 p: y'"0

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@ -0,0 +1,2 @@
42 modInv 2017
1969

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@ -0,0 +1 @@
System.out.println(BigInteger.valueOf(42).modInverse(BigInteger.valueOf(2017)));

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@ -0,0 +1,8 @@
var modInverse = function(a, b) {
a %= b;
for (var x = 1; x < b; x++) {
if ((a*x)%b == 1) {
return x;
}
}
}

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@ -0,0 +1,36 @@
# Integer division:
# If $j is 0, then an error condition is raised;
# otherwise, assuming infinite-precision integer arithmetic,
# if the input and $j are integers, then the result will be an integer.
def idivide($j):
. as $i
| ($i % $j) as $mod
| ($i - $mod) / $j ;
# the multiplicative inverse of . modulo $n
def modInv($n):
if $n == 1 then 1
else . as $this
| { r : $n,
t : 0,
newR: length, # abs
newT: 1}
| until(.newR == 0;
.newR as $newR
| (.r | idivide($newR)) as $q
| {r : $newR,
t : .newT,
newT: (.t - $q * .newT),
newR: (.r - $q * $newR) } )
| if (.r|length) != 1 then "\($this) and \($n) are not co-prime." | error
else .t
| if . < 0 then . + $n
elif $this < 0 then - .
else .
end
end
end ;
# Example:
42 | modInv(2017)

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@ -0,0 +1 @@
invmod(a, b)

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@ -0,0 +1,11 @@
function modinv{T<:Integer}(a::T, b::T)
b0 = b
x0, x1 = zero(T), one(T)
while a > 1
q = div(a, b)
a, b = b, a % b
x0, x1 = x1 - q * x0, x0
end
x1 < 0 ? x1 + b0 : x1
end
modinv(a::Integer, b::Integer) = modinv(promote(a,b)...)

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@ -0,0 +1,9 @@
// version 1.0.6
import java.math.BigInteger
fun main(args: Array<String>) {
val a = BigInteger.valueOf(42)
val m = BigInteger.valueOf(2017)
println(a.modInverse(m))
}

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@ -0,0 +1,32 @@
{def mulinv
{def mulinv.loop
{lambda {:t :nt :r :nr}
{if {not {= :nr 0}}
then {mulinv.loop :nt
{- :t {* {floor {/ :r :nr}} :nt}}
:nr
{- :r {* {floor {/ :r :nr}} :nr}} }
else {cons :t :r} }}}
{lambda {:a :n}
{let { {:a :a} {:n :n}
{:cons {mulinv.loop 0
1
{if {< :n 0} then {- :n} else :n}
{if {< :a 0} then {- :n {% {- :a} :n}} else :a}}}
} {if {> {cdr :cons} 1}
then not invertible
else {if {< {car :cons} 0}
then {+ {car :cons} :n}
else {car :cons} }}}}}
-> mulinv
{mulinv 42 2017}
-> 1969
{mulinv 40 1}
-> 0
{mulinv 52 -217}
-> 96
{mulinv -486 217}
-> 121
{mulinv 40 218}
-> not invertible

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@ -0,0 +1,18 @@
divert(-1)
# I assume non-negative arguments. The algorithm is described at
# https://en.wikipedia.org/w/index.php?title=Extended_Euclidean_algorithm&oldid=1135569411#Modular_integers
define(`inverse',`_$0(eval(`$1'), eval(`$2'))')
define(`_inverse',`_$0($2, 0, 1, $2, $1)')
define(`__inverse',
`dnl n = $1, t = $2, newt = $3, r = $4, newr = $5
ifelse(eval($5 != 0), 1, `$0($1, $3,
eval($2 - (($4 / $5) * $3)),
$5,eval($4 % $5))',
eval($4 > 1), 1, `no inverse',
eval($2 < 0), 1, eval($2 + $1),
$2)')
divert`'dnl
inverse(42, 2017)

