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Ingy döt Net 2023-07-01 11:58:00 -04:00
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---
category:
- CHR
from: http://rosettacode.org/wiki/Twelve_statements
note: Puzzles

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This puzzle is borrowed from   [http://math-frolic.blogspot.co.uk/2012/08/mind-wrenching.html math-frolic.blogspot].
Given the following twelve statements, which of them are true?
<pre>
1. This is a numbered list of twelve statements.
2. Exactly 3 of the last 6 statements are true.
3. Exactly 2 of the even-numbered statements are true.
4. If statement 5 is true, then statements 6 and 7 are both true.
5. The 3 preceding statements are all false.
6. Exactly 4 of the odd-numbered statements are true.
7. Either statement 2 or 3 is true, but not both.
8. If statement 7 is true, then 5 and 6 are both true.
9. Exactly 3 of the first 6 statements are true.
10. The next two statements are both true.
11. Exactly 1 of statements 7, 8 and 9 are true.
12. Exactly 4 of the preceding statements are true.
</pre>
;Task:
When you get tired of trying to figure it out in your head,
write a program to solve it, and print the correct answer or answers.
;Extra credit:
Print out a table of near misses, that is, solutions that are contradicted by only a single statement.
<br><br>

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[([Int] -> Bool)] predicates
predicates [+]= st -> st.len == 12
predicates [+]= st -> sum(st[(len)-6 ..]) == 3
predicates [+]= st -> sum(st[(1..).step(2)]) == 2
predicates [+]= st -> I st[4] {(st[5] [&] st[6])} E 1
predicates [+]= st -> sum(st[1.<4]) == 0
predicates [+]= st -> sum(st[(0..).step(2)]) == 4
predicates [+]= st -> sum(st[1.<3]) == 1
predicates [+]= st -> I st[6] {(st[4] [&] st[5])} E 1
predicates [+]= st -> sum(st[0.<6]) == 3
predicates [+]= st -> (st[10] [&] st[11])
predicates [+]= st -> sum(st[6.<9]) == 1
predicates [+]= st -> sum(st[0.<11]) == 4
F to_str(b)
R (0.<12).filter(i -> @b[i]).map(i -> i + 1).join( )
print(Exact hits:)
L(n) 0 .< (1 << 12)
V bools = [0] * 12
L(i) 12
I n [&] (1 << (11 - i)) != 0
bools[i] = 1
L(predicate) predicates
I Int(predicate(bools)) != bools[L.index]
L.break
L.was_no_break
print( to_str(bools))
print("\nNear misses:")
L(n) 0 .< (1 << 12)
V bools = [0] * 12
L(i) 12
I n [&] (1 << (11 - i)) != 0
bools[i] = 1
V count = 0
L(predicate) predicates
I Int(predicate(bools)) == bools[L.index]
count++
I count == 11
L(predicate) predicates
V i = L.index
I Int(predicate(bools)) != bools[i]
print(f: (Fails at statement {i + 1:2}) {to_str(bools)})
L.break

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begin
% we have 12 statements to determine the truth/falsehood of (see task) %
logical array stmt, expected( 1 :: 12 );
% logical (boolean) to integer utility procedure %
integer procedure toInteger ( logical value v ) ; if v then 1 else 0;
% procedure to determine whether the statements are true or not %
procedure findExpectedValues ;
begin
expected( 1 ) := true;
expected( 2 ) := 3 = ( toInteger( stmt( 7 ) ) + toInteger( stmt( 8 ) )
+ toInteger( stmt( 9 ) ) + toInteger( stmt( 10 ) )
+ toInteger( stmt( 11 ) ) + toInteger( stmt( 12 ) )
);
expected( 3 ) := 2 = ( toInteger( stmt( 2 ) ) + toInteger( stmt( 4 ) )
+ toInteger( stmt( 6 ) ) + toInteger( stmt( 8 ) )
+ toInteger( stmt( 10 ) ) + toInteger( stmt( 12 ) )
);
expected( 4 ) := ( not stmt( 5 ) ) or ( stmt( 6 ) and stmt( 7 ) );
expected( 5 ) := not ( stmt( 2 ) or stmt( 3 ) or stmt( 4 ) );
expected( 6 ) := 4 = ( toInteger( stmt( 1 ) ) + toInteger( stmt( 3 ) )
+ toInteger( stmt( 5 ) ) + toInteger( stmt( 7 ) )
+ toInteger( stmt( 9 ) ) + toInteger( stmt( 11 ) )
);
expected( 7 ) := stmt( 2 ) not = stmt( 3 );
expected( 8 ) := ( not stmt( 7 ) ) or ( stmt( 5 ) and stmt( 6 ) );
expected( 9 ) := 3 = ( toInteger( stmt( 1 ) ) + toInteger( stmt( 2 ) )
+ toInteger( stmt( 3 ) ) + toInteger( stmt( 4 ) )
+ toInteger( stmt( 5 ) ) + toInteger( stmt( 6 ) )
);
expected( 10 ) := stmt( 11 ) and stmt( 12 );
expected( 11 ) := 1 = ( toInteger( stmt( 7 ) )
+ toInteger( stmt( 8 ) )
+ toInteger( stmt( 9 ) )
);
expected( 12 ) := 4 = ( toInteger( stmt( 1 ) ) + toInteger( stmt( 2 ) )
+ toInteger( stmt( 3 ) ) + toInteger( stmt( 4 ) )
+ toInteger( stmt( 5 ) ) + toInteger( stmt( 6 ) )
+ toInteger( stmt( 7 ) ) + toInteger( stmt( 8 ) )
+ toInteger( stmt( 9 ) ) + toInteger( stmt( 10 ) )
+ toInteger( stmt( 11 ) )
);
end expected ;
% clearly, statement 1 is true, however to enumerate the near %
% solutions, we need to consider "solutions" where statement 1 is false %
% we iterate through the possibilities for the statements, %
% looking for a non-contradictory set of values %
% we print the solutions with allowedContradictions contradictions %
procedure printSolutions ( integer value allowedContradictions
; string(60) value heading
) ;
begin
logical array wrong( 1 :: 12 );
write( heading );
write( " 1 2 3 4 5 6 7 8 9 10 11 12" );
write( " ====================================" );
% there are 12 statements, so we have 2^12 possible combinations %
for solution := 1 until 4096 do begin
integer n, incorrect;
% convert the number to the set of true/false values %
n := solution;
for dPos := 1 until 12 do begin
stmt( dPos ) := odd( n );
n := n div 2;
end for_dPos ;
% get the expected values of the statements, based on the %
% suggested values %
findExpectedValues;
% count the contradictions, if we have the required number, %
% print the solution %
incorrect := 0;
for dPos := 1 until 12 do begin
wrong( dPos ) := expected( dPos ) not = stmt( dPos );
incorrect := incorrect + toInteger( wrong( dPos ) );
end for_dPos ;
if incorrect = allowedContradictions then begin
% have a solution %
write( " " );
for s := 1 until 12 do writeon( s_w := 0
, " "
, if stmt( s ) then "T" else "-"
, if wrong( s ) then "*" else " "
);
end ;
end for_solution ;
end printSolutions ;
% find complete solutions %
printSolutions( 0, "Solutions" );
% find near solutions %
printSolutions( 1, "Near solutions (incorrect values marked ""*"")" );
end.

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with Ada.Text_IO, Logic;
procedure Twelve_Statements is
package L is new Logic(Number_Of_Statements => 12); use L;
-- formally define the 12 statements as expression function predicates
function P01(T: Table) return Boolean is (T'Length = 12); -- list of 12 statements
function P02(T: Table) return Boolean is (Sum(T(7 .. 12)) = 3); -- three of last six
function P03(T: Table) return Boolean is (Sum(Half(T, Even)) = 2); -- two of the even
function P04(T: Table) return Boolean is (if T(5) then T(6) and T(7)); -- if 5 is true, then ...
function P05(T: Table) return Boolean is
( (not T(2)) and (not T(3)) and (not T(4)) ); -- none of preceding three
function P06(T: Table) return Boolean is (Sum(Half(T, Odd)) = 4); -- four of the odd
function P07(T: Table) return Boolean is (T(2) xor T(3)); -- either 2 or 3, not both
function P08(T: Table) return Boolean is (if T(7) then T(5) and T(6)); -- if 7 is true, then ...
function P09(T: Table) return Boolean is (Sum(T(1 .. 6)) = 3); -- three of first six
function P10(T: Table) return Boolean is (T(11) and T(12)); -- next two
function P11(T: Table) return Boolean is (Sum(T(7..9)) = 1); -- one of 7, 8, 9
function P12(T: Table) return Boolean is (Sum(T(1 .. 11)) = 4); -- four of the preding
-- define a global list of statements
Statement_List: constant Statements :=
(P01'Access, P02'Access, P03'Access, P04'Access, P05'Access, P06'Access,
P07'Access, P08'Access, P09'Access, P10'Access, P11'Access, P12'Access);
-- try out all 2^12 possible choices for the table
procedure Try(T: Table; Fail: Natural; Idx: Indices'Base := Indices'First) is
procedure Print_Table(T: Table) is
use Ada.Text_IO;
begin
Put(" ");
if Fail > 0 then
Put("(wrong at");
for J in T'Range loop
if Statement_List(J)(T) /= T(J) then
Put(Integer'Image(J) & (if J < 10 then ") " else ") "));
end if;
end loop;
end if;
if T = (1..12 => False) then
Put_Line("All false!");
else
Put("True are");
for J in T'Range loop
if T(J) then
Put(Integer'Image(J));
end if;
end loop;
New_Line;
end if;
end Print_Table;
Wrong_Entries: Natural := 0;
begin
if Idx <= T'Last then
Try(T(T'First .. Idx-1) & False & T(Idx+1 .. T'Last), Fail, Idx+1);
Try(T(T'First .. Idx-1) & True & T(Idx+1 .. T'Last), Fail, Idx+1);
else -- now Index > T'Last and we have one of the 2^12 choices to test
for J in T'Range loop
if Statement_List(J)(T) /= T(J) then
Wrong_Entries := Wrong_Entries + 1;
end if;
end loop;
if Wrong_Entries = Fail then
Print_Table(T);
end if;
end if;
end Try;
begin
Ada.Text_IO.Put_Line("Exact hits:");
Try(T => (1..12 => False), Fail => 0);
Ada.Text_IO.New_Line;
Ada.Text_IO.Put_Line("Near Misses:");
Try(T => (1..12 => False), Fail => 1);
end Twelve_Statements;

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generic
Number_Of_Statements: Positive;
package Logic is
--types
subtype Indices is Natural range 1 .. Number_Of_Statements;
type Table is array(Indices range <>) of Boolean;
type Predicate is access function(T: Table) return Boolean;
type Statements is array(Indices) of Predicate;
type Even_Odd is (Even, Odd);
-- convenience functions
function Sum(T: Table) return Natural;
function Half(T: Table; Which: Even_Odd) return Table;
end Logic;

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package body Logic is
function Sum(T: Table) return Natural is
Result: Natural := 0;
begin
for I in T'Range loop
if T(I) then
Result := Result + 1;
end if;
end loop;
return Result;
end Sum;
function Half(T: Table; Which: Even_Odd) return Table is
Result: Table(T'Range);
Last: Natural := Result'First - 1;
begin
for I in T'Range loop
if I mod 2 = (if (Which=Odd) then 1 else 0) then
Last := Last+1;
Result(Last) := T(I);
end if;
end loop;
return Result(Result'First .. Last);
end Half;
end Logic;

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on twelveStatements()
set statements to " 1. This is a numbered list of twelve statements.
2. Exactly 3 of the last 6 statements are true.
3. Exactly 2 of the even-numbered statements are true.
4. If statement 5 is true, then statements 6 and 7 are both true.
5. The 3 preceding statements are all false.
6. Exactly 4 of the odd-numbered statements are true.
7. Either statement 2 or 3 is true, but not both.
8. If statement 7 is true, then 5 and 6 are both true.
9. Exactly 3 of the first 6 statements are true.
10. The next two statements are both true.
11. Exactly 1 of statements 7, 8 and 9 are true.
12. Exactly 4 of the preceding statements are true."
script o
property posits : {}
property upshots : missing value
on countTrues(indexList)
set sum to 0
repeat with i in indexList
if (my posits's item i) then set sum to sum + 1
end repeat
return sum
end countTrues
end script
-- While setting up, test statement 1, whose truth isn't about the others' truths.
set statements to statements's paragraphs
set nStatements to (count statements)
set statement1Truth to (nStatements = 12)
repeat with stmt from 1 to nStatements
set end of o's o's posits to false
tell (statements's item stmt's words) to set statement1Truth to ¬
((statement1Truth) and ((count) > 1) and (beginning = stmt as text))
end repeat
set output to {}
set firstIteration to true
repeat (2 ^ nStatements) times
-- Postulate answer:
if (firstIteration) then
set firstIteration to false
else -- "Increment" the 'posits' boolean array binarily.
repeat with stmt from 1 to nStatements
set o's posits's item stmt to (not (o's posits's item stmt))
if (result) then exit repeat -- No carry.
end repeat
end if
-- Test consistency:
tell o's posits to set o's upshots to {statement1Truth, ¬
(o's countTrues({7, 8, 9, 10, 11, 12}) = 3), ¬
(o's countTrues({2, 4, 6, 8, 10, 12}) = 2), ¬
((not (item 5)) or ((item 6) and (item 7))), ¬
(not ((item 2) or (item 3) or (item 4))), ¬
(o's countTrues({1, 3, 5, 7, 9, 11}) = 4), ¬
((item 2) (item 3)), ¬
((not (item 7)) or ((item 5) and (item 6))), ¬
(o's countTrues({1, 2, 3, 4, 5, 6}) = 3), ¬
((item 11) and (item 12)), ¬
(o's countTrues({7, 8, 9}) = 1), ¬
(o's countTrues({1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11}) = 4)}
set nMatches to 0
repeat with stmt from 1 to nStatements
if ((o's posits's item stmt) = (o's upshots's item stmt)) then set nMatches to nMatches + 1
end repeat
if (nMatches > nStatements - 2) then
set statementsPositedTrue to {}
repeat with stmt from 1 to nStatements
set thisPosit to o's posits's item stmt
if (thisPosit) then set end of statementsPositedTrue to stmt
if ((thisPosit) (o's upshots's item stmt)) then set failure to stmt
end repeat
set statementsPositedTrue's last item to "and " & statementsPositedTrue's end
if ((count statementsPositedTrue) > 2) then
set statementsPositedTrue to join(statementsPositedTrue, ", ")
else
set statementsPositedTrue to join(statementsPositedTrue, space)
end if
if (nMatches = nStatements) then
set output's end to "SOLUTION: statements " & statementsPositedTrue & " are true."
else
set output's end to "Near miss when statements " & statementsPositedTrue & ¬
" are posited true: posit for statement " & failure & " fails."
end if
end if
end repeat
return join(output, linefeed)
end twelveStatements
on join(lst, delim)
set astid to AppleScript's text item delimiters
set AppleScript's text item delimiters to delim
set txt to lst as text
set AppleScript's text item delimiters to astid
return txt
end join
twelveStatements()

