Data commit

Task/Sorting-algorithms-Merge-sort/ActionScript/sorting-algorithms-merge-sort.as

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+function mergesort(a:Array)
+{
+	//Arrays of length 1 and 0 are always sorted
+	if(a.length <= 1) return a;
+	else
+	{
+		var middle:uint = a.length/2;
+		//split the array into two
+		var left:Array = new Array(middle);
+		var right:Array = new Array(a.length-middle);
+		var j:uint = 0, k:uint = 0;
+		//fill the left array
+		for(var i:uint = 0; i < middle; i++)
+			left[j++]=a[i];
+		//fill the right array
+		for(i = middle; i< a.length; i++)
+			right[k++]=a[i];
+		//sort the arrays
+		left = mergesort(left);
+		right = mergesort(right);
+		//If the last element of the left array is less than or equal to the first
+		//element of the right array, they are in order and don't need to be merged
+		if(left[left.length-1] <= right[0])
+			return left.concat(right);
+		a = merge(left, right);
+		return a;
+	}
+}
+
+function merge(left:Array, right:Array)
+{
+	var result:Array = new Array(left.length + right.length);
+	var j:uint = 0, k:uint = 0, m:uint = 0;
+	//merge the arrays in order
+	while(j < left.length && k < right.length)
+	{
+		if(left[j] <= right[k])
+			result[m++] = left[j++];
+		else
+			result[m++] = right[k++];
+	}
+	//If one of the arrays has remaining entries that haven't been merged, they
+	//will be greater than the rest of the numbers merged so far, so put them on the
+	//end of the array.
+	for(; j < left.length; j++)
+		result[m++] = left[j];
+	for(; k < right.length; k++)
+		result[m++] = right[k];
+	return result;
+}