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@ -0,0 +1,38 @@
NORMAL MODE IS INTEGER
INTERNAL FUNCTION(AA, BB)
ENTRY TO MULINV.
A = AA
B = BB
WHENEVER B.L.0, B = -B
WHENEVER A.L.0, A = B - (-(A-A/B*B))
T = 0
NT = 1
R = B
NR = A-A/B*B
LOOP WHENEVER NR.NE.0
Q = R/NR
TMP = NT
NT = T - Q*NT
T = TMP
TMP = NR
NR = R - Q*NR
R = TMP
TRANSFER TO LOOP
END OF CONDITIONAL
WHENEVER R.G.1, FUNCTION RETURN -1
WHENEVER T.L.0, T = T+B
FUNCTION RETURN T
END OF FUNCTION
INTERNAL FUNCTION(AA, BB)
VECTOR VALUES FMT = $I5,2H, ,I5,2H: ,I5*$
ENTRY TO SHOW.
PRINT FORMAT FMT, AA, BB, MULINV.(AA, BB)
END OF FUNCTION
SHOW.(42,2017)
SHOW.(40,1)
SHOW.(52,-217)
SHOW.(-486,217)
SHOW.(40,2018)
END OF PROGRAM

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@ -0,0 +1 @@
1/42 mod 2017;

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@ -0,0 +1 @@
ModularInverse[a, m]

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@ -0,0 +1,42 @@
%%% -*- mode: mercury; prolog-indent-width: 2; -*-
%%%
%%% Compile with:
%%% mmc --make --use-subdirs modular_inverse_task
%%%
:- module modular_inverse_task.
:- interface.
:- import_module io.
:- pred main(io::di, io::uo) is det.
:- implementation.
:- import_module exception.
:- import_module int.
%% inverse(A, N, Inverse). I assume N > 0, and throw an exception if
%% it is not. The predicate fails if there is no inverse (and thus is
%% "semidet"). The algorithm is described at
%% https://en.wikipedia.org/w/index.php?title=Extended_Euclidean_algorithm&oldid=1135569411#Modular_integers
:- pred inverse(int::in, int::in, int::out) is semidet.
inverse(A, N, Inverse) :-
if (N =< 0) then throw(domain_error("inverse"))
else inverse_(N, 0, 1, N, A, Inverse).
:- pred inverse_(int::in, int::in, int::in, int::in, int::in,
int::out) is semidet.
inverse_(N, T, NewT, R, NewR, Inverse) :-
if (NewR \= 0)
then (Quotient = div(R, NewR), % Floor division.
inverse_(N,
NewT, T - (Quotient * NewT),
NewR, R - (Quotient * NewR),
Inverse)) % Tail recursion.
else (R =< 1, % R =< 1 FAILS if R > 1.
(if (T < 0) then Inverse = T + N else Inverse = T)).
main(!IO) :-
if inverse(42, 2017, Inverse)
then (print(Inverse, !IO), nl(!IO))
else (print("There is no inverse.", !IO), nl(!IO)).
:- end_module modular_inverse_task.

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@ -0,0 +1,19 @@
10 REM Modular inverse
20 LET E = 42
30 LET T = 2017
40 GOSUB 500
50 PRINT M
60 END
490 REM Calculate modular inverse
500 LET D = 0
510 IF E >= T THEN 600
520 LET B = E
530 LET C = 1
540 LET S1 = INT((T-B)/E)+1
550 LET B = B+S1*E
560 LET C = C+S1
570 LET B = B-T
580 IF B <> 1 THEN 540
590 LET D = C
600 LET M = D
610 RETURN

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@ -0,0 +1,43 @@
MODULE ModularInverse;
FROM InOut IMPORT WriteString, WriteInt, WriteLn;
TYPE Data = RECORD x : INTEGER;
y : INTEGER
END;
VAR c : INTEGER;
ab : ARRAY [1..5] OF Data;
PROCEDURE mi(VAR a, b : INTEGER): INTEGER;
VAR t, nt, r, nr, q, tmp : INTEGER;
BEGIN
b := ABS(b);
IF a < 0 THEN a := b - (-a MOD b) END;
t := 0; nt := 1; r := b; nr := a MOD b;
WHILE (nr # 0) DO
q := r / nr;
tmp := nt; nt := t - q * nt; t := tmp;
tmp := nr; nr := r - q * nr; r := tmp;
END;
IF (r > 1) THEN RETURN -1 END;
IF (t < 0) THEN RETURN t + b END;
RETURN t;
END mi;
BEGIN
ab[1].x := 42; ab[1].y := 2017;
ab[2].x := 40; ab[2].y := 1;
ab[3].x := 52; ab[3].y := -217;
ab[4].x := -486; ab[4].y := 217;
ab[5].x := 40; ab[5].y := 2018;
WriteLn;
WriteString("Modular inverse");
WriteLn;
FOR c := 1 TO 5 DO
WriteInt(ab[c].x, 6); WriteString(", ");
WriteInt(ab[c].y, 6); WriteString(" = ");
WriteInt(mi(ab[c].x, ab[c].y),6);
WriteLn;
END;
END ModularInverse.