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"Near miss when statements 1 and 4 are posited true: posit for statement 8 fails.
Near miss when statements 1 and 5 are posited true: posit for statement 8 fails.
Near miss when statements 1, 5, and 8 are posited true: posit for statement 11 fails.
Near miss when statements 1, 3, 4, 6, 7, and 9 are posited true: posit for statement 9 fails.
Near miss when statements 1, 3, 4, 8, and 9 are posited true: posit for statement 7 fails.
Near miss when statements 1, 4, 6, 8, and 9 are posited true: posit for statement 6 fails.
Near miss when statements 1, 2, 4, 7, 8, and 9 are posited true: posit for statement 8 fails.
Near miss when statements 1, 2, 4, 7, 9, and 10 are posited true: posit for statement 10 fails.
SOLUTION: statements 1, 3, 4, 6, 7, and 11 are true.
Near miss when statements 5, 8, and 11 are posited true: posit for statement 1 fails.
Near miss when statements 1, 5, 8, and 11 are posited true: posit for statement 12 fails.
Near miss when statements 1, 5, 6, 9, and 11 are posited true: posit for statement 8 fails.
Near miss when statements 1, 2, 4, 7, 9, and 12 are posited true: posit for statement 12 fails.
Near miss when statements 4, 8, 10, 11, and 12 are posited true: posit for statement 1 fails.
Near miss when statements 1, 4, 8, 10, 11, and 12 are posited true: posit for statement 12 fails.
Near miss when statements 5, 8, 10, 11, and 12 are posited true: posit for statement 1 fails.
Near miss when statements 1, 5, 8, 10, 11, and 12 are posited true: posit for statement 12 fails."

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; Note: the original puzzle provides 12 statements and starts with
; "Given the following twelve statements...", so the first statement
; should ignore the F1 flag and always be true (see "( N == 1 )").
S := 12 ; number of statements
Output := ""
Loop, % 2**S {
;;If !Mod(A_Index,100) ;; optional 'if' to show the loop progress
;; ToolTip, Index: %A_Index%
SetFlags(A_Index-1), Current := "", Count := 0
Loop, %S%
R := TestStatement(A_Index), Current .= " " R, Count += (R == F%A_Index%)
If ( Count >= S-1 )
Output .= Count " ->" Current "`n"
If ( Count = S )
Solution := "`nSolution = " Current
}
ToolTip
MsgBox, % Output . Solution
Return
;-------------------------------------------------------------------------------------
SetFlags(D) {
Local I
Loop, %S%
I := S-A_Index+1 , F%I% := (D >> (S-A_Index)) & 1
}
;-------------------------------------------------------------------------------------
TestStatement(N) {
Local I, C := 0
If ( N == 1 ) ; This is a numbered list of twelve statements.
Return ( S == 12 ) ; should always be true
If ( N == 2 ) { ; Exactly 3 of the last 6 statements are true.
Loop, 6
I := S-A_Index+1 , C += F%I%
Return ( C == 3 )
}
If ( N == 3 ) { ; Exactly 2 of the even-numbered statements are true.
Loop, %S%
C += ( !Mod(A_Index,2) & F%A_Index% )
Return ( C == 2 )
}
If ( N == 4 ) ; If statement 5 is true, then statements 6 and 7 are both true.
Return ( F5 ? F6 & F7 : 1 )
If ( N == 5 ) { ; The 3 preceding statements are all false.
Loop, 3
I := N-A_Index , C += F%I%
Return ( C == 0 )
}
If ( N == 6 ) { ; Exactly 4 of the odd-numbered statements are true.
Loop, %S%
C += ( !!Mod(A_Index,2) & F%A_Index% )
Return ( C == 4 )
}
If ( N == 7 ) ; Either statement 2 or 3 is true, but not both.
Return ( F2 ^ F3 )
If ( N == 8 ) ; If statement 7 is true, then 5 and 6 are both true.
Return ( F7 ? F5 & F6 : 1 )
If ( N == 9 ) { ; Exactly 3 of the first 6 statements are true.
Loop, 6
C += F%A_Index%
Return ( C == 3 )
}
If ( N == 10 ) ; The next two statements are both true.
Return ( F11 & F12 )
If ( N == 11 ) ; Exactly 1 of statements 7, 8 and 9 are true
Return ( F7+F8+F9 == 1 )
If ( N == 12 ) { ; Exactly 4 of the preceding statements are true
Loop, % N-1
C += F%A_Index%
Return ( C == 4 )
}
}

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nStatements% = 12
DIM Pass%(nStatements%), T%(nStatements%)
FOR try% = 0 TO 2^nStatements%-1
REM Postulate answer:
FOR stmt% = 1 TO 12
T%(stmt%) = (try% AND 2^(stmt%-1)) <> 0
NEXT
REM Test consistency:
Pass%(1) = T%(1) = (nStatements% = 12)
Pass%(2) = T%(2) = ((T%(7)+T%(8)+T%(9)+T%(10)+T%(11)+T%(12)) = -3)
Pass%(3) = T%(3) = ((T%(2)+T%(4)+T%(6)+T%(8)+T%(10)+T%(12)) = -2)
Pass%(4) = T%(4) = ((NOT T%(5) OR (T%(6) AND T%(7))))
Pass%(5) = T%(5) = (NOT T%(2) AND NOT T%(3) AND NOT T%(4))
Pass%(6) = T%(6) = ((T%(1)+T%(3)+T%(5)+T%(7)+T%(9)+T%(11)) = -4)
Pass%(7) = T%(7) = ((T%(2) EOR T%(3)))
Pass%(8) = T%(8) = ((NOT T%(7) OR (T%(5) AND T%(6))))
Pass%(9) = T%(9) = ((T%(1)+T%(2)+T%(3)+T%(4)+T%(5)+T%(6)) = -3)
Pass%(10) = T%(10) = (T%(11) AND T%(12))
Pass%(11) = T%(11) = ((T%(7)+T%(8)+T%(9)) = -1)
Pass%(12) = T%(12) = ((T%(1)+T%(2)+T%(3)+T%(4)+T%(5)+T%(6) + \
\ T%(7)+T%(8)+T%(9)+T%(10)+T%(11)) = -4)
CASE SUM(Pass%()) OF
WHEN -11:
PRINT "Near miss with statements ";
FOR stmt% = 1 TO 12
IF T%(stmt%) PRINT ; stmt% " ";
IF NOT Pass%(stmt%) miss% = stmt%
NEXT
PRINT "true (failed " ;miss% ")."
WHEN -12:
PRINT "Solution! with statements ";
FOR stmt% = 1 TO 12
IF T%(stmt%) PRINT ; stmt% " ";
NEXT
PRINT "true."
ENDCASE
NEXT try%
END

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(
( number
= n done ntest oldFT
. !arg:(?done.(=?ntest).?oldFT)
& 0:?n
& ( !done
: ?
( !ntest
. !oldFT&1+!n:?n&~
)
?
| !n
)
)
& ( STATEMENTS
= ( (1."This is a numbered list of twelve statements.")
. 1
. (
= n nr done toDo
. !arg:(?done.?toDo)
& 0:?n
& whl
' ( !done:(?nr.?) ?done
& 1+!n:!nr:?n
)
& whl
' ( !toDo:((?nr.?).?) ?toDo
& 1+!n:!nr:?n
)
& (!n:12&true|false)
)
)
( (2."Exactly 3 of the last 6 statements are true.")
. end
. (
= done toDo lastSix
. !arg:(?done.?toDo)
& !done:? [-7 ?lastSix
& ( number$(!lastSix.(=?).true):3
& true
| false
)
)
)
( (3."Exactly 2 of the even-numbered statements are true.")
. end
. (
= done toDo ii
. !arg:(?done.?toDo)
& ( number
$ ( !done
. (=?ii&!ii*1/2:~/)
. true
)
: 2
& true
| false
)
)
)
( (4."If statement 5 is true, then statements 6 and 7 are both true.")
. 7
. (
= done toDo
. !arg:(?done.?toDo)
& ( !done
: ( ? (5.false) ?
| ? (6.true) ?
: ? (7.true) ?
)
& true
| false
)
)
)
( (5."The 3 preceding statements are all false.")
. 5
. (
= done toDo
. !arg:(?done.?toDo)
& ( !done
: ?
(?.false)
(?.false)
(?.false)
(?.?)
& true
| false
)
)
)
( (6."Exactly 4 of the odd-numbered statements are true.")
. end
. (
= done toDo i
. !arg:(?done.?toDo)
& ( number
$ ( !done
. (=?i&!i*1/2:/)
. true
)
: 4
& true
| false
)
)
)
( (7."Either statement 2 or 3 is true, but not both.")
. 7
. (
= done toDo
. !arg:(?done.?toDo)
& ( number
$ (!done.(=2|3).true)
: 1
& true
| false
)
)
)
( (8."If statement 7 is true, then 5 and 6 are both true.")
. 8
. (
= done toDo
. !arg:(?done.?toDo)
& ( !done
: ( ? (7.false) ?
| ? (5.true) ?
: ? (6.true) ?
)
& true
| false
)
)
)
( (9."Exactly 3 of the first 6 statements are true.")
. 9
. (
= done toDo firstSix
. !arg:(?done.?toDo)
& !done:?firstSix [6 ?
& ( number$(!firstSix.(=?).true):3
& true
| false
)
)
)
( (10."The next two statements are both true.")
. 12
. (
= done toDo
. !arg:(?done.?toDo)
& ( !done:? (?.true) (?.true)
& true
| false
)
)
)
( (11."Exactly 1 of statements 7, 8 and 9 are true.")
. 11
. (
= done toDo
. !arg:(?done.?toDo)
& ( number
$ ( !done
. (=7|8|9)
. true
)
: 1
& true
| false
)
)
)
( (12."Exactly 4 of the preceding statements are true.")
. 12
. (
= done toDo preceding
. !arg:(?done.?toDo)
& !done:?preceding (?.?)
& ( number$(!preceding.(=?).true):4
& true
| false
)
)
)
)
& ( TestTruth
= done toDo postponedTests testToBePostponed
, n when test FT oldFT A Z text
, postponedTest testNow
. !arg:(?done.?toDo.?postponedTests)
& ( !toDo:
& "We have come to the end of the list of tests.
Perform any tests that had to be postponed until now."
& whl
' ( !postponedTests
: (?.?oldFT.(=?postponedTest)) ?A
& postponedTest$(!done.):!oldFT
& !A:?postponedTests
)
& !postponedTests:
& out$("Solution:" !done)
& ~
| !toDo
: ((?n.?text).?when.(=?test)) ?toDo
& "'false' and 'true' are just two symbols, not 'boolean values'.
You can choose other symbols if you like.
The program first guesses the first symbol and assigns it to the variable FT.
After backtracking, the second symbol is guessed and assigned to FT.
This is done for each statement."
& false true
: ?
%@?FT
( ?
& 1+!guesses:?guesses
& (!n.!FT):?testNow
& "Do all tests that had to be postponed until now, unless one of those tests
fails. Remove the successful tests from the list of postponed tests."
& whl
' ( !postponedTests
: ?A
(!n.?oldFT.(=?postponedTest))
?Z
& postponedTest$(!done !testNow.!toDo)
: !oldFT
& !A !Z:?postponedTests
)
& "Check that all tests that had to be postponed until now are removed from
the list of postponed tests. Only then go on with looking at testing
the current statement. Backtrack if a test failed."
& !postponedTests:~(? (!n.?) ?)
& ( !when:>!n
& "The current statement cannot be tested right now. Postpone it to
the earliest coming statement where the current statement can be
tested.
(The earliest statement, denoted by 'when', is computed manually.)"
& (!when.!FT.'$test):?testToBePostponed
| "No need to postpone. Test the current statement now."
& :?testToBePostponed
& "If the test fails, backtrack. If it succeeds, go on to the next
statement."
& test$(!done !testNow.!toDo):!FT
)
& "So far so good. Test the next statements. (recursively)"
& TestTruth
$ ( !done !testNow
. !toDo
. !testToBePostponed !postponedTests
)
)
)
)
& 0:?guesses
& TestTruth$(.!STATEMENTS.)
| out
$ ( str
$ ( "That's it. I made "
!guesses
" true/false guesses in all. (A brute force method needs 2^12="
2^12
" guesses."
)
)
);

