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27
Task/Perfect-numbers/C/perfect-numbers-1.c
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Task/Perfect-numbers/C/perfect-numbers-1.c
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#include "stdio.h"
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#include "math.h"
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int perfect(int n) {
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int max = (int)sqrt((double)n) + 1;
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int tot = 1;
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int i;
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for (i = 2; i < max; i++)
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if ( (n % i) == 0 ) {
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tot += i;
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int q = n / i;
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if (q > i)
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tot += q;
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}
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return tot == n;
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}
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int main() {
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int n;
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for (n = 2; n < 33550337; n++)
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if (perfect(n))
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printf("%d\n", n);
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return 0;
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}
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Task/Perfect-numbers/C/perfect-numbers-2.c
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Task/Perfect-numbers/C/perfect-numbers-2.c
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int main()
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{
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int j;
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ulong fac[10000], n, sum;
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sieve();
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for (n = 2; n < 33550337; n++) {
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j = get_factors(n, fac) - 1;
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for (sum = 0; j && sum <= n; sum += fac[--j]);
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if (sum == n) printf("%lu\n", n);
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}
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return 0;
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}
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