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@ -0,0 +1,30 @@
(define (modular-multiplicative-inverse a n)
(if (< n 0)
(setf n (abs n)))
(if (< a 0)
(setf a (- n (% (- 0 a) n))))
(setf t 0)
(setf nt 1)
(setf r n)
(setf nr (mod a n))
(while (not (zero? nr))
(setf q (int (div r nr)))
(setf tmp nt)
(setf nt (sub t (mul q nt)))
(setf t tmp)
(setf tmp nr)
(setf nr (sub r (mul q nr)))
(setf r tmp))
(if (> r 1)
(setf retvalue nil))
(if (< t 0)
(setf retvalue (add t n))
(setf retvalue t))
retvalue)
(println (modular-multiplicative-inverse 42 2017))

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@ -0,0 +1,12 @@
proc modInv(a0, b0: int): int =
var (a, b, x0) = (a0, b0, 0)
result = 1
if b == 1: return
while a > 1:
result = result - (a div b) * x0
a = a mod b
swap a, b
swap x0, result
if result < 0: result += b0
echo modInv(42, 2017)

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@ -0,0 +1,8 @@
let mul_inv a = function 1 -> 1 | b ->
let rec aux a b x0 x1 =
if a <= 1 then x1 else
if b = 0 then failwith "mul_inv" else
aux b (a mod b) (x1 - (a / b) * x0) x0
in
let x = aux a b 0 1 in
if x < 0 then x + b else x

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@ -0,0 +1,11 @@
let rec gcd_ext a = function
| 0 -> (1, 0, a)
| b ->
let s, t, g = gcd_ext b (a mod b) in
(t, s - (a / b) * t, g)
let mod_inv a m =
let mk_pos x = if x < 0 then x + m else x in
match gcd_ext a m with
| i, _, 1 -> mk_pos i
| _ -> failwith "mod_inv"

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@ -0,0 +1,75 @@
(*-*- mode: indented-text; tab-width: 2; -*-*)
MODULE modularInverseInOberon2;
IMPORT Out;
(* Division with a non-negative remainder. This will work no matter
how your compiler handles DIV (and mine seems not to do what the
Oberon-2 specification says). *)
PROCEDURE euclidDiv (x, y : INTEGER) : INTEGER;
VAR q : INTEGER;
BEGIN
IF 0 <= y THEN (* Do floor division. *)
IF 0 <= x THEN
q := x DIV y
ELSE
q := -((-x) DIV y);
IF (-x) MOD y # 0 THEN q := q - 1 END
END;
ELSE (* Do ceiling division. *)
IF 0 <= x THEN
q := -(x DIV (-y))
ELSE
q := ((-x) DIV (-y));
IF (-x) MOD (-y) # 0 THEN q := q + 1 END
END
END;
RETURN q
END euclidDiv;
(* I have added this unit test because, earlier, I posted a buggy
version of euclidDiv. *)
PROCEDURE testEuclidDiv;
VAR x, y, q, r : INTEGER;
BEGIN
FOR x := -100 TO 100 DO
FOR y := -100 TO 100 DO
IF y # 0 THEN
q := euclidDiv (x, y);
r := x - (q * y);
IF (r < 0) OR (ABS (y) <= r) THEN
(* A remainder was outside the expected range. *)
Out.String ("euclidDiv fails its test")
END
END
END
END
END testEuclidDiv;
PROCEDURE inverse (a, n : INTEGER) : INTEGER;
VAR t, newt : INTEGER;
VAR r, newr : INTEGER;
VAR quotient : INTEGER;
VAR tmp : INTEGER;
BEGIN
t := 0; newt := 1;
r := n; newr := a;
WHILE newr # 0 DO
quotient := euclidDiv (r, newr);
tmp := newt; newt := t - (quotient * newt); t := tmp;
tmp := newr; newr := r - (quotient * newr); r := tmp
END;
IF r > 1 THEN
t := -1
ELSIF t < 0 THEN
t := t + n
END;
RETURN t
END inverse;
BEGIN
testEuclidDiv;
Out.Int (inverse (42, 2017), 0);
Out.Ln
END modularInverseInOberon2.