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#include <iostream>
#include <vector>
#include <string>
#include <cmath>
using namespace std;
// convert int (0 or 1) to string (F or T)
inline
string str(int n)
{
return n ? "T": "F";
}
int main(void)
{
int solution_list_number = 1;
vector<string> st;
st = {
" 1. This is a numbered list of twelve statements.",
" 2. Exactly 3 of the last 6 statements are true.",
" 3. Exactly 2 of the even-numbered statements are true.",
" 4. If statement 5 is true, then statements 6 and 7 are both true.",
" 5. The 3 preceding statements are all false.",
" 6. Exactly 4 of the odd-numbered statements are true.",
" 7. Either statement 2 or 3 is true, but not both.",
" 8. If statement 7 is true, then 5 and 6 are both true.",
" 9. Exactly 3 of the first 6 statements are true.",
" 10. The next two statements are both true.",
" 11. Exactly 1 of statements 7, 8 and 9 are true.",
" 12. Exactly 4 of the preceding statements are true."
}; // Good solution is: 1 3 4 6 7 11 are true
int n = 12; // Number of statements.
int nTemp = (int)pow(2, n); // Number of solutions to check.
for (int counter = 0; counter < nTemp; counter++)
{
vector<int> s;
for (int k = 0; k < n; k++)
{
s.push_back((counter >> k) & 0x1);
}
vector<int> test(12);
int sum = 0;
// check each of the nTemp solutions for match.
// 1. This is a numbered list of twelve statements.
test[0] = s[0];
// 2. Exactly 3 of the last 6 statements are true.
sum = s[6]+ s[7]+s[8]+s[9]+s[10]+s[11];
test[1] = ((sum == 3) == s[1]);
// 3. Exactly 2 of the even-numbered statements are true.
sum = s[1]+s[3]+s[5]+s[7]+s[9]+s[11];
test[2] = ((sum == 2) == s[2]);
// 4. If statement 5 is true, then statements 6 and 7 are both true.
test[3] = ((s[4] ? (s[5] && s[6]) : true) == s[3]);
// 5. The 3 preceding statements are all false.
test[4] = (((s[1] + s[2] + s[3]) == 0) == s[4]);
// 6. Exactly 4 of the odd-numbered statements are true.
sum = s[0] + s[2] + s[4] + s[6] + s[8] + s[10];
test[5] = ((sum == 4) == s[5]);
// 7. Either statement 2 or 3 is true, but not both.
test[6] = (((s[1] + s[2]) == 1) == s[6]);
// 8. If statement 7 is true, then 5 and 6 are both true.
test[7] = ((s[6] ? (s[4] && s[5]) : true) == s[7]);
// 9. Exactly 3 of the first 6 statements are true.
sum = s[0]+s[1]+s[2]+s[3]+s[4]+s[5];
test[8] = ((sum == 3) == s[8]);
// 10. The next two statements are both true.
test[9] = ((s[10] && s[11]) == s[9]);
// 11. Exactly 1 of statements 7, 8 and 9 are true.
sum = s[6]+ s[7] + s[8];
test[10] = ((sum == 1) == s[10]);
// 12. Exactly 4 of the preceding statements are true.
sum = s[0]+s[1]+s[2]+s[3]+s[4]+s[5]+s[6]+s[7]+s[8]+s[9]+s[10];
test[11] = ((sum == 4) == s[11]);
// Check test results and print solution if 11 or 12 are true
int resultsTrue = 0;
for(unsigned int i = 0; i < test.size(); i++){
resultsTrue += test[i];
}
if(resultsTrue == 11 || resultsTrue == 12){
cout << solution_list_number++ << ". " ;
string output = "1:"+str(s[0])+" 2:"+str(s[1])+" 3:"+str(s[2])
+" 4:"+str(s[3])+" 5:"+str(s[4])+" 6:"+ str(s[5])
+" 7:"+str(s[6])+" 8:"+str(s[7])+" 9:"+str(s[8])
+" 10:"+str(s[9])+" 11:"+str(s[10])+" 12:"+ str(s[11]);
if (resultsTrue == 12) {
cout << "Full Match, good solution!" << endl;
cout << "\t" << output << endl;
}
else if(resultsTrue == 11){
int i;
for(i = 0; i < 12; i++){
if(test[i] == 0){
break;
}
}
cout << "Missed by one statement: " << st[i] << endl;
cout << "\t" << output << endl;
}
}
}
}

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using System;
using System.Collections.Generic;
using System.Linq;
public static class TwelveStatements
{
public static void Main() {
Func<Statements, bool>[] checks = {
st => st[1],
st => st[2] == (7.To(12).Count(i => st[i]) == 3),
st => st[3] == (2.To(12, by: 2).Count(i => st[i]) == 2),
st => st[4] == st[5].Implies(st[6] && st[7]),
st => st[5] == (!st[2] && !st[3] && !st[4]),
st => st[6] == (1.To(12, by: 2).Count(i => st[i]) == 4),
st => st[7] == (st[2] != st[3]),
st => st[8] == st[7].Implies(st[5] && st[6]),
st => st[9] == (1.To(6).Count(i => st[i]) == 3),
st => st[10] == (st[11] && st[12]),
st => st[11] == (7.To(9).Count(i => st[i]) == 1),
st => st[12] == (1.To(11).Count(i => st[i]) == 4)
};
for (Statements statements = new Statements(0); statements.Value < 4096; statements++) {
int count = 0;
int falseIndex = 0;
for (int i = 0; i < checks.Length; i++) {
if (checks[i](statements)) count++;
else falseIndex = i;
}
if (count == 0) Console.WriteLine($"{"All wrong:", -13}{statements}");
else if (count == 11) Console.WriteLine($"{$"Wrong at {falseIndex + 1}:", -13}{statements}");
else if (count == 12) Console.WriteLine($"{"All correct:", -13}{statements}");
}
}
struct Statements
{
public Statements(int value) : this() { Value = value; }
public int Value { get; }
public bool this[int index] => (Value & (1 << index - 1)) != 0;
public static Statements operator ++(Statements statements) => new Statements(statements.Value + 1);
public override string ToString() {
Statements copy = this; //Cannot access 'this' in anonymous method...
return string.Join(" ", from i in 1.To(12) select copy[i] ? "T" : "F");
}
}
//Extension methods
static bool Implies(this bool x, bool y) => !x || y;
static IEnumerable<int> To(this int start, int end, int by = 1) {
while (start <= end) {
yield return start;
start += by;
}
}
}

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(use '[clojure.math.combinatorics]
(defn xor? [& args]
(odd? (count (filter identity args))))
(defn twelve-statements []
(for [[a b c d e f g h i j k l] (selections [true false] 12)
:when (true? a)
:when (if (= 3 (count (filter true? [g h i j k l]))) (true? b) (false? b))
:when (if (= 2 (count (filter true? [b d f h j l]))) (true? c) (false? c))
:when (if (or (false? e) (every? true? [e f g])) (true? d) (false? d))
:when (if (every? false? [b c d]) (true? e) (false? e))
:when (if (= 4 (count (filter true? [a c e g i k]))) (true? f) (false? f))
:when (if (xor? (true? b) (true? c)) (true? g) (false? g))
:when (if (or (false? g) (every? true? [e f g])) (true? h) (false? h))
:when (if (= 3 (count (filter true? [a b c d e f]))) (true? i) (false? i))
:when (if (every? true? [k l]) (true? j) (false? j))
:when (if (= 1 (count (filter true? [g h i]))) (true? k) (false? k))
:when (if (= 4 (count (filter true? [a b c d e f g h i j k]))) (true? l) (false? l))]
[a b c d e f g h i j k l]))

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(defparameter *state* (make-list 12))
(defparameter *statements* '(t ; 1
(= (count-true '(7 8 9 10 11 12)) 3) ; 2
(= (count-true '(2 4 6 8 10 12)) 2) ; 3
(or (not (p 5)) (and (p 6) (p 7))) ; 4
(and (not (p 2)) (not (p 3)) (not (p 4))) ; 5
(= (count-true '(1 3 5 7 9 11)) 4) ; 6
(or (and (p 2) (not (p 3))) (and (not (p 2)) (p 3))) ; 7
(or (not (p 7)) (and (p 5) (p 6))) ; 8
(= (count-true '(1 2 3 4 5 6)) 3) ; 9
(and (p 11) (p 12)) ;10
(= (count-true '(7 8 9)) 1) ;11
(= (count-true '(1 2 3 4 5 6 7 8 9 10 11)) 4))) ;12
(defun start ()
(loop while (not (equal *state* '(t t t t t t t t t t t t)))
do (progn (let ((true-stats (check)))
(cond ((= true-stats 11) (result nil))
((= true-stats 12) (result t))))
(new-state))))
(defun check ()
(loop for el in *state*
for stat in *statements*
counting (eq el (eval stat)) into true-stats
finally (return true-stats)))
(defun count-true (lst)
(loop for i in lst
counting (nth (- i 1) *state*) into total
finally (return total)))
(defun p (n)
(nth (- n 1) *state*))
(defun new-state ()
(let ((contr t))
(loop for i from 0 to 11
do (progn (setf (nth i *state*) (not (eq (nth i *state*) contr)))
(setq contr (and contr (not (nth i *state*))))))))
(defun result (?)
(format t "~:[Missed by one~;Solution:~] ~%~{~:[F~;T~] ~}~%" ? *state*))

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import std.stdio, std.algorithm, std.range, std.functional;
immutable texts = [
"this is a numbered list of twelve statements",
"exactly 3 of the last 6 statements are true",
"exactly 2 of the even-numbered statements are true",
"if statement 5 is true, then statements 6 and 7 are both true",
"the 3 preceding statements are all false",
"exactly 4 of the odd-numbered statements are true",
"either statement 2 or 3 is true, but not both",
"if statement 7 is true, then 5 and 6 are both true",
"exactly 3 of the first 6 statements are true",
"the next two statements are both true",
"exactly 1 of statements 7, 8 and 9 are true",
"exactly 4 of the preceding statements are true"];
immutable pure @safe @nogc bool function(in bool[])[12] predicates = [
s => s.length == 12,
s => s[$ - 6 .. $].sum == 3,
s => s.dropOne.stride(2).sum == 2,
s => s[4] ? (s[5] && s[6]) : true,
s => s[1 .. 4].sum == 0,
s => s.stride(2).sum == 4,
s => s[1 .. 3].sum == 1,
s => s[6] ? (s[4] && s[5]) : true,
s => s[0 .. 6].sum == 3,
s => s[10] && s[11],
s => s[6 .. 9].sum == 1,
s => s[0 .. 11].sum == 4];
void main() @safe {
enum nStats = predicates.length;
foreach (immutable n; 0 .. 2 ^^ nStats) {
bool[nStats] st, matches;
nStats.iota.map!(i => !!(n & (2 ^^ i))).copy(st[]);
st[].zip(predicates[].map!(f => f(st)))
.map!(s_t => s_t[0] == s_t[1]).copy(matches[]);
if (matches[].sum >= nStats - 1) {
if (matches[].all)
">>> Solution:".writeln;
else
writefln("Missed by statement: %d",
matches[].countUntil(false) + 1);
writefln("%-(%s %)", st[].map!q{ "FT"[a] });
}
}
}

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PROGRAM TWELVE_STMS
!$DYNAMIC
DIM PASS%[0],T%[0]
FUNCTION EOR(X,Y)
EOR=(X AND NOT(Y)) OR (NOT(X) AND Y)
END FUNCTION
BEGIN
NSTATEMENTS%=12
!$DIM PASS%[NSTATEMENTS%],T%[NSTATEMENTS%]
FOR TRY%=0 TO 2^NSTATEMENTS%-1 DO
! Postulate answer:
FOR STMT%=1 TO 12 DO
T%[STMT%]=(TRY% AND 2^(STMT%-1))<>0
END FOR
! Test consistency:
PASS%[1]=T%[1]=(NSTATEMENTS%=12)
PASS%[2]=T%[2]=((T%[7]+T%[8]+T%[9]+T%[10]+T%[11]+T%[12])=-3)
PASS%[3]=T%[3]=((T%[2]+T%[4]+T%[6]+T%[8]+T%[10]+T%[12])=-2)
PASS%[4]=T%[4]=((NOT T%[5] OR (T%[6] AND T%[7])))
PASS%[5]=T%[5]=(NOT T%[2] AND NOT T%[3] AND NOT T%[4])
PASS%[6]=T%[6]=((T%[1]+T%[3]+T%[5]+T%[7]+T%[9]+T%[11])=-4)
PASS%[7]=T%[7]=(EOR(T%[2],T%[3]))
PASS%[8]=T%[8]=((NOT T%[7] OR (T%[5] AND T%[6])))
PASS%[9]=T%[9]=((T%[1]+T%[2]+T%[3]+T%[4]+T%[5]+T%[6])=-3)
PASS%[10]=T%[10]=(T%[11] AND T%[12])
PASS%[11]=T%[11]=((T%[7]+T%[8]+T%[9])=-1)
PASS%[12]=T%[12]=((T%[1]+T%[2]+T%[3]+T%[4]+T%[5]+T%[6]+T%[7]+T%[8]+T%[9]+T%[10]+T%[11])=-4)
SUM=0
FOR I%=1 TO 12 DO
SUM=SUM+PASS%[I%]
END FOR
CASE SUM OF
-11->
PRINT("Near miss with statements ";)
FOR STMT%=1 TO 12 DO
IF T%[STMT%] THEN PRINT(STMT%;) END IF
IF NOT PASS%[STMT%] THEN MISS%=STMT% END IF
END FOR
PRINT("true (failed ";MISS%;").")
END ->
-12->
PRINT("Solution! with statements ";)
FOR STMT%=1 TO 12 DO
IF T%[STMT%] THEN PRINT(STMT%;) END IF
END FOR
PRINT("true.")
END ->
END CASE
END FOR ! TRY%
END PROGRAM

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class
APPLICATION
create
make
feature
make
-- Possible solutions.
do
create s.make_filled (False, 1, 12)
s [1] := True
recurseAll (2)
io.put_string (counter.out + " solution found. ")
end
feature {NONE}
s: ARRAY [BOOLEAN]
check2: BOOLEAN
-- Is statement 2 fulfilled?
local
count: INTEGER
do
across
7 |..| 12 as c
loop
if s [c.item] then
count := count + 1
end
end
Result := s [2] = (count = 3)
end
check3: BOOLEAN
-- Is statement 3 fulfilled?
local
count, i: INTEGER
do
from
i := 2
until
i > 12
loop
if s [i] then
count := count + 1
end
i := i + 2
end
Result := s [3] = (count = 2)
end
check4: BOOLEAN
-- Is statement 4 fulfilled?
do
Result := s [4] = ((not s [5]) or (s [6] and s [7]))
end
check5: BOOLEAN
-- Is statement 5 fulfilled?
do
Result := s [5] = ((not s [2]) and (not s [3]) and (not s [4]))
end
check6: BOOLEAN
-- Is statement 6 fulfilled?
local
count, i: INTEGER
do
from
i := 1
until
i > 11
loop
if s [i] then
count := count + 1
end
i := i + 2
end
Result := s [6] = (count = 4)
end
check7: BOOLEAN
-- Is statement 7 fulfilled?
do
Result := s [7] = ((s [2] or s [3]) and not (s [2] and s [3]))
end
check8: BOOLEAN
-- Is statement 8 fulfilled?
do
Result := s [8] = (not s [7] or (s [5] and s [6]))
end
check9: BOOLEAN
-- Is statement 9 fulfilled?
local
count: INTEGER
do
across
1 |..| 6 as c
loop
if s [c.item] then
count := count + 1
end
end
Result := s [9] = (count = 3)
end
check10: BOOLEAN
-- Is statement 10 fulfilled?
do
Result := s [10] = (s [11] and s [12])
end
check11: BOOLEAN
-- Is statement 11 fulfilled?
local
count: INTEGER
do
across
7 |..| 9 as c
loop
if s [c.item] then
count := count + 1
end
end
Result := s [11] = (count = 1)
end
check12: BOOLEAN
-- Is statement 12 fulfilled?
local
count: INTEGER
do
across
1 |..| 11 as c
loop
if s [c.item] then
count := count + 1
end
end
Result := (s [12] = (count = 4))
end
counter: INTEGER
checkit
-- Check if all statements are correctly solved.
do
if check2 and check3 and check4 and check5 and check6 and check7 and check8 and check9 and check10 and check11 and check12 then
across
1 |..| 12 as c
loop
if s [c.item] then
io.put_string (c.item.out + "%T")
end
end
io.new_line
counter := counter + 1
end
end
recurseAll (k: INTEGER)
-- All possible True and False combinations to check for a solution.
do
if k = 13 then
checkit
else
s [k] := False
recurseAll (k + 1)
s [k] := True
recurseAll (k + 1)
end
end
end

