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Task/Numerical-integration/00-TASK.txt
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Task/Numerical-integration/00-TASK.txt
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Write functions to calculate the definite integral of a function <big><big> {{math|1=''ƒ(x)''}} </big></big> using ''all'' five of the following methods:
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:* [[wp:Rectangle_method|rectangular]]
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:** left
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:** right
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:** midpoint
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:* [[wp:Trapezoidal_rule|trapezium]]
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:* [[wp:Simpson%27s_rule|Simpson's]]
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:** composite
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Your functions should take in the upper and lower bounds ({{math|''a''}} and {{math|''b''}}), and the number of approximations to make in that range ({{math|''n''}}).
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Assume that your example already has a function that gives values for <big> {{math|1=''ƒ(x)''}} </big>.
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Simpson's method is defined by the following pseudo-code:
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{| class="mw-collapsible mw-collapsed"
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|+ Pseudocode: Simpson's method, composite
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'''procedure''' quad_simpson_composite(f, a, b, n)
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h := (b - a) / n
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sum1 := f(a + h/2)
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sum2 := 0
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loop on i from 1 to (n - 1)
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sum1 := sum1 + f(a + h * i + h/2)
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sum2 := sum2 + f(a + h * i)
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''answer'' := (h / 6) * (f(a) + f(b) + 4*sum1 + 2*sum2)
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|}
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Demonstrate your function by showing the results for:
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* {{math|1=ƒ(x) = x<sup>3</sup>}}, where '''x''' is [0,1], with 100 approximations. The exact result is 0.25 (or 1/4)
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* {{math|1=ƒ(x) = 1/x}}, where '''x''' is [1,100], with 1,000 approximations. The exact result is 4.605170<sup>+</sup> (natural log of 100)
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* {{math|1=ƒ(x) = x}}, where '''x''' is [0,5000], with 5,000,000 approximations. The exact result is 12,500,000
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* {{math|1=ƒ(x) = x}}, where '''x''' is [0,6000], with 6,000,000 approximations. The exact result is 18,000,000
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<br/>
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;See also:
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* [[Active object]] for integrating a function of real time.
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* [[Special:PrefixIndex/Numerical integration]] for other integration methods.
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<br/>
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