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/*REXX program demonstrates removal of 1st/last/1st-and-last characters from a string.*/
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@ = 'abcdefghijk'
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say ' the original string =' @
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say 'string first character removed =' substr(@, 2)
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say 'string last character removed =' left(@, length(@) -1)
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say 'string first & last character removed =' substr(@, 2, length(@) -2)
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/*stick a fork in it, we're all done. */
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/* ╔═══════════════════════════════════════════════════════════════════════════════╗
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║ However, the original string may be null or exactly one byte in length which ║
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║ will cause the BIFs to fail because of either zero or a negative length. ║
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╚═══════════════════════════════════════════════════════════════════════════════╝ */
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/*REXX program demonstrates removal of 1st/last/1st-and-last characters from a string.*/
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@ = 'abcdefghijk'
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say ' the original string =' @
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say 'string first character removed =' substr(@, 2)
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say 'string last character removed =' left(@, max(0, length(@) -1))
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say 'string first & last character removed =' substr(@, 2, max(0, length(@) -2))
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exit /*stick a fork in it, we're all done. */
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/* [↓] an easier to read version using a length variable.*/
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@ = 'abcdefghijk'
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L=length(@)
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say ' the original string =' @
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say 'string first character removed =' substr(@, 2)
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say 'string last character removed =' left(@, max(0, L-1) )
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say 'string first & last character removed =' substr(@, 2, max(0, L-2) )
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/*REXX program demonstrates removal of 1st/last/1st-and-last characters from a string.*/
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@ = 'abcdefghijk'
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say ' the original string =' @
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parse var @ 2 z
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say 'string first character removed =' z
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m=length(@) - 1
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parse var @ z +(m)
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say 'string last character removed =' z
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n=length(@) - 2
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parse var @ 2 z +(n)
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if n==0 then z= /*handle special case of a length of 2.*/
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say 'string first & last character removed =' z /*stick a fork in it, we're all done. */
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