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import system'routines;
import extensions;
import extensions'text;
extension op
{
printSolution(bits)
= self.zipBy(bits,
(s,b => s.iif("T","F") + (s.xor:b).iif("* "," "))).summarize(new StringWriter());
toBit()
= self.iif(1,0);
}
puzzle = new Func1[]
{
(bits => bits.Length == 12),
(bits => bits.last(6).selectBy:(x => x.toBit()).summarize() == 3 ),
(bits => bits.zipBy(new Range(1, 12),
(x,i => (i.toInt().isEven()).and:x.toBit())).summarize() == 2 ),
(bits => bits[4].iif(bits[5] && bits[6],true) ),
(bits => ((bits[1] || bits[2]) || bits[3]).Inverted ),
(bits => bits.zipBy(new Range(1, 12),
(x,i => (i.toInt().isOdd()).and:x.toBit() )).summarize() == 4 ),
(bits => bits[1].xor(bits[2]) ),
(bits => bits[6].iif(bits[5] && bits[4],true) ),
(bits => bits.top(6).selectBy:(x => x.toBit() ).summarize() == 3 ),
(bits => bits[10] && bits[11] ),
(bits => (bits[6].toBit() + bits[7].toBit() + bits[8].toBit())==1 ),
(bits => bits.top(11).selectBy:(x => x.toBit()).summarize() == 4 )
};
public program()
{
console.writeLine();
for(int n := 0, n < 2.power(12), n += 1)
{
var bits := BitArray32.load(n).top(12).toArray();
var results := puzzle.selectBy:(r => r(bits)).toArray();
var counts := bits.zipBy(results, (b,r => b.xor:r.toBit() )).summarize();
counts =>
0 { console.printLine("Total hit :",results.printSolution:bits) }
1 { console.printLine("Near miss :",results.printSolution:bits) }
12 { console.printLine("Total miss:",results.printSolution:bits) };
};
console.readChar()
}

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: lastbit ( n1 -- n2)
dup if 1 swap begin dup 1 <> while swap 1+ swap 1 rshift repeat drop then
;
: bit 1 swap lshift and 0<> ; ( n1 n2 -- f)
: bitcount 0 swap begin dup while dup 1- and swap 1+ swap repeat drop ;
12 constant #stat \ number of statements
\ encoding of the statements
: s1 >r #stat 12 = r> 0 bit = ; \ heavy use of binary
: s2 >r r@ 4032 and bitcount 3 = r> 1 bit = ;
: s3 >r r@ 2730 and bitcount 2 = r> 2 bit = ;
: s4 >r r@ 4 bit 0= 96 r@ over and = or r> 3 bit = ;
: s5 >r r@ 14 and 0= r> 4 bit = ;
: s6 >r r@ 1365 and bitcount 4 = r> 5 bit = ;
: s7 >r r@ 1 bit r@ 2 bit xor r> 6 bit = ;
: s8 >r r@ 6 bit 0= 48 r@ over and = or r> 7 bit = ;
: s9 >r r@ 63 and bitcount 3 = r> 8 bit = ;
: s10 >r 3072 r@ over and = r> 9 bit = ;
: s11 >r r@ 448 and bitcount 1 = r> 10 bit = ;
: s12 >r r@ 2047 and bitcount 4 = r> 11 bit = ;
: list #stat 0 do dup i bit if i 1+ . then loop drop ;
: nearmiss? \ do we have a near miss?
over #stat 1- = if ( true-pattern #true stat-pattern)
." Near miss with statements " dup list ." true (failed "
>r over invert 1 #stat lshift 1- and lastbit 0 .r ." )" cr r>
then \ extract the failed statement
;
\ have we found a solution?
: solution? ( true-pattern #true stat-pattern)
over #stat = if ." Solution! with statements " dup list ." true." cr then
;
: 12statements \ test the twelve patterns
1 #stat lshift 0 do \ create another bit pattern
i s12 2* i s11 + 2* i s10 + 2* i s9 + 2* i s8 + 2* i s7 + 2*
i s6 + 2* i s5 + 2* i s4 + 2* i s3 + 2* i s2 + 2* i s1 +
abs dup bitcount i solution? nearmiss? drop drop drop
loop \ count number of bytes and evaluate
;
12statements

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Dim As Integer nEnunciados = 12, intento, enun, errado
Dim As Integer Afirm(nEnunciados), T(nEnunciados)
For intento = 0 To 2^nEnunciados-1
REM Postular respuesta:
For enun = 1 To 12
T(enun) = (intento And 2^(enun-1)) <> 0
Next enum
REM Prueba de consistencia:
Afirm(1) = T(1) = (nEnunciados = 12)
Afirm(2) = T(2) = ((T(7)+T(8)+T(9)+T(10)+T(11)+T(12)) = -3)
Afirm(3) = T(3) = ((T(2)+T(4)+T(6)+T(8)+T(10)+T(12)) = -2)
Afirm(4) = T(4) = ((Not T(5) Or (T(6) And T(7))))
Afirm(5) = T(5) = (Not T(2) And Not T(3) And Not T(4))
Afirm(6) = T(6) = ((T(1)+T(3)+T(5)+T(7)+T(9)+T(11)) = -4)
Afirm(7) = T(7) = ((T(2) Or T(3)))
Afirm(8) = T(8) = ((Not T(7) Or (T(5) And T(6))))
Afirm(9) = T(9) = ((T(1)+T(2)+T(3)+T(4)+T(5)+T(6)) = -3)
Afirm(10) = T(10) = (T(11) And T(12))
Afirm(11) = T(11) = ((T(7)+T(8)+T(9)) = -1)
Afirm(12) = T(12) = ((T(1)+T(2)+T(3)+T(4)+T(5)+T(6) + T(7)+T(8)+T(9)+T(10)+T(11)) = -4)
Dim As Integer suma = 0
For cont As Integer = 1 To 12
suma += Afirm(cont)
Next cont
Select Case suma
Case -11
Color 7: Print "Casi resuelto, con los enunciados ";
For enun = 1 To 12
If T(enun) Then Print ; enun; " ";
If Not Afirm(enun) Then errado = enun
Next enun
Print "verdaderos (falsos"; errado; ")."
Case -12
Color 10: Print "­Resuelto! con los enunciados ";
For enun = 1 To 12
If T(enun) Then Print ; enun; " ";
Next enun
Print "verdaderos."
End Select
Next intento
Sleep

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@ -0,0 +1,127 @@
package main
import "fmt"
// its' not too much more work to check all the permutations concurrently
var solution = make(chan int)
var nearMiss = make(chan int)
var done = make(chan bool)
func main() {
// iterate and use the bits as the permutation
for i := 0; i < 4096; i++ {
go checkPerm(i)
}
// collect the misses and list them after the complete solution(s)
var ms []int
for i := 0; i < 4096; {
select {
case <-done:
i++
case s := <-solution:
print12("solution", s)
case m := <-nearMiss:
ms = append(ms, m)
}
}
for _, m := range ms {
print12("near miss", m)
}
}
func print12(label string, bits int) {
fmt.Print(label, ":")
for i := 1; i <= 12; i++ {
if bits&1 == 1 {
fmt.Print(" ", i)
}
bits >>= 1
}
fmt.Println()
}
func checkPerm(tz int) {
// closure returns true if tz bit corresponding to
// 1-based statement number is 1.
ts := func(n uint) bool {
return tz>>(n-1)&1 == 1
}
// variadic closure returns number of statements listed as arguments
// which have corresponding tz bit == 1.
ntrue := func(xs ...uint) int {
nt := 0
for _, x := range xs {
if ts(x) {
nt++
}
}
return nt
}
// a flag used on repeated calls to test.
// set to true when first contradiction is found.
// if another is found, this function (checkPerm) can "short circuit"
// and return immediately without checking additional statements.
var con bool
// closure called to test each statement
test := func(statement uint, b bool) {
switch {
case ts(statement) == b:
case con:
panic("bail")
default:
con = true
}
}
// short circuit mechanism
defer func() {
if x := recover(); x != nil {
if msg, ok := x.(string); !ok && msg != "bail" {
panic(x)
}
}
done <- true
}()
// 1. This is a numbered list of twelve statements.
test(1, true)
// 2. Exactly 3 of the last 6 statements are true.
test(2, ntrue(7, 8, 9, 10, 11, 12) == 3)
// 3. Exactly 2 of the even-numbered statements are true.
test(3, ntrue(2, 4, 6, 8, 10, 12) == 2)
// 4. If statement 5 is true, then statements 6 and 7 are both true.
test(4, !ts(5) || ts(6) && ts(7))
// 5. The 3 preceding statements are all false.
test(5, !ts(4) && !ts(3) && !ts(2))
// 6. Exactly 4 of the odd-numbered statements are true.
test(6, ntrue(1, 3, 5, 7, 9, 11) == 4)
// 7. Either statement 2 or 3 is true, but not both.
test(7, ts(2) != ts(3))
// 8. If statement 7 is true, then 5 and 6 are both true.
test(8, !ts(7) || ts(5) && ts(6))
// 9. Exactly 3 of the first 6 statements are true.
test(9, ntrue(1, 2, 3, 4, 5, 6) == 3)
// 10. The next two statements are both true.
test(10, ts(11) && ts(12))
// 11. Exactly 1 of statements 7, 8 and 9 are true.
test(11, ntrue(7, 8, 9) == 1)
// 12. Exactly 4 of the preceding statements are true.
test(12, ntrue(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11) == 4)
// no short circuit? send permutation as either near miss or solution
if con {
nearMiss <- tz
} else {
solution <- tz
}
}

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enum Rule {
r01( 1, { r()*.num == (1..12) }),
r02( 2, { r(7..12).count { it.truth } == 3 }),
r03( 3, { r(2..12, 2).count { it.truth } == 2 }),
r04( 4, { r(5).truth ? r(6).truth && r(7).truth : true }),
r05( 5, { r(2..4).count { it.truth } == 0 }),
r06( 6, { r(1..11, 2).count { it.truth } == 4 }),
r07( 7, { r(2).truth != r(3).truth }),
r08( 8, { r(7).truth ? r(5).truth && r(6).truth : true }),
r09( 9, { r(1..6).count { it.truth } == 3 }),
r10(10, { r(11).truth && r(12).truth }),
r11(11, { r(7..9).count { it.truth } == 1 }),
r12(12, { r(1..11).count { it.truth } == 4 });
final int num
final Closure statement
boolean truth
static final List<Rule> rules = [ null, r01, r02, r03, r04, r05, r06, r07, r08, r09, r10, r11, r12]
private Rule(num, statement) {
this.num = num
this.statement = statement
}
public static Rule r(int index) { rules[index] }
public static List<Rule> r() { rules[1..12] }
public static List<Rule> r(List<Integer> indices) { rules[indices] }
public static List<Rule> r(IntRange indices) { rules[indices] }
public static List<Rule> r(IntRange indices, int step) { r(indices.step(step)) }
public static void setAllTruth(int bits) {
(1..12).each { r(it).truth = !(bits & (1 << (12 - it))) }
}
public static void evaluate() {
def nearMisses = [:]
(0..<(2**12)).each { i ->
setAllTruth(i)
def truthCandidates = r().findAll { it.truth }
def truthMatchCount = r().count { it.statement() == it.truth }
if (truthMatchCount == 12) {
println ">Solution< ${truthCandidates*.num}"
} else if (truthMatchCount == 11) {
def miss = (1..12).find { r(it).statement() != r(it).truth }
nearMisses << [(truthCandidates): miss]
}
}
nearMisses.each { truths, miss ->
printf ("Near Miss: %-21s (failed %2d)\n", "${truths*.num}", miss)
}
}
}
Rule.evaluate()

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import Data.List (findIndices)
tf :: [[Int] -> Bool] -> [[Int]]
tf = traverse (const [1, 0])
wrongness :: [Int] -> [[Int] -> Bool] -> [Int]
wrongness ns ps = findIndices id (zipWith (/=) ns (map (fromEnum . ($ ns)) ps))
statements :: [[Int] -> Bool]
statements =
[ (== 12) . length
, 3 [length statements - 6 ..]
, 2 [1,3 ..]
, 4 [4 .. 6]
, 0 [1 .. 3]
, 4 [0,2 ..]
, 1 [1, 2]
, 6 [4 .. 6]
, 3 [0 .. 5]
, 2 [10, 11]
, 1 [6, 7, 8]
, 4 [0 .. 10]
]
where
(), () :: Int -> [Int] -> [Int] -> Bool
(s x) b = s == (sum . map (b !!) . takeWhile (< length b)) x
(a x) b = (b !! a == 0) || all ((== 1) . (b !!)) x
testall :: [[Int] -> Bool] -> Int -> [([Int], [Int])]
testall s n =
[ (b, w)
| b <- tf s
, w <- [wrongness b s]
, length w == n ]
main :: IO ()
main =
let t = testall statements
in do putStrLn "Answer"
mapM_ print $ t 0
putStrLn "Near misses"
mapM_ print $ t 1

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@ -0,0 +1,6 @@
apply
128!:2
NB. example
'*:' apply 1 2 3
1 4 9

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@ -0,0 +1,18 @@
offby1=: 1=+/errors
'Statement ',"1 (":1+I.|: offby1 #"1 errors),"1 ' is inconsistent with exactly ',"1 ((1":@:+I.)"1 #:I.offby1),"1 ' being true'
Statement 1 is inconsistent with exactly 5 8 11 being true
Statement 1 is inconsistent with exactly 5 8 10 11 12 being true
Statement 1 is inconsistent with exactly 4 8 10 11 12 being true
Statement 8 is inconsistent with exactly 1 5 being true
Statement 11 is inconsistent with exactly 1 5 8 being true
Statement 12 is inconsistent with exactly 1 5 8 11 being true
Statement 12 is inconsistent with exactly 1 5 8 10 11 12 being true
Statement 8 is inconsistent with exactly 1 5 6 9 11 being true
Statement 8 is inconsistent with exactly 1 4 being true
Statement 12 is inconsistent with exactly 1 4 8 10 11 12 being true
Statement 6 is inconsistent with exactly 1 4 6 8 9 being true
Statement 7 is inconsistent with exactly 1 3 4 8 9 being true
Statement 9 is inconsistent with exactly 1 3 4 6 7 9 being true
Statement 12 is inconsistent with exactly 1 2 4 7 9 12 being true
Statement 10 is inconsistent with exactly 1 2 4 7 9 10 being true
Statement 8 is inconsistent with exactly 1 2 4 7 8 9 being true