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@ -0,0 +1,55 @@
# -*- ObjectIcon -*-
import exception
import io
procedure main ()
test_euclid_div ()
io.write (inverse (42, 2017))
end
procedure inverse (a, n) # FAILS if there is no inverse.
local t, newt, r, newr, quotient, tmp
if n <= 0 then throw ("non-positive modulus")
t := 0; newt := 1
r := n; newr := a
while newr ~= 0 do
{
quotient := euclid_div (r, newr)
tmp := newt; newt := t - (quotient * newt); t := tmp
tmp := newr; newr := r - (quotient * newr); r := tmp
}
r <= 1 | fail
return (if t < 0 then t + n else t)
end
procedure euclid_div (x, y)
# This kind of integer division always gives a remainder between 0
# and abs(y)-1, inclusive. Thus the remainder is always a LEAST
# RESIDUE modulo abs(y). (If y is a positive modulus, then only the
# floor division branch is used.)
return \
if 0 <= y then # Do floor division.
(if 0 <= x then x / y
else if (-x) % y = 0 then -((-x) / y)
else -((-x) / y) - 1)
else # Do ceiling division.
(if 0 <= x then -(x / (-y))
else if (-x) % (-y) = 0 then ((-x) / (-y))
else ((-x) / (-y)) + 1)
end
procedure test_euclid_div ()
local x, y, q, r
every x := -100 to 100 do
every y := -100 to 100 & y ~= 0 do
{
q := euclid_div (x, y)
r := x - (q * y)
if r < 0 | abs (y) <= r then
# A remainder was outside the expected range.
throw ("Test of euclid_div failed.")
}
end

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@ -0,0 +1,22 @@
// euclid ( a b -- u v r )
// Return r = gcd(a, b) and (u, v) / r = au + bv
: euclid(a, b)
| q u u1 v v1 |
b 0 < ifTrue: [ b neg ->b ]
a 0 < ifTrue: [ b a neg b mod - ->a ]
1 dup ->u ->v1
0 dup ->v ->u1
while(b) [
b a b /mod ->q ->b ->a
u1 u u1 q * - ->u1 ->u
v1 v v1 q * - ->v1 ->v
]
u v a ;
: invmod(a, modulus)
a modulus euclid 1 == ifFalse: [ drop drop null return ]
drop dup 0 < ifTrue: [ modulus + ] ;

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@ -0,0 +1,39 @@
(import (owl math)
(owl math extra))
(define (euclid-quotient x y)
(if (<= 0 y)
(cond ((<= 0 x) (quotient x y))
((zero? (remainder (negate x) y))
(negate (quotient (negate x) y)))
(else (- (negate (quotient (negate x) y)) 1)))
(cond ((<= 0 x) (negate (quotient x (negate y))))
((zero? (remainder (negate x) (negate y)))
(quotient (negate x) (negate y)))
(else (+ (quotient (negate x) (negate y)) 1)))))
;; A unit test of euclid-quotient.
(let repeat ((x -100)
(y -100))
(cond ((= x 101) #t)
((= y 0) (repeat x (+ y 1)))
((= y 101) (repeat (+ x 1) -100))
(else (let* ((q (euclid-quotient x y))
(r (- x (* q y))))
(cond ((< r 0) (display "negative remainder\n"))
((<= (abs y) r) (display "remainder too large\n"))
(else (repeat x (+ y 1))))))))
(define (inverse a n)
(let repeat ((t 0) (newt 1)
(r n) (newr a))
(cond ((not (zero? newr))
(let ((quotient (euclid-quotient r newr)))
(repeat newt (- t (* quotient newt))
newr (- r (* quotient newr)))))
((< 1 r) #f) ; The inverse does not exist.
((negative? t) (+ t n))
(else t))))
(display (inverse 42 2017))
(newline)

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@ -0,0 +1 @@
Mod(1/42,2017)

