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Ingy döt Net 2023-07-01 11:58:00 -04:00
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/*REXX program demonstrates a method of set consolidating using some sample sets. */
@.=; @.1 = '{A,B} {C,D}'
@.2 = "{A,B} {B,D}"
@.3 = '{A,B} {C,D} {D,B}'
@.4 = '{H,I,K} {A,B} {C,D} {D,B} {F,G,H}'
@.5 = '{snow,ice,slush,frost,fog} {icebergs,icecubes} {rain,fog,sleet}'
do j=1 while @.j\=='' /*traipse through each of sample sets. */
call SETconsolidate @.j /*have the function do the heavy work. */
end /*j*/
exit 0 /*stick a fork in it, we're all done. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
isIn: return wordpos(arg(1), arg(2))\==0 /*is (word) argument 1 in the set arg2?*/
/*──────────────────────────────────────────────────────────────────────────────────────*/
SETconsolidate: procedure; parse arg old; #= words(old); new=
say ' the old set=' space(old)
do k=1 for # /* [↓] change all commas to a blank. */
!.k= translate( word(old, k), , '},{') /*create a list of words (aka, a set).*/
end /*k*/ /* [↑] ··· and also remove the braces.*/
do until \changed; changed= 0 /*consolidate some sets (well, maybe).*/
do set=1 for #-1
do item=1 for words(!.set); x= word(!.set, item)
do other=set+1 to #
if isIn(x, !.other) then do; changed= 1 /*it's changed*/
!.set= !.set !.other; !.other=
iterate set
end
end /*other*/
end /*item */
end /*set */
end /*until ¬changed*/
do set=1 for #; $= /*elide dups*/
do items=1 for words(!.set); x= word(!.set, items)
if x==',' then iterate; if x=='' then leave
$= $ x /*build new.*/
do until \isIn(x, !.set); _= wordpos(x, !.set)
_= wordpos(x, !.set)
!.set= subword(!.set, 1, _-1) ',' subword(!.set, _+1) /*purify set*/
end /*until ¬isIn ··· */
end /*items*/
!.set= translate( strip($), ',', " ")
end /*set*/
do i=1 for #; if !.i=='' then iterate /*ignore any set that is a null set. */
new= space(new '{'!.i"}") /*prepend and append a set identifier. */
end /*i*/
say ' the new set=' new; say
return