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@ -0,0 +1,16 @@
S=: <;._2 (0 :0)
12&=@# NB. 1. This is a numbered list of twelve statements.
3=+/@:{.~&_6 NB. 2. Exactly 3 of the last 6 statements are true.
2= +/@:{~&1 3 5 7 9 11 NB. 3. Exactly 2 of the even-numbered statements are true.
4&{=*./@:{~&4 5 6 NB. 4. If statement 5 is true, then statements 6 and 7 are both true.
0=+/@:{~&1 2 3 NB. 5. The 3 preceding statements are all false.
4=+/@:{~&0 2 4 6 8 10 NB. 6. Exactly 4 of the odd-numbered statements are true.
1=+/@:{~&1 2 NB. 7. Either statement 2 or 3 is true, but not both.
6&{=*./@:{~&4 5 6 NB. 8. If statement 7 is true, then 5 and 6 are both true.
3=+/@:{.~&6 NB. 9. Exactly 3 of the first 6 statements are true.
2=+/@:{~&10 11 NB. 10. The next two statements are both true.
1=+/@:{~&6 7 8 NB. 11. Exactly 1 of statements 7, 8 and 9 are true.
4=+/@:{.~&11 NB. 12. Exactly 4 of the preceding statements are true.
)
testall=: (];"1 0<@I.@:(]~:(apply&><))"1) #:@i.@(2&^)@#

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@ -0,0 +1,4 @@
(#~0=#@{::~&_1"1) testall S
┌───────────────────────┬┐
│1 0 1 1 0 1 1 0 0 0 1 0││
└───────────────────────┴┘

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@ -0,0 +1,2 @@
1+I.;(#~0=#@{::~&_1"1) testall S
1 3 4 6 7 11

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@ -0,0 +1,34 @@
(#~1=#@{::~&_1"1) testall S
┌───────────────────────┬──┐
│0 0 0 0 1 0 0 1 0 0 1 0│0 │
├───────────────────────┼──┤
│0 0 0 0 1 0 0 1 0 1 1 1│0 │
├───────────────────────┼──┤
│0 0 0 1 0 0 0 1 0 1 1 1│0 │
├───────────────────────┼──┤
│1 0 0 0 1 0 0 0 0 0 0 0│7 │
├───────────────────────┼──┤
│1 0 0 0 1 0 0 1 0 0 0 0│10│
├───────────────────────┼──┤
│1 0 0 0 1 0 0 1 0 0 1 0│11│
├───────────────────────┼──┤
│1 0 0 0 1 0 0 1 0 1 1 1│11│
├───────────────────────┼──┤
│1 0 0 0 1 1 0 0 1 0 1 0│7 │
├───────────────────────┼──┤
│1 0 0 1 0 0 0 0 0 0 0 0│7 │
├───────────────────────┼──┤
│1 0 0 1 0 0 0 1 0 1 1 1│11│
├───────────────────────┼──┤
│1 0 0 1 0 1 0 1 1 0 0 0│5 │
├───────────────────────┼──┤
│1 0 1 1 0 0 0 1 1 0 0 0│6 │
├───────────────────────┼──┤
│1 0 1 1 0 1 1 0 1 0 0 0│8 │
├───────────────────────┼──┤
│1 1 0 1 0 0 1 0 1 0 0 1│11│
├───────────────────────┼──┤
│1 1 0 1 0 0 1 0 1 1 0 0│9 │
├───────────────────────┼──┤
│1 1 0 1 0 0 1 1 1 0 0 0│7 │
└───────────────────────┴──┘

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@ -0,0 +1,2 @@
(-N)&{. #: S <:@]^:((]-.@-:(apply&><)"1) (-N)&{.@#:@])^:(_) 2^N=.#S
1 0 1 1 0 1 1 0 0 0 1 0

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@ -0,0 +1,16 @@
true=:1 :'(m-1)&{'
S=: <;._2 (0 :0)
12 = # NB. 1. This is a numbered list of twelve statements.
3 (= +/) _6&{. NB. 2. Exactly 3 of the last 6 statements are true.
2 (= +/) (12$0 1)&# NB. 3. Exactly 2 of the even-numbered statements are true.
5 true (<: */) 6 7 true NB. 4. If statement 5 is true, then statements 6 and 7 are both true.
0 (= +/) 2 3 4 true NB. 5. The 3 preceding statements are all false.
4 (= +/) (12$1 0)&# NB. 6. Exactly 4 of the odd-numbered statements are true.
1 (= +/) 2 3 true NB. 7. Either statement 2 or 3 is true, but not both.
7 true (<: */) 5 6 true NB. 8. If statement 7 is true, then 5 and 6 are both true.
3 (= +/) 6&{. NB. 9. Exactly 3 of the first 6 statements are true.
*/@(11 12 true) NB. 10. The next two statements are both true.
1 (= +/) 7 8 9 true NB. 11. Exactly 1 of statements 7, 8 and 9 are true.
4 (= +/) }: NB. 12. Exactly 4 of the preceding statements are true.
)

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@ -0,0 +1,17 @@
'sum not mask'=: |:".;._2(0 :0)
0; 0; 0 0 0 0 0 0 0 0 0 0 0 0 NB. 1. This is a numbered list of twelve statements.
3; 0; 0 0 0 0 0 0 1 1 1 1 1 1 NB. 2. Exactly 3 of the last 6 statements are true.
2; 0; 0 1 0 1 0 1 0 1 0 1 0 1 NB. 3. Exactly 2 of the even-numbered statements are true.
2; 5; 0 0 0 0 0 1 1 0 0 0 0 0 NB. 4. If statement 5 is true, then statements 6 and 7 are both true.
0; 0; 0 1 1 1 0 0 0 0 0 0 0 0 NB. 5. The 3 preceding statements are all false.
4; 0; 1 0 1 0 1 0 1 0 1 0 1 0 NB. 6. Exactly 4 of the odd-numbered statements are true.
1; 0; 0 1 1 0 0 0 0 0 0 0 0 0 NB. 7. Either statement 2 or 3 is true, but not both.
2; 7; 0 0 0 0 1 1 0 0 0 0 0 0 NB. 8. If statement 7 is true, then 5 and 6 are both true.
3; 0; 1 1 1 1 1 1 0 0 0 0 0 0 NB. 9. Exactly 3 of the first 6 statements are true.
2; 0; 0 0 0 0 0 0 0 0 0 0 1 1 NB. 10. The next two statements are both true.
1; 0; 0 0 0 0 0 0 1 1 1 0 0 0 NB. 11. Exactly 1 of statements 7, 8 and 9 are true.
4; 0; 1 1 1 1 1 1 1 1 1 1 1 0 NB. 12. Exactly 4 of the preceding statements are true.
)
propositions=: |:#:i.2^#sum
errors=: propositions~:(1 - not { 1,propositions) >. sum = mask +/ .*propositions

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@ -0,0 +1,4 @@
#:I.0=+/errors
1 0 1 1 0 1 1 0 0 0 1 0
1+I.#:I.0=+/errors NB. true propositions for the consistent case
1 3 4 6 7 11

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@ -0,0 +1,113 @@
public class LogicPuzzle
{
boolean S[] = new boolean[13];
int Count = 0;
public boolean check2 ()
{
int count = 0;
for (int k = 7; k <= 12; k++)
if (S[k]) count++;
return S[2] == (count == 3);
}
public boolean check3 ()
{
int count = 0;
for (int k = 2; k <= 12; k += 2)
if (S[k]) count++;
return S[3] == (count == 2);
}
public boolean check4 ()
{
return S[4] == ( !S[5] || S[6] && S[7]);
}
public boolean check5 ()
{
return S[5] == ( !S[2] && !S[3] && !S[4]);
}
public boolean check6 ()
{
int count = 0;
for (int k = 1; k <= 11; k += 2)
if (S[k]) count++;
return S[6] == (count == 4);
}
public boolean check7 ()
{
return S[7] == ((S[2] || S[3]) && !(S[2] && S[3]));
}
public boolean check8 ()
{
return S[8] == ( !S[7] || S[5] && S[6]);
}
public boolean check9 ()
{
int count = 0;
for (int k = 1; k <= 6; k++)
if (S[k]) count++;
return S[9] == (count == 3);
}
public boolean check10 ()
{
return S[10] == (S[11] && S[12]);
}
public boolean check11 ()
{
int count = 0;
for (int k = 7; k <= 9; k++)
if (S[k]) count++;
return S[11] == (count == 1);
}
public boolean check12 ()
{
int count = 0;
for (int k = 1; k <= 11; k++)
if (S[k]) count++;
return S[12] == (count == 4);
}
public void check ()
{
if (check2() && check3() && check4() && check5() && check6()
&& check7() && check8() && check9() && check10() && check11()
&& check12())
{
for (int k = 1; k <= 12; k++)
if (S[k]) System.out.print(k + " ");
System.out.println();
Count++;
}
}
public void recurseAll (int k)
{
if (k == 13)
check();
else
{
S[k] = false;
recurseAll(k + 1);
S[k] = true;
recurseAll(k + 1);
}
}
public static void main (String args[])
{
LogicPuzzle P = new LogicPuzzle();
P.S[1] = true;
P.recurseAll(2);
System.out.println();
System.out.println(P.Count + " Solutions found.");
}
}

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@ -0,0 +1,51 @@
def indexed(filter):
. as $in
| reduce range(0;length) as $i ([]; if ($i | filter) then . + [$in[$i]] else . end);
def count(value): map(select(. == value)) | length;
# The truth or falsity of the 12 statements can be captured in an array of size 12:
def generate(k):
if k == 1 then [true], [false]
else generate(1) + generate(k-1)
end;
# Input: a boolean array
def evaluate:
[ (length == 12), #1
((.[6:] | count(true)) == 3), #2
((indexed(. % 2 == 1) | count(true)) == 2), #3
(if .[4] then .[5] and .[6] else true end), #4
((.[1:4] | count(false)) == 3), #5
((indexed(. % 2 == 0) | count(true)) == 4), #6
(([.[1], .[2]] | count(true)) == 1), #7
(if .[6] then .[4] and .[5] else true end), #8
((.[0:6] | count(true)) == 3), #9
(.[10] and .[11]), #10
((.[6:9] | count(true)) == 1), #11
((.[0:11] | count(true)) == 4) #12
];
# The following query generates the solution to the problem:
# generate(12) | . as $vector | if evaluate == $vector then $vector else empty end
# Running "task" as defined next would generate
# both the general solution as well as the off-by-one solutions:
def task:
# count agreements
def agreed(x;y): reduce range(0;x|length) as $i (0; if x[$i] == y[$i] then .+1 else . end);
reduce generate(12) as $vector
([]; ($vector | evaluate) as $e
| agreed($vector; $e) as $agreed
| if $agreed == 12 then [[12,$vector]] + .
elif $agreed == 11 then . + [[11, $vector]]
else .
end);
# Since the solutions have been given elsewhere, we simply count the
# number of exact and off-by-one solutions:
task | length

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@ -0,0 +1,56 @@
using Printf
function showflaggedbits{T<:BitArray{1}}(a::T, f::T)
tf = map(x->x ? "T" : "F", a)
flg = map(x->x ? "*" : " ", f)
join(tf .* flg, " ")
end
const props = [s -> length(s) == 12,
s -> sum(s[7:12]) == 3,
s -> sum(s[2:2:end]) == 2,
s -> !s[5] || (s[6] & s[7]),
s -> !any(s[2:4]),
s -> sum(s[1:2:end]) == 4,
s -> s[2] $ s[3],
s -> !s[7] || (s[5] & s[6]),
s -> sum(s[1:6]) == 3,
s -> s[11] & s[12],
s -> sum(s[7:9]) == 1,
s -> sum(s[1:end-1]) == 4]
const NDIG = length(props)
NDIG < WORD_SIZE || println("WARNING, too many propositions!")
mhist = zeros(Int, NDIG+1)
println("Checking the ", NDIG, " statements against all possibilities.\n")
print(" "^15)
for i in 1:NDIG
print(@sprintf "%3d" i)
end
println()
for i in 0:(2^NDIG-1)
s = bitpack(digits(i, 2, NDIG))
t = bitpack([p(s) for p in props])
misses = s$t
mcnt = sum(misses)
mhist[NDIG-mcnt+1] += 1
mcnt < 2 || mcnt == NDIG || continue
if mcnt == 0
print(" Exact Match: ")
elseif mcnt == NDIG
print(" Total Miss: ")
else
print(" Near Miss: ")
end
println(showflaggedbits(t, misses))
end
println()
println("Distribution of matches")
println(" Matches Cases")
for i in (NDIG+1):-1:1
println(@sprintf " %2d => %4d" i-1 mhist[i])
end

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@ -0,0 +1,45 @@
// version 1.1.3
typealias Predicate = (String) -> Boolean
val predicates = listOf<Predicate>(
{ it.length == 13 }, // indexing starts at 0 but first bit ignored
{ (7..12).count { i -> it[i] == '1' } == 3 },
{ (2..12 step 2).count { i -> it[i] == '1' } == 2 },
{ it[5] == '0' || (it[6] == '1' && it[7] == '1') },
{ it[2] == '0' && it[3] == '0' && it[4] == '0' },
{ (1..11 step 2).count { i -> it[i] == '1' } == 4 },
{ (it[2] == '1') xor (it[3] == '1') },
{ it[7] == '0' || (it[5] == '1' && it[6] == '1') },
{ (1..6).count { i -> it[i] == '1' } == 3 },
{ it[11] == '1' && it[12] == '1' },
{ (7..9).count { i -> it[i] == '1' } == 1 },
{ (1..11).count { i -> it[i] == '1' } == 4 }
)
fun show(s: String, indent: Boolean) {
if (indent) print(" ")
for (i in s.indices) if (s[i] == '1') print("$i ")
println()
}
fun main(args: Array<String>) {
println("Exact hits:")
for (i in 0..4095) {
val s = i.toString(2).padStart(13, '0')
var j = 1
if (predicates.all { it(s) == (s[j++] == '1') }) show(s, true)
}
println("\nNear misses:")
for (i in 0..4095) {
val s = i.toString(2).padStart(13, '0')
var j = 1
if (predicates.count { it(s) == (s[j++] == '1') } == 11) {
var k = 1
val iof = predicates.indexOfFirst { it(s) != (s[k++] == '1') } + 1
print(" (Fails at statement ${"%2d".format(iof)}) ")
show(s, false)
}
}
}