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@ -0,0 +1,16 @@
<?php
function invmod($a,$n){
if ($n < 0) $n = -$n;
if ($a < 0) $a = $n - (-$a % $n);
$t = 0; $nt = 1; $r = $n; $nr = $a % $n;
while ($nr != 0) {
$quot= intval($r/$nr);
$tmp = $nt; $nt = $t - $quot*$nt; $t = $tmp;
$tmp = $nr; $nr = $r - $quot*$nr; $r = $tmp;
}
if ($r > 1) return -1;
if ($t < 0) $t += $n;
return $t;
}
printf("%d\n", invmod(42, 2017));
?>

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@ -0,0 +1,33 @@
*process source attributes xref or(!);
/*--------------------------------------------------------------------
* 13.07.2015 Walter Pachl
*-------------------------------------------------------------------*/
minv: Proc Options(main);
Dcl (x,y) Bin Fixed(31);
x=42;
y=2017;
Put Edit('modular inverse of',x,' by ',y,' ---> ',modinv(x,y))
(Skip,3(a,f(4)));
modinv: Proc(a,b) Returns(Bin Fixed(31));
Dcl (a,b,ob,ox,d,t) Bin Fixed(31);
ob=b;
ox=0;
d=1;
If b=1 Then;
Else Do;
Do While(a>1);
q=a/b;
r=mod(a,b);
a=b;
b=r;
t=ox;
ox=d-q*ox;
d=t;
End;
End;
If d<0 Then
d=d+ob;
Return(d);
End;
End;

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@ -0,0 +1,24 @@
// increments e step times until bal is greater than t
// repeats until bal = 1 (mod = 1) and returns count
// bal will not be greater than t + e
function modInv(e, t : integer) : integer;
var
d : integer;
bal, count, step : integer;
begin
d := 0;
if e < t then
begin
count := 1;
bal := e;
repeat
step := ((t-bal) DIV e)+1;
bal := bal + step * e;
count := count + step;
bal := bal - t;
until bal = 1;
d := count;
end;
modInv := d;
end;

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@ -0,0 +1,9 @@
use bigint; say 42->bmodinv(2017);
# or
use Math::ModInt qw/mod/; say mod(42, 2017)->inverse->residue;
# or
use Math::Pari qw/PARI lift/; say lift PARI "Mod(1/42,2017)";
# or
use Math::GMP qw/:constant/; say 42->bmodinv(2017);
# or
use ntheory qw/invmod/; say invmod(42, 2017);

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@ -0,0 +1,15 @@
sub invmod {
my($a,$n) = @_;
my($t,$nt,$r,$nr) = (0, 1, $n, $a % $n);
while ($nr != 0) {
# Use this instead of int($r/$nr) to get exact unsigned integer answers
my $quot = int( ($r - ($r % $nr)) / $nr );
($nt,$t) = ($t-$quot*$nt,$nt);
($nr,$r) = ($r-$quot*$nr,$nr);
}
return if $r > 1;
$t += $n if $t < 0;
$t;
}
say invmod(42,2017);

