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Ingy döt Net 2023-07-01 11:58:00 -04:00
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/*REXX program generates N decks of numbered cards and finds the maximum "swops". */
parse arg things .; if things=='' then things= 10
do n=1 for things; #= decks(n, n) /*create a (things) number of "decks". */
mx= n\==1 /*handle the case of a one-card deck.*/
do i=1 for #; p= swops(!.i) /*compute the SWOPS for this iteration.*/
if p>mx then mx= p /*This a new maximum? Use a new max. */
end /*i*/
say ' maximum swops for a deck of' right(n,2) ' cards is' right(mx,4)
end /*n*/
exit 0 /*stick a fork in it, we're all done. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
decks: procedure expose !.; parse arg x,y,,$ @. /* X things taken Y at a time. */
#= 0; call .decks 1 /* [↑] initialize $ & @. to null.*/
return # /*return number of permutations (decks)*/
/*──────────────────────────────────────────────────────────────────────────────────────*/
.decks: procedure expose !. @. x y $ #; parse arg ?
if ?>y then do; _=@.1; do j=2 for y-1; _= _ @.j; end /*j*/; #= #+1; !.#=_
end
else do; qm= ? - 1
if ?==1 then qs= 2 /*don't use 1-swops that start with 1 */
else if @.1==? then qs=2 /*skip the 1-swops: 3 x 1 x ···*/
else qs=1
do q=qs to x /*build the permutations recursively. */
do k=1 for qm; if @.k==q then iterate q
end /*k*/
@.?=q ; call .decks ? + 1
end /*q*/
end
return
/*──────────────────────────────────────────────────────────────────────────────────────*/
swops: parse arg z; do u=1; parse var z t .; if \datatype(t, 'W') then t= x2d(t)
if word(z, t)==1 then return u /*found unity at T. */
do h=10 to things; if pos(h, z)==0 then iterate
z= changestr(h, z, d2x(h) ) /* [↑] any H's in Z?*/
end /*h*/
z= reverse( subword(z, 1, t) ) subword(z, t + 1)
end /*u*/