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@ -0,0 +1,10 @@
Print["Answer:\n", Column@Cases[#, {s_, 0} :> s], "\nNear misses:\n",
Column@Cases[#, {s_, 1} :> s]] &[{#,
Count[Boole /@ {Length@# == 12, Total@#[[7 ;;]] == 3,
Total@#[[2 ;; 12 ;; 2]] == 2, #[[5]] (#[[6]] + #[[7]] - 2) ==
0, Total@#[[2 ;; 4]] == 0,
Total@#[[1 ;; 11 ;; 2]] == 4, #[[2]] + #[[3]] ==
1, #[[7]] (#[[5]] + #[[6]] - 2) == 0,
Total@#[[;; 6]] == 3, #[[11]] + #[[12]] == 2,
Total@#[[7 ;; 9]] == 1, Total@#[[;; 11]] == 4} - #,
Except[0]]} & /@ Tuples[{1, 0}, 12]]

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@ -0,0 +1,43 @@
import bitops, sequtils, strformat, strutils, sugar
type Bools = array[1..12, bool]
const Predicates = [1: (b: Bools) => b.len == 12,
2: (b: Bools) => b[7..12].count(true) == 3,
3: (b: Bools) => toSeq(countup(2, 12, 2)).mapIt(b[it]).count(true) == 2,
4: (b: Bools) => not b[5] or b[6] and b[7],
5: (b: Bools) => not b[2] and not b[3] and not b[4],
6: (b: Bools) => toSeq(countup(1, 12, 2)).mapIt(b[it]).count(true) == 4,
7: (b: Bools) => b[2] xor b[3],
8: (b: Bools) => not b[7] or b[5] and b[6],
9: (b: Bools) => b[1..6].count(true) == 3,
10: (b: Bools) => b[11] and b[12],
11: (b: Bools) => b[7..9].count(true) == 1,
12: (b: Bools) => b[1..11].count(true) == 4]
proc `$`(b: Bools): string =
toSeq(1..12).filterIt(b[it]).join(" ")
echo "Exacts hits:"
var bools: Bools
for n in 0..4095:
block check:
for i in 1..12: bools[i] = n.testBit(12 - i)
for i, predicate in Predicates:
if predicate(bools) != bools[i]:
break check
echo " ", bools
echo "\nNear misses:"
for n in 0..4095:
for i in 1..12: bools[i] = n.testBit(12 - i)
var count = 0
for i, predicate in Predicates:
if predicate(bools) == bools[i]: inc count
if count == 11:
for i, predicate in Predicates:
if predicate(bools) != bools[i]:
echo &" (Fails at statement {i:2}) {bools}"
break

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PROGRAM TwelveStatements;
{
This program searches through the 4095 possible sets
of 12 statements for any which may be self-consistent.
}
CONST
max12b = 4095; { Largest 12 byte number. }
TYPE
statnum = 1..12; { statement numbers }
statset = set of statnum; { sets of statements }
VAR { global variables for use in main algorithm }
trialNumber: integer;
trialSet, testResults: statset;
function Convert(n: integer): statset;
{
Converts an integer into a set of statements.
For each "1" in the last 12 bits of
the integer's binary representation,
a statement number is put into the set.
}
var
i: statnum;
s: statset;
begin
s := []; { Empty set. }
for i := 12 downto 1 do begin
if (n mod 2) = 1 then s := s + [i];
n := n div 2
end;
Convert := s
end;
procedure Express(truths: statset);
{
Writes the statement number of each "truth",
with at least one space in front,
all on one line.
}
var n: statnum;
begin
for n := 1 to 12 do
if n in truths then write(n:3);
writeln
end;
function Count(truths: statset): integer;
{ Counts the statement numbers in the set. }
var
s: statnum;
i: integer;
begin
i := 0;
for s := 1 to 12 do if s in truths then i := i + 1;
Count := i
end;
function Test(truths: statset): statset;
{
Starts with a set of supposedly true statements
and checks which of the 12 statements can actually
be confirmed about the set itself.
}
var
evens, odds, confirmations: statset;
begin
evens := [2, 4, 6, 8, 10, 12];
odds := [1, 3, 5, 7, 9, 11];
{ Statement 1 is necessarily true. }
confirmations := [1];
{ Statement 2 }
if Count(truths * [7..12]) = 3
then confirmations := confirmations + [2];
{ Statement 3 }
if Count(truths * evens) = 2
then confirmations := confirmations + [3];
{ Statement 4 is true if 6 and 7 are true, or if 5 is false. }
if ([6, 7] <= truths) or not (5 in truths)
then confirmations := confirmations + [4];
{ Statement 5 }
if [2, 3, 4] <= truths
then confirmations := confirmations + [5];
{ Statement 6 }
if Count(truths * odds) = 4
then confirmations := confirmations + [6];
{ Statement 7 }
if (2 in truths) xor (3 in truths)
then confirmations := confirmations + [7];
{ Statement 8 is true if 5 and 6 are true, or if 7 is false. }
if ([5, 6] <= truths) or not (7 in truths)
then confirmations := confirmations + [8];
{ Statement 9 }
if Count(truths * [1..6]) = 3
then confirmations := confirmations + [9];
{ Statement 10 }
if [11, 12] <= truths
then confirmations := confirmations + [10];
{ Statement 11 }
if Count(truths * [7, 8, 9]) = 1
then confirmations := confirmations + [11];
{ Statement 12 }
if Count(truths - [12]) = 4
then confirmations := confirmations + [12];
Test := confirmations
end;
BEGIN { Main algorithm. }
for trialNumber := 1 to max12b do begin
trialSet := Convert(trialNumber);
testResults := Test(trialSet);
if testResults = trialSet then Express(trialSet)
end;
writeln('Done. Press ENTER.');
readln
END.

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@ -0,0 +1,28 @@
use List::Util 'sum';
my @condition = (
sub { 0 }, # dummy sub for index 0
sub { 13==@_ },
sub { 3==sum @_[7..12] },
sub { 2==sum @_[2,4,6,8,10,12] },
sub { $_[5] ? ($_[6] and $_[7]) : 1 },
sub { !$_[2] and !$_[3] and !$_[4] },
sub { 4==sum @_[1,3,5,7,9,11] },
sub { $_[2]==1-$_[3] },
sub { $_[7] ? ($_[5] and $_[6]) : 1 },
sub { 3==sum @_[1..6] },
sub { 2==sum @_[11..12] },
sub { 1==sum @_[7,8,9] },
sub { 4==sum @_[1..11] },
);
sub miss {
return grep { $condition[$_]->(@_) != $_[$_] } 1..12;
}
for (0..2**12-1) {
my @truth = split //, sprintf "0%012b", $_;
my @no = miss @truth;
print "Solution: true statements are ", join( " ", grep { $truth[$_] } 1..12), "\n" if 0 == @no;
print "1 miss (",$no[0],"): true statements are ", join( " ", grep { $truth[$_] } 1..12), "\n" if 1 == @no;
}

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@ -0,0 +1,32 @@
(phixonline)-->
<span style="color: #008080;">function</span> <span style="color: #000000;">s1</span><span style="color: #0000FF;">(</span><span style="color: #004080;">string</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">return</span> <span style="color: #7060A8;">length</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">)=</span><span style="color: #000000;">12</span> <span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #008080;">function</span> <span style="color: #000000;">s2</span><span style="color: #0000FF;">(</span><span style="color: #004080;">string</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">return</span> <span style="color: #7060A8;">sum</span><span style="color: #0000FF;">(</span><span style="color: #7060A8;">sq_eq</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">7</span><span style="color: #0000FF;">..</span><span style="color: #000000;">12</span><span style="color: #0000FF;">],</span><span style="color: #008000;">'1'</span><span style="color: #0000FF;">))=</span><span style="color: #000000;">3</span> <span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #008080;">function</span> <span style="color: #000000;">s3</span><span style="color: #0000FF;">(</span><span style="color: #004080;">string</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">return</span> <span style="color: #7060A8;">sum</span><span style="color: #0000FF;">(</span><span style="color: #7060A8;">sq_eq</span><span style="color: #0000FF;">(</span><span style="color: #7060A8;">extract</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">,</span><span style="color: #7060A8;">tagset</span><span style="color: #0000FF;">(</span><span style="color: #000000;">12</span><span style="color: #0000FF;">,</span><span style="color: #000000;">2</span><span style="color: #0000FF;">,</span><span style="color: #000000;">2</span><span style="color: #0000FF;">)),</span><span style="color: #008000;">'1'</span><span style="color: #0000FF;">))=</span><span style="color: #000000;">2</span> <span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #008080;">function</span> <span style="color: #000000;">s4</span><span style="color: #0000FF;">(</span><span style="color: #004080;">string</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">return</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">5</span><span style="color: #0000FF;">]=</span><span style="color: #008000;">'0'</span> <span style="color: #008080;">or</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">6</span><span style="color: #0000FF;">..</span><span style="color: #000000;">7</span><span style="color: #0000FF;">]=</span><span style="color: #008000;">"11"</span> <span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #008080;">function</span> <span style="color: #000000;">s5</span><span style="color: #0000FF;">(</span><span style="color: #004080;">string</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">return</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">2</span><span style="color: #0000FF;">..</span><span style="color: #000000;">4</span><span style="color: #0000FF;">]=</span><span style="color: #008000;">"000"</span> <span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #008080;">function</span> <span style="color: #000000;">s6</span><span style="color: #0000FF;">(</span><span style="color: #004080;">string</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">return</span> <span style="color: #7060A8;">sum</span><span style="color: #0000FF;">(</span><span style="color: #7060A8;">sq_eq</span><span style="color: #0000FF;">(</span><span style="color: #7060A8;">extract</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">,</span><span style="color: #7060A8;">tagset</span><span style="color: #0000FF;">(</span><span style="color: #000000;">12</span><span style="color: #0000FF;">,</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #000000;">2</span><span style="color: #0000FF;">)),</span><span style="color: #008000;">'1'</span><span style="color: #0000FF;">))=</span><span style="color: #000000;">4</span> <span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #008080;">function</span> <span style="color: #000000;">s7</span><span style="color: #0000FF;">(</span><span style="color: #004080;">string</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">return</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">2</span><span style="color: #0000FF;">]!=</span><span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">3</span><span style="color: #0000FF;">]</span> <span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #008080;">function</span> <span style="color: #000000;">s8</span><span style="color: #0000FF;">(</span><span style="color: #004080;">string</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">return</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">7</span><span style="color: #0000FF;">]=</span><span style="color: #008000;">'0'</span> <span style="color: #008080;">or</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">5</span><span style="color: #0000FF;">..</span><span style="color: #000000;">6</span><span style="color: #0000FF;">]=</span><span style="color: #008000;">"11"</span> <span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #008080;">function</span> <span style="color: #000000;">s9</span><span style="color: #0000FF;">(</span><span style="color: #004080;">string</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">return</span> <span style="color: #7060A8;">sum</span><span style="color: #0000FF;">(</span><span style="color: #7060A8;">sq_eq</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">1</span><span style="color: #0000FF;">..</span><span style="color: #000000;">6</span><span style="color: #0000FF;">],</span><span style="color: #008000;">'1'</span><span style="color: #0000FF;">))=</span><span style="color: #000000;">3</span> <span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #008080;">function</span> <span style="color: #000000;">s10</span><span style="color: #0000FF;">(</span><span style="color: #004080;">string</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">return</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">11</span><span style="color: #0000FF;">..</span><span style="color: #000000;">12</span><span style="color: #0000FF;">]=</span><span style="color: #008000;">"11"</span> <span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #008080;">function</span> <span style="color: #000000;">s11</span><span style="color: #0000FF;">(</span><span style="color: #004080;">string</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">return</span> <span style="color: #7060A8;">sum</span><span style="color: #0000FF;">(</span><span style="color: #7060A8;">sq_eq</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">7</span><span style="color: #0000FF;">..</span><span style="color: #000000;">9</span><span style="color: #0000FF;">],</span><span style="color: #008000;">'1'</span><span style="color: #0000FF;">))=</span><span style="color: #000000;">1</span> <span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #008080;">function</span> <span style="color: #000000;">s12</span><span style="color: #0000FF;">(</span><span style="color: #004080;">string</span> <span style="color: #000000;">s</span><span style="color: #0000FF;">)</span> <span style="color: #008080;">return</span> <span style="color: #7060A8;">sum</span><span style="color: #0000FF;">(</span><span style="color: #7060A8;">sq_eq</span><span style="color: #0000FF;">(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">1</span><span style="color: #0000FF;">..</span><span style="color: #000000;">11</span><span style="color: #0000FF;">],</span><span style="color: #008000;">'1'</span><span style="color: #0000FF;">))=</span><span style="color: #000000;">4</span> <span style="color: #008080;">end</span> <span style="color: #008080;">function</span>
<span style="color: #004080;">sequence</span> <span style="color: #000000;">rtn</span> <span style="color: #0000FF;">=</span> <span style="color: #0000FF;">{</span><span style="color: #000000;">s1</span><span style="color: #0000FF;">,</span><span style="color: #000000;">s2</span><span style="color: #0000FF;">,</span><span style="color: #000000;">s3</span><span style="color: #0000FF;">,</span><span style="color: #000000;">s4</span><span style="color: #0000FF;">,</span><span style="color: #000000;">s5</span><span style="color: #0000FF;">,</span><span style="color: #000000;">s6</span><span style="color: #0000FF;">,</span><span style="color: #000000;">s7</span><span style="color: #0000FF;">,</span><span style="color: #000000;">s8</span><span style="color: #0000FF;">,</span><span style="color: #000000;">s9</span><span style="color: #0000FF;">,</span><span style="color: #000000;">s10</span><span style="color: #0000FF;">,</span><span style="color: #000000;">s11</span><span style="color: #0000FF;">,</span><span style="color: #000000;">s12</span><span style="color: #0000FF;">}</span>
<span style="color: #004080;">string</span> <span style="color: #000000;">misses</span> <span style="color: #0000FF;">=</span> <span style="color: #008000;">"\n"</span>
<span style="color: #008080;">for</span> <span style="color: #000000;">i</span><span style="color: #0000FF;">=</span><span style="color: #000000;">0</span> <span style="color: #008080;">to</span> <span style="color: #7060A8;">power</span><span style="color: #0000FF;">(</span><span style="color: #000000;">2</span><span style="color: #0000FF;">,</span><span style="color: #000000;">12</span><span style="color: #0000FF;">)-</span><span style="color: #000000;">1</span> <span style="color: #008080;">do</span>
<span style="color: #004080;">string</span> <span style="color: #000000;">s</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">sprintf</span><span style="color: #0000FF;">(</span><span style="color: #008000;">"%012b"</span><span style="color: #0000FF;">,</span><span style="color: #000000;">i</span><span style="color: #0000FF;">)</span>
<span style="color: #004080;">sequence</span> <span style="color: #000000;">res</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">find_all</span><span style="color: #0000FF;">(</span><span style="color: #008000;">'1'</span><span style="color: #0000FF;">,</span><span style="color: #000000;">s</span><span style="color: #0000FF;">)</span>
<span style="color: #004080;">integer</span> <span style="color: #000000;">t</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">0</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">pass</span><span style="color: #0000FF;">,</span> <span style="color: #000000;">fail</span>
<span style="color: #008080;">for</span> <span style="color: #000000;">b</span><span style="color: #0000FF;">=</span><span style="color: #000000;">1</span> <span style="color: #008080;">to</span> <span style="color: #000000;">12</span> <span style="color: #008080;">do</span>
<span style="color: #000000;">pass</span> <span style="color: #0000FF;">=</span> <span style="color: #7060A8;">call_func</span><span style="color: #0000FF;">(</span><span style="color: #000000;">rtn</span><span style="color: #0000FF;">[</span><span style="color: #000000;">b</span><span style="color: #0000FF;">],{</span><span style="color: #000000;">s</span><span style="color: #0000FF;">})=(</span><span style="color: #000000;">s</span><span style="color: #0000FF;">[</span><span style="color: #000000;">b</span><span style="color: #0000FF;">]=</span><span style="color: #008000;">'1'</span><span style="color: #0000FF;">)</span>
<span style="color: #008080;">if</span> <span style="color: #008080;">not</span> <span style="color: #000000;">pass</span> <span style="color: #008080;">then</span> <span style="color: #000000;">fail</span> <span style="color: #0000FF;">=</span> <span style="color: #000000;">b</span> <span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #000000;">t</span> <span style="color: #0000FF;">+=</span> <span style="color: #000000;">pass</span>
<span style="color: #008080;">if</span> <span style="color: #000000;">b</span><span style="color: #0000FF;">=</span><span style="color: #000000;">12</span> <span style="color: #008080;">and</span> <span style="color: #000000;">t</span><span style="color: #0000FF;">=</span><span style="color: #000000;">12</span> <span style="color: #008080;">then</span> <span style="color: #7060A8;">printf</span><span style="color: #0000FF;">(</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #008000;">"Solution: %v\n"</span><span style="color: #0000FF;">,{</span><span style="color: #000000;">res</span><span style="color: #0000FF;">})</span> <span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">for</span>
<span style="color: #008080;">if</span> <span style="color: #000000;">t</span><span style="color: #0000FF;">=</span><span style="color: #000000;">11</span> <span style="color: #008080;">then</span>
<span style="color: #000000;">misses</span> <span style="color: #0000FF;">&=</span> <span style="color: #7060A8;">sprintf</span><span style="color: #0000FF;">(</span><span style="color: #008000;">"Near miss: %v, fail on %d\n"</span><span style="color: #0000FF;">,{</span><span style="color: #000000;">res</span><span style="color: #0000FF;">,</span><span style="color: #000000;">fail</span><span style="color: #0000FF;">})</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">if</span>
<span style="color: #008080;">end</span> <span style="color: #008080;">for</span>
<span style="color: #7060A8;">puts</span><span style="color: #0000FF;">(</span><span style="color: #000000;">1</span><span style="color: #0000FF;">,</span><span style="color: #000000;">misses</span><span style="color: #0000FF;">)</span>
<!--