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@ -0,0 +1,22 @@
(phixonline)-->
<span style="color: #008080;">function</span> <span style="color: #000000;">mul_inv</span><span style="color: #0000FF;">(</span><span style="color: #004080;">integer</span> <span style="color: #000000;">a</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">n</span><span style="color: #0000FF;">)</span>
<span style="color: #008080;">if</span> <span style="color: #000000;">n</span><span style="color: #0000FF;"><</span><span style="color: #000000;">0</span> <span style="color: #008080;">then</span> <span style="color: #000000;">n</span> <span style="color: #0000FF;">=</span> <span style="color: #0000FF;">-</span><span style="color: #000000;">n</span> <span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #008080;">if</span> <span style="color: #000000;">a</span><span style="color: #0000FF;"><</span><span style="color: #000000;">0</span> <span style="color: #008080;">then</span> <span style="color: #000000;">a</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">n</span> <span style="color: #0000FF;">-</span> <span style="color: #7060A8;">mod</span><span style="color: #0000FF;">(-</span><span style="color: #000000;">a</span><span style="color: #0000FF;">,</span><span style="color: #000000;">n</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #004080;">integer</span> <span style="color: #000000;">t</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">0</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">nt</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">1</span><span style="color: #0000FF;">,</span>
<span style="color: #000000;">r</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">n</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">nr</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">a</span><span style="color: #0000FF;">;</span>
<span style="color: #008080;">while</span> <span style="color: #000000;">nr</span><span style="color: #0000FF;">!=</span><span style="color: #000000;">0</span> <span style="color: #008080;">do</span>
<span style="color: #004080;">integer</span> <span style="color: #000000;">q</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">floor</span><span style="color: #0000FF;">(</span><span style="color: #000000;">r</span><span style="color: #0000FF;">/</span><span style="color: #000000;">nr</span><span style="color: #0000FF;">)</span>
<span style="color: #0000FF;">{</span><span style="color: #000000;">t</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">nt</span><span style="color: #0000FF;">}</span> <span style="color: #0000FF;">=</span> <span style="color: #0000FF;">{</span><span style="color: #000000;">nt</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">t</span><span style="color: #0000FF;">-</span><span style="color: #000000;">q</span><span style="color: #0000FF;">*</span><span style="color: #000000;">nt</span><span style="color: #0000FF;">}</span>
<span style="color: #0000FF;">{</span><span style="color: #000000;">r</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">nr</span><span style="color: #0000FF;">}</span> <span style="color: #0000FF;">=</span> <span style="color: #0000FF;">{</span><span style="color: #000000;">nr</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">r</span><span style="color: #0000FF;">-</span><span style="color: #000000;">q</span><span style="color: #0000FF;">*</span><span style="color: #000000;">nr</span><span style="color: #0000FF;">}</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">while</span>
<span style="color: #008080;">if</span> <span style="color: #000000;">r</span><span style="color: #0000FF;">></span><span style="color: #000000;">1</span> <span style="color: #008080;">then</span> <span style="color: #008080;">return</span> <span style="color: #008000;">"a is not invertible"</span> <span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #008080;">if</span> <span style="color: #000000;">t</span><span style="color: #0000FF;"><</span><span style="color: #000000;">0</span> <span style="color: #008080;">then</span> <span style="color: #000000;">t</span> <span style="color: #0000FF;">+=</span> <span style="color: #000000;">n</span> <span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #008080;">return</span> <span style="color: #000000;">t</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #0000FF;">?</span><span style="color: #000000;">mul_inv</span><span style="color: #0000FF;">(</span><span style="color: #000000;">42</span><span style="color: #0000FF;">,</span><span style="color: #000000;">2017</span><span style="color: #0000FF;">)</span>
<span style="color: #0000FF;">?</span><span style="color: #000000;">mul_inv</span><span style="color: #0000FF;">(</span><span style="color: #000000;">40</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">1</span><span style="color: #0000FF;">)</span>
<span style="color: #0000FF;">?</span><span style="color: #000000;">mul_inv</span><span style="color: #0000FF;">(</span><span style="color: #000000;">52</span><span style="color: #0000FF;">,</span> <span style="color: #0000FF;">-</span><span style="color: #000000;">217</span><span style="color: #0000FF;">)</span> <span style="color: #000080;font-style:italic;">/* Pari semantics for negative modulus */</span>
<span style="color: #0000FF;">?</span><span style="color: #000000;">mul_inv</span><span style="color: #0000FF;">(-</span><span style="color: #000000;">486</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">217</span><span style="color: #0000FF;">)</span>
<span style="color: #0000FF;">?</span><span style="color: #000000;">mul_inv</span><span style="color: #0000FF;">(</span><span style="color: #000000;">40</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">2018</span><span style="color: #0000FF;">)</span>
<!--

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@ -0,0 +1,17 @@
(de modinv (A B)
(let (B0 B X0 0 X1 1 Q 0 T1 0)
(while (< 1 A)
(setq
Q (/ A B)
T1 B
B (% A B)
A T1
T1 X0
X0 (- X1 (* Q X0))
X1 T1 ) )
(if (lt0 X1) (+ X1 B0) X1) ) )
(println
(modinv 42 2017) )
(bye)

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@ -0,0 +1,23 @@
function invmod($a,$n){
if ([int]$n -lt 0) {$n = -$n}
if ([int]$a -lt 0) {$a = $n - ((-$a) % $n)}
$t = 0
$nt = 1
$r = $n
$nr = $a % $n
while ($nr -ne 0) {
$q = [Math]::truncate($r/$nr)
$tmp = $nt
$nt = $t - $q*$nt
$t = $tmp
$tmp = $nr
$nr = $r - $q*$nr
$r = $tmp
}
if ($r -gt 1) {return -1}
if ($t -lt 0) {$t += $n}
return $t
}
invmod 42 2017

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@ -0,0 +1,10 @@
egcd(_, 0, 1, 0) :- !.
egcd(A, B, X, Y) :-
divmod(A, B, Q, R),
egcd(B, R, S, X),
Y is S - Q*X.
modinv(A, B, N) :-
egcd(A, B, X, Y),
A*X + B*Y =:= 1,
N is X mod B.