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@ -0,0 +1,51 @@
% {{trans|Prolog}}
go ?=>
puzzle,
fail, % check for more answers
nl.
go => true.
puzzle =>
% 1. This is a numbered list of twelve statements.
L = [A1, A2, A3, A4, A5, A6, A7, A8, A9, A10, A11, A12],
L :: 0..1,
element(1, L, 1),
% 2. Exactly 3 of the last 6 statements are true.
A2 #<=> sum(L[7..12]) #= 3,
% 3. Exactly 2 of the even-numbered statements are true.
A3 #<=> sum([L[I]:I in 1..12,I mod 2 == 0]) #= 2,
% 4. If statement 5 is true, then statements 6 and 7 are both true.
A4 #<=> (A5 #=> (A6 #/\ A7)),
% 5. The 3 preceding statements are all false.
A5 #<=> sum(L[2..4]) #= 0,
% 6. Exactly 4 of the odd-numbered statements are true.
A6 #<=> sum([L[I]:I in 1..12,I mod 2 == 1]) #= 4,
% 7. Either statement 2 or 3 is true, but not both.
A7 #<=> (A2 + A3 #= 1),
% 8. If statement 7 is true, then 5 and 6 are both true.
A8 #<=> (A7 #=> A5 #/\ A6),
% 9. Exactly 3 of the first 6 statements are true.
A9 #<=> sum(L[1..6]) #= 3,
% 10. The next two statements are both true.
A10 #<=> (A11 #/\ A12),
% 11. Exactly 1 of statements 7, 8 and 9 are true.
A11 #<=> (A7 + A8 + A9 #= 1),
% 12. Exactly 4 of the preceding statements are true.
A12 #<=> sum(L[1..11]) #= 4,
solve(L),
println('L'=L),
printf("Statements %w are true.\n", [I.to_string : I in 1..12, L[I] == 1].join(" ")),
nl.

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puzzle :-
% 1. This is a numbered list of twelve statements.
L = [A1, A2, A3, A4, A5, A6, A7, A8, A9, A10, A11, A12],
L ins 0..1,
element(1, L, 1),
% 2. Exactly 3 of the last 6 statements are true.
A2 #<==> A7 + A8 + A9 + A10 + A11 + A12 #= 3,
% 3. Exactly 2 of the even-numbered statements are true.
A3 #<==> A2 + A4 + A6 + A8 + A10 + A12 #= 2,
% 4. If statement 5 is true, then statements 6 and 7 are both true.
A4 #<==> (A5 #==> (A6 #/\ A7)),
% 5. The 3 preceding statements are all false.
A5 #<==> A2 + A3 + A4 #= 0,
% 6. Exactly 4 of the odd-numbered statements are true.
A6 #==> A1 + A3 + A5 + A7 + A9 + A11 #= 4,
% 7. Either statement 2 or 3 is true, but not both.
A7 #<==> A2 + A3 #= 1,
% 8. If statement 7 is true, then 5 and 6 are both true.
A8 #<==> (A7 #==> A5 #/\ A6),
% 9. Exactly 3 of the first 6 statements are true.
A9 #<==> A1 + A2 + A3 + A4 + A5 + A6 #= 3,
% 10. The next two statements are both true.
A10 #<==> A11 #/\ A12,
% 11. Exactly 1 of statements 7, 8 and 9 are true.
A11 #<==> A7 + A8 + A9 #= 1,
% 12. Exactly 4 of the preceding statements are true.
A12 #<==> A1 + A2 + A3 + A4 + A5 + A6 + A7 +A8 + A9 + A10 + A11 #= 4,
label(L),
numlist(1, 12, NL),
write('Statements '),
maplist(my_write, NL, L),
writeln('are true').
my_write(N, 1) :-
format('~w ', [N]).
my_write(_N, 0).

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from itertools import product
#from pprint import pprint as pp
constraintinfo = (
(lambda st: len(st) == 12 ,(1, 'This is a numbered list of twelve statements')),
(lambda st: sum(st[-6:]) == 3 ,(2, 'Exactly 3 of the last 6 statements are true')),
(lambda st: sum(st[1::2]) == 2 ,(3, 'Exactly 2 of the even-numbered statements are true')),
(lambda st: (st[5]&st[6]) if st[4] else 1 ,(4, 'If statement 5 is true, then statements 6 and 7 are both true')),
(lambda st: sum(st[1:4]) == 0 ,(5, 'The 3 preceding statements are all false')),
(lambda st: sum(st[0::2]) == 4 ,(6, 'Exactly 4 of the odd-numbered statements are true')),
(lambda st: sum(st[1:3]) == 1 ,(7, 'Either statement 2 or 3 is true, but not both')),
(lambda st: (st[4]&st[5]) if st[6] else 1 ,(8, 'If statement 7 is true, then 5 and 6 are both true')),
(lambda st: sum(st[:6]) == 3 ,(9, 'Exactly 3 of the first 6 statements are true')),
(lambda st: (st[10]&st[11]) ,(10, 'The next two statements are both true')),
(lambda st: sum(st[6:9]) == 1 ,(11, 'Exactly 1 of statements 7, 8 and 9 are true')),
(lambda st: sum(st[0:11]) == 4 ,(12, 'Exactly 4 of the preceding statements are true')),
)
def printer(st, matches):
if False in matches:
print('Missed by one statement: %i, %s' % docs[matches.index(False)])
else:
print('Full match:')
print(' ' + ', '.join('%i:%s' % (i, 'T' if t else 'F') for i, t in enumerate(st, 1)))
funcs, docs = zip(*constraintinfo)
full, partial = [], []
for st in product( *([(False, True)] * 12) ):
truths = [bool(func(st)) for func in funcs]
matches = [s == t for s,t in zip(st, truths)]
mcount = sum(matches)
if mcount == 12:
full.append((st, matches))
elif mcount == 11:
partial.append((st, matches))
for stm in full + partial:
printer(*stm)

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/*REXX program solves the "Twelve Statement Puzzle". */
q=12; @stmt=right('statement',20) /*number of statements in the puzzle. */
m=0 /*[↓] statement one is TRUE by fiat.*/
do pass=1 for 2 /*find the maximum number of "trues". */
do e=0 for 2**(q-1); n = '1'right( x2b( d2x( e ) ), q-1, 0)
do b=1 for q /*define various bits in the number Q.*/
@.b=substr(n, b, 1) /*define a particular @ bit (in Q).*/
end /*b*/
if @.1 then if yeses(1, 1) \==1 then iterate
if @.2 then if yeses(7, 12) \==3 then iterate
if @.3 then if yeses(2, 12,2) \==2 then iterate
if @.4 then if yeses(5, 5) then if yeses(6, 7) \==2 then iterate
if @.5 then if yeses(2, 4) \==0 then iterate
if @.6 then if yeses(1, 12,2) \==4 then iterate
if @.7 then if yeses(2, 3) \==1 then iterate
if @.8 then if yeses(7, 7) then if yeses(5,6) \==2 then iterate
if @.9 then if yeses(1, 6) \==3 then iterate
if @.10 then if yeses(11,12) \==2 then iterate
if @.11 then if yeses(7, 9) \==1 then iterate
if @.12 then if yeses(1, 11) \==4 then iterate
g=yeses(1, 12)
if pass==1 then do; m=max(m,g); iterate; end
else if g\==m then iterate
do j=1 for q; z=substr(n, j, 1)
if z then say @stmt right(j, 2) " is " word('false true', 1 + z)
end /*tell*/
end /*e*/
end /*pass*/
exit /*stick a fork in it, we're all done. */
/*──────────────────────────────────────────────────────────────────────────────────────*/
yeses: parse arg L,H,B; #=0; do i=L to H by word(B 1, 1); #=#+@.i; end; return #

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/*REXX program solves the "Twelve Statement Puzzle". */
q=12; @stmt=right('statement',20) /*number of statements in the puzzle. */
m=0 /*[↓] statement one is TRUE by fiat.*/
do pass=1 for 2 /*find the maximum number of "trues". */
do e=0 for 2**(q-1); n = '1'right( x2b( d2x( e ) ), q-1, 0)
do b=1 for q /*define various bits in the number Q.*/
@.b=substr(n, b, 1) /*define a particular @ bit (in Q).*/
end /*b*/
if @.1 then if \ @.1 then iterate
if @.2 then if @.7+@.8+@.9+@.10+@.11+@.12 \==3 then iterate
if @.3 then if @.2+@.4+@.6+@.8+@.10+@.12 \==2 then iterate
if @.4 then if @.5 then if \(@.6 & @.7) then iterate
if @.5 then if @.2 | @.3 | @.4 then iterate
if @.6 then if @.1+@.3+@.5+@.7+@.9+@.11 \==4 then iterate
if @.7 then if \ (@.2 && @.3 ) then iterate
if @.8 then if @.7 then if \(@.5 & @.6) then iterate
if @.9 then if @.1+@.2+@.3+@.4+@.5+@.6 \==3 then iterate
if @.10 then if \ (@.11 & @.12) then iterate
if @.11 then if @.7+@.8+@.9 \==1 then iterate
g=@.1 +@.2 +@.3 +@.4 +@.5 +@.6 +@.7 +@.8+ @.9 +@.10 +@.11
if @.12 then if g \==4 then iterate
g=g + @.12
if pass==1 then do; m=max(m,g); iterate; end
else if g\==m then iterate
do j=1 for q; z=substr(n, j, 1)
if z then say @stmt right(j, 2) " is " word('false true', 1+z)
end /*tell*/
end /*e*/
end /*pass*/ /*stick a fork in it, we're all done. */

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/*REXX program solves the "Twelve Statement Puzzle". */
q=12; @stmt=right('statement',20) /*number of statements in the puzzle. */
m=0 /*[↓] statement one is TRUE by fiat.*/
do pass=1 for 2 /*find the maximum number of "trues". */
do e=0 for 2**(q-1); n = '1'right( x2b( d2x( e ) ), q-1, 0)
parse var n @1 2 @2 3 @3 4 @4 5 @5 6 @6 7 @7 8 @8 9 @9 10 @10 11 @11 12 @12
/*▒▒▒▒ if @1 then if \ @1 then iterate ▒▒▒▒*/
if @2 then if @7+@8+@9+@10+@11+@12 \==3 then iterate
if @3 then if @2+@4+@6+@8+@10+@12 \==2 then iterate
if @4 then if @5 then if \(@6 & @7) then iterate
if @5 then if @2 | @3 | @4 then iterate
if @6 then if @1+@3+@5+@7+@9+@11 \==4 then iterate
if @7 then if \ (@2 && @3 ) then iterate
if @8 then if @7 then if \(@5 & @6) then iterate
if @9 then if @1+@2+@3+@4+@5+@6 \==3 then iterate
if @10 then if \ (@11 & @12) then iterate
if @11 then if @7+@8+@9 \==1 then iterate
g=@1 + @2 + @3 + @4 + @5 + @6 + @7 + @8 + @9 + @10 + @11
if @12 then if g \==4 then iterate
g=g + @12
if pass==1 then do; m=max(m,g); iterate; end
else if g\==m then iterate
do j=1 for q; z=substr(n, j, 1)
if z then say @stmt right(j, 2) " is " word('false true', 1+z)
end /*j*/
end /*e*/
end /*pass*/ /*stick a fork in it, we're all done. */

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#lang racket
;; A quick `amb' implementation
(define failures null)
(define (fail)
(if (pair? failures) ((first failures)) (error "no more choices!")))
(define (amb/thunks choices)
(let/cc k (set! failures (cons k failures)))
(if (pair? choices)
(let ([choice (first choices)]) (set! choices (rest choices)) (choice))
(begin (set! failures (rest failures)) (fail))))
(define-syntax-rule (amb E ...) (amb/thunks (list (lambda () E) ...)))
(define (assert condition) (unless condition (fail)))
;; just to make things more fun
(define ( x y) (assert (eq? x y)))
(require (only-in racket [and ] [or ] [implies ] [xor ] [not ¬]))
(define (count xs)
(let loop ([n 0] [xs xs])
(if (null? xs) n (loop (if (car xs) (add1 n) n) (cdr xs)))))
;; even more fun, make []s infix
(require (only-in racket [#%app r:app]))
(define-syntax (#%app stx)
(if (not (eq? #\[ (syntax-property stx 'paren-shape)))
(syntax-case stx () [(_ x ...) #'(r:app x ...)])
(syntax-case stx ()
;; extreme hack on next two cases, so it works for macros too.
[(_ x op y) (syntax-property #'(op x y) 'paren-shape #f)]
[(_ x op y op1 z) (free-identifier=? #'op #'op1)
(syntax-property #'(op x y z) 'paren-shape #f)])))
;; might as well do more
(define-syntax-rule (define-booleans all x ...)
(begin (define x (amb #t #f)) ...
(define all (list x ...))))
(define (puzzle)
(define-booleans all q1 q2 q3 q4 q5 q6 q7 q8 q9 q10 q11 q12)
;; 1. This is a numbered list of twelve statements.
[q1 [12 = (length all)]]
;; 2. Exactly 3 of the last 6 statements are true.
[q2 [3 = (count (take-right all 6))]]
;; 3. Exactly 2 of the even-numbered statements are true.
[q3 [2 = (count (list q2 q4 q6 q8 q10 q12))]]
;; 4. If statement 5 is true, then statements 6 and 7 are both true.
[q4 [q5 [q6 q7]]]
;; 5. The 3 preceding statements are all false.
[q5 (¬ [q2 q3 q4])]
;; 6. Exactly 4 of the odd-numbered statements are true.
[q6 [4 = (count (list q1 q3 q5 q7 q9 q11))]]
;; 7. Either statement 2 or 3 is true, but not both.
[q7 [q2 q3]]
;; 8. If statement 7 is true, then 5 and 6 are both true.
[q8 [q7 (and q5 q6)]]
;; 9. Exactly 3 of the first 6 statements are true.
[q9 [3 = (count (take all 3))]]
;; 10. The next two statements are both true.
[q10 [q11 q12]]
;; 11. Exactly 1 of statements 7, 8 and 9 are true.
[q11 [1 = (count (list q7 q8 q9))]]
;; 12. Exactly 4 of the preceding statements are true.
[q12 [4 = (count (drop-right all 1))]]
;; done
(for/list ([i (in-naturals 1)] [q all] #:when q) i))
(puzzle)
;; -> '(1 3 4 6 7 11)

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sub infix:<> ($protasis, $apodosis) { !$protasis or $apodosis }
my @tests =
{ .end == 12 and all(.[1..12]) === any(True, False) },
{ 3 == [+] .[7..12] },
{ 2 == [+] .[2,4...12] },
{ .[5]all .[6,7] },
{ none .[2,3,4] },
{ 4 == [+] .[1,3...11] },
{ one .[2,3] },
{ .[7]all .[5,6] },
{ 3 == [+] .[1..6] },
{ all .[11,12] },
{ one .[7,8,9] },
{ 4 == [+] .[1..11] },
;
my @solutions;
my @misses;
for [X] (True, False) xx 12 {
my @assert = Nil, |$_;
my @result = Nil, |@tests.map({ ?.(@assert) });
my @true = @assert.grep(?*, :k);
my @cons = (@assert Z=== @result).grep(!*, :k);
given @cons {
when 0 { push @solutions, "<{@true}> is consistent."; }
when 1 { push @misses, "<{@true}> implies { "¬" if !@result[~$_] }$_." }
}
}
.say for @solutions;
say "";
say "Near misses:";
.say for @misses;

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constraints = [
->(st) { st.size == 12 },
->(st) { st.last(6).count(true) == 3 },
->(st) { st.each_slice(2).map(&:last).count(true) == 2 },
->(st) { st[4] ? (st[5] & st[6]) : true },
->(st) { st[1..3].none? },
->(st) { st.each_slice(2).map(&:first).count(true) == 4 },
->(st) { st[1] ^ st[2] },
->(st) { st[6] ? (st[4] & st[5]) : true },
->(st) { st.first(6).count(true) == 3 },
->(st) { st[10] & st[11] },
->(st) { st[6..8].one? },
->(st) { st[0,11].count(true) == 4 },
]
Result = Struct.new(:truths, :consistency)
results = [true, false].repeated_permutation(12).map do |truths|
Result.new(truths, constraints.zip(truths).map {|cn,truth| cn[truths] == truth })
end
puts "solution:",
results.find {|r| r.consistency.all? }.truths.to_s
puts "\nnear misses: "
near_misses = results.select {|r| r.consistency.count(false) == 1 }
near_misses.each do |r|
puts "missed by statement #{r.consistency.index(false) + 1}", r.truths.to_s
end

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class LogicPuzzle {
val s = new Array[Boolean](13)
var count = 0
def check2: Boolean = {
var count = 0
for (k <- 7 to 12) if (s(k)) count += 1
s(2) == (count == 3)
}
def check3: Boolean = {
var count = 0
for (k <- 2 to 12 by 2) if (s(k)) count += 1
s(3) == (count == 2)
}
def check4: Boolean = s(4) == (!s(5) || s(6) && s(7))
def check5: Boolean = s(5) == (!s(2) && !s(3) && !s(4))
def check6: Boolean = {
var count = 0
for (k <- 1 to 11 by 2) if (s(k)) count += 1
s(6) == (count == 4)
}
def check7: Boolean = s(7) == ((s(2) || s(3)) && !(s(2) && s(3)))
def check8: Boolean = s(8) == (!s(7) || s(5) && s(6))
def check9: Boolean = {
var count = 0
for (k <- 1 to 6) if (s(k)) count += 1
s(9) == (count == 3)
}
def check10: Boolean = s(10) == (s(11) && s(12))
def check11: Boolean = {
var count = 0
for (k <- 7 to 9) if (s(k)) count += 1
s(11) == (count == 1)
}
def check12: Boolean = {
var count = 0
for (k <- 1 to 11) if (s(k)) count += 1
s(12) == (count == 4)
}
def check(): Unit = {
if (check2 && check3 && check4 && check5 && check6 && check7 && check8 && check9 && check10 && check11 && check12) {
for (k <- 1 to 12) if (s(k)) print(k + " ")
println()
count += 1
}
}
def recurseAll(k: Int): Unit = {
if (k == 13) check()
else {
s(k) = false
recurseAll(k + 1)
s(k) = true
recurseAll(k + 1)
}
}
}
object LogicPuzzle extends App {
val p = new LogicPuzzle
p.s(1) = true
p.recurseAll(2)
println()
println(s"${p.count} Solutions found.")
}

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var conditions = [
{ false },
{|a| a.len == 13 },
{|a| [a[7..12]].count(true) == 3 },
{|a| [a[2..12 `by` 2]].count(true) == 2 },
{|a| a[5] ? (a[6] && a[7]) : true },
{|a| !a[2] && !a[3] && !a[4] },
{|a| [a[1..11 `by` 2]].count(true) == 4 },
{|a| a[2] == true^a[3] },
{|a| a[7] ? (a[5] && a[6]) : true },
{|a| [a[1..6]].count(true) == 3 },
{|a| [a[11,12]].count(true) == 2 },
{|a| [a[7..9]].count(true) == 1 },
{|a| [a[1..11]].count(true) == 4 },
]
func miss(args) {
1..12 -> grep {|i| conditions[i](args) != args[i] }
}
for k in (^(1<<12)) {
var t = ("0%012b" % k -> chars.map {|bit| bit == '1' })
var no = miss(t)
no.len == 0 && say "Solution: true statements are #{1..12->grep{t[_]}.join(' ')}"
no.len == 1 && say "1 miss (#{no[0]}): true statements are #{1..12->grep{t[_]}.join(' ')}"
}

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(defmacro defconstraints (name size-name (var) . forms)
^(progn (defvar ,size-name ,(length forms))
(defun ,name (,var)
(list ,*forms))))
(defconstraints con con-count (s)
(= (length s) con-count) ;; tautology
(= (countq t [s -6..t]) 3)
(= (countq t (mapcar (op if (evenp @1) @2) (range 1) s)) 2)
(if [s 4] (and [s 5] [s 6]) t)
(none [s 1..3])
(= (countq t (mapcar (op if (oddp @1) @2) (range 1) s)) 4)
(and (or [s 1] [s 2]) (not (and [s 1] [s 2])))
(if [s 6] (and [s 4] [s 5]) t)
(= (countq t [s 0..6]) 3)
(and [s 10] [s 11])
(= (countq t [s 6..9]) 1)
(= (countq t [s 0..con-count]) 4))
(defun true-indices (truths)
(mappend (do if @1 ^(,@2)) truths (range 1)))
(defvar results
(append-each ((truths (rperm '(nil t) con-count)))
(let* ((vals (con truths))
(consist [mapcar eq truths vals])
(wrong-count (countq nil consist))
(pos-wrong (+ 1 (or (posq nil consist) -2))))
(cond
((zerop wrong-count)
^((:----> ,*(true-indices truths))))
((= 1 wrong-count)
^((:close ,*(true-indices truths) (:wrong ,pos-wrong))))))))
(each ((r results))
(put-line `@r`))

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package require Tcl 8.6
# Function to evaluate the truth of a statement
proc tcl::mathfunc::S {idx} {
upvar 1 state s
apply [lindex $s [expr {$idx - 1}]] $s
}
# Procedure to count the number of statements which are true
proc S+ args {
upvar 1 state state
tcl::mathop::+ {*}[lmap i $args {expr {S($i)}}]
}
# Turn a list of expressions into a list of lambda terms
proc lambdas items {lmap x $items {list state [list expr $x]}}
# Find the truth assignment that produces consistency. And those that are
# near misses too.
proc findTruthMatch {statements} {
set n [llength $statements]
for {set i 0} {$i < 2**$n} {incr i} {
set state [split [format %0.*b $n $i] ""]
set truths [lmap f $statements {apply $f [lambdas $state]}]
set counteq [tcl::mathop::+ {*}[lmap s $state t $truths {expr {
$s == $t
}}]]
if {$counteq == $n} {
lappend exact $state
} elseif {$counteq == $n-1} {
set j 0
foreach s $state t $truths {
incr j
if {$s != $t} {
lappend differ $state $j
break
}
}
}
}
return [list $exact $differ]
}
# Rendering code
proc renderstate state {
return ([join [lmap s $state {
incr i
expr {$s ? "S($i)" : "\u00acS($i)"}
}] "\u22c0"])
}
# The statements, encoded as expressions
set statements {
{[llength $state] == 12}
{[S+ 7 8 9 10 11 12] == 3}
{[S+ 2 4 6 8 10 12] == 2}
{S(5) ? S(6) && S(7) : 1}
{[S+ 2 3 4] == 0}
{[S+ 1 3 5 7 9 11] == 4}
{S(2) != S(3)}
{S(7) ? S(5) && S(6) : 1}
{[S+ 1 2 3 4 5 6] == 3}
{S(11) && S(12)}
{[S+ 7 8 9] == 1}
{[S+ 1 2 3 4 5 6 7 8 9 10 11] == 4}
}
# Find the truth assignment(s) that give consistency
lassign [findTruthMatch [lambdas $statements]] exact differ
# Print the results
foreach state $exact {
puts "exact match\t[renderstate $state ]"
}
foreach {state j} $differ {
puts "almost found\t[renderstate $state] \u21d2 [expr {[lindex $state $j-1]?"\u00ac":{}}]S($j)"
}

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Public s As String '-- (eg "101101100010")
Public t As Integer '-- scratch
Function s1()
s1 = Len(s) = 12
End Function
Function s2()
t = 0
For i = 7 To 12
t = t - (Mid(s, i, 1) = "1")
Next i
s2 = t = 3
End Function
Function s3()
t = 0
For i = 2 To 12 Step 2
t = t - (Mid(s, i, 1) = "1")
Next i
s3 = t = 2
End Function
Function s4()
s4 = Mid(s, 5, 1) = "0" Or ((Mid(s, 6, 1) = "1" And Mid(s, 7, 1) = "1"))
End Function
Function s5()
s5 = Mid(s, 2, 1) = "0" And Mid(s, 3, 1) = "0" And Mid(s, 4, 1) = "0"
End Function
Function s6()
t = 0
For i = 1 To 12 Step 2
t = t - (Mid(s, i, 1) = "1")
Next i
s6 = t = 4
End Function
Function s7()
s7 = Mid(s, 2, 1) <> Mid(s, 3, 1)
End Function
Function s8()
s8 = Mid(s, 7, 1) = "0" Or (Mid(s, 5, 1) = "1" And Mid(s, 6, 1) = "1")
End Function
Function s9()
t = 0
For i = 1 To 6
t = t - (Mid(s, i, 1) = "1")
Next i
s9 = t = 3
End Function
Function s10()
s10 = Mid(s, 11, 1) = "1" And Mid(s, 12, 1) = "1"
End Function
Function s11()
t = 0
For i = 7 To 9
t = t - (Mid(s, i, 1) = "1")
Next i
s11 = t = 1
End Function
Function s12()
t = 0
For i = 1 To 11
t = t - (Mid