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@ -0,0 +1,37 @@
EnableExplicit
Declare main()
Declare.i mi(a.i, b.i)
If OpenConsole("MODULAR-INVERSE")
main() : Input() : End
EndIf
Macro ModularInverse(a, b)
PrintN(~"\tMODULAR-INVERSE(" + RSet(Str(a),5) + "," +
RSet(Str(b),5)+") = " +
RSet(Str(mi(a, b)),5))
EndMacro
Procedure main()
ModularInverse(42, 2017) ; = 1969
ModularInverse(40, 1) ; = 0
ModularInverse(52, -217) ; = 96
ModularInverse(-486, 217) ; = 121
ModularInverse(40, 2018) ; = -1
EndProcedure
Procedure.i mi(a.i, b.i)
Define x.i = 1,
y.i = Int(Abs(b)),
r.i = 0
If y = 1 : ProcedureReturn 0 : EndIf
While x < y
r = (a * x) % b
If r = 1 Or (y + r) = 1
Break
EndIf
x + 1
Wend
If x > y - 1 : x = -1 : EndIf
ProcedureReturn x
EndProcedure

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@ -0,0 +1,18 @@
>>> def extended_gcd(aa, bb):
lastremainder, remainder = abs(aa), abs(bb)
x, lastx, y, lasty = 0, 1, 1, 0
while remainder:
lastremainder, (quotient, remainder) = remainder, divmod(lastremainder, remainder)
x, lastx = lastx - quotient*x, x
y, lasty = lasty - quotient*y, y
return lastremainder, lastx * (-1 if aa < 0 else 1), lasty * (-1 if bb < 0 else 1)
>>> def modinv(a, m):
g, x, y = extended_gcd(a, m)
if g != 1:
raise ValueError
return x % m
>>> modinv(42, 2017)
1969
>>>

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@ -0,0 +1,91 @@
from functools import (reduce)
from itertools import (chain)
# modInv :: Int -> Int -> Maybe Int
def modInv(a):
return lambda m: (
lambda ig=gcdExt(a)(m): (
lambda i=ig[0]: (
Just(i + m if 0 > i else i) if 1 == ig[2] else (
Nothing()
)
)
)()
)()
# gcdExt :: Int -> Int -> (Int, Int, Int)
def gcdExt(x):
def go(a, b):
if 0 == b:
return (1, 0, a)
else:
(q, r) = divmod(a, b)
(s, t, g) = go(b, r)
return (t, s - q * t, g)
return lambda y: go(x, y)
# TEST ---------------------------------------------------
# Numbers between 2010 and 2015 which do yield modular inverses for 42:
# main :: IO ()
def main():
print (
mapMaybe(
lambda y: bindMay(modInv(42)(y))(
lambda mInv: Just((y, mInv))
)
)(
enumFromTo(2010)(2025)
)
)
# -> [(2011, 814), (2015, 48), (2017, 1969), (2021, 1203)]
# GENERIC ABSTRACTIONS ------------------------------------
# enumFromTo :: Int -> Int -> [Int]
def enumFromTo(m):
return lambda n: list(range(m, 1 + n))
# bindMay (>>=) :: Maybe a -> (a -> Maybe b) -> Maybe b
def bindMay(m):
return lambda mf: (
m if m.get('Nothing') else mf(m.get('Just'))
)
# Just :: a -> Maybe a
def Just(x):
return {'type': 'Maybe', 'Nothing': False, 'Just': x}
# mapMaybe :: (a -> Maybe b) -> [a] -> [b]
def mapMaybe(mf):
return lambda xs: reduce(
lambda a, x: maybe(a)(lambda j: a + [j])(mf(x)),
xs,
[]
)
# maybe :: b -> (a -> b) -> Maybe a -> b
def maybe(v):
return lambda f: lambda m: v if m.get('Nothing') else (
f(m.get('Just'))
)
# Nothing :: Maybe a
def Nothing():
return {'type': 'Maybe', 'Nothing': True}
# MAIN ---
main()

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@ -0,0 +1,17 @@
[ dup 1 != if
[ tuck 1 0
[ swap temp put
temp put
over 1 > while
tuck /mod swap
temp take tuck *
temp take swap -
again ]
2drop
temp release
temp take
dup 0 < if
[ over + ] ]
nip ] is modinv ( n n --> n )
42 2017 modinv echo

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@ -0,0 +1,17 @@
/*REXX program calculates and displays the modular inverse of an integer X modulo Y.*/
parse arg x y . /*obtain two integers from the C.L. */
if x=='' | x=="," then x= 42 /*Not specified? Then use the default.*/
if y=='' | y=="," then y= 2017 /* " " " " " " */
say 'modular inverse of ' x " by " y ' ' modInv(x,y)
exit /*stick a fork in it, we're all done. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
modInv: parse arg a,b 1 ob; z= 0 /*B & OB are obtained from the 2nd arg.*/
$= 1 /*initialize modular inverse to unity. */
if b\=1 then do while a>1
parse value a/b a//b b z with q b a t
z= $ - q * z
$= trunc(t)
end /*while*/
if $<0 then $= $ + ob /*Negative? Then add the original B. */
return $

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(require math)
(modular-inverse 42 2017)

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1969

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sub inverse($n, :$modulo) {
my ($c, $d, $uc, $vc, $ud, $vd) = ($n % $modulo, $modulo, 1, 0, 0, 1);
my $q;
while $c != 0 {
($q, $c, $d) = ($d div $c, $d % $c, $c);
($uc, $vc, $ud, $vd) = ($ud - $q*$uc, $vd - $q*$vc, $uc, $vc);
}
return $ud % $modulo;
}
say inverse 42, :modulo(2017)

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see "42 %! 2017 = " + multInv(42, 2017) + nl
func multInv a,b
b0 = b
x0 = 0
multInv = 1
if b = 1 return 0 ok
while a > 1
q = floor(a / b)
t = b
b = a % b
a = t
t = x0
x0 = multInv - q * x0
multInv = t
end
if multInv < 0 multInv = multInv + b0 ok
return multInv

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#based on pseudo code from http://en.wikipedia.org/wiki/Extended_Euclidean_algorithm#Iterative_method_2 and from translating the python implementation.
def extended_gcd(a, b)
last_remainder, remainder = a.abs, b.abs
x, last_x, y, last_y = 0, 1, 1, 0
while remainder != 0
last_remainder, (quotient, remainder) = remainder, last_remainder.divmod(remainder)
x, last_x = last_x - quotient*x, x
y, last_y = last_y - quotient*y, y
end
return last_remainder, last_x * (a < 0 ? -1 : 1)
end
def invmod(e, et)
g, x = extended_gcd(e, et)
if g != 1
raise 'The maths are broken!'
end
x % et
end

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def modinv(a, m) # compute a^-1 mod m if possible
raise "NO INVERSE - #{a} and #{m} not coprime" unless a.gcd(m) == 1
return m if m == 1
m0, inv, x0 = m, 1, 0
while a > 1
inv -= (a / m) * x0
a, m = m, a % m
inv, x0 = x0, inv
end
inv += m0 if inv < 0
inv
end

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require 'openssl'
p OpenSSL::BN.new(42).mod_inverse(2017).to_i

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print multInv(42, 2017)
end
function multInv(a,b)
b0 = b
multInv = 1
if b = 1 then goto [endFun]
while a > 1
q = a / b
t = b
b = a mod b
a = t
t = x0
x0 = multInv - q * x0
multInv = int(t)
wend
if multInv < 0 then multInv = multInv + b0
[endFun]
end function

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fn mod_inv(a: isize, module: isize) -> isize {
let mut mn = (module, a);
let mut xy = (0, 1);
while mn.1 != 0 {
xy = (xy.1, xy.0 - (mn.0 / mn.1) * xy.1);
mn = (mn.1, mn.0 % mn.1);
}
while xy.0 < 0 {
xy.0 += module;
}
xy.0
}
fn main() {
println!("{}", mod_inv(42, 2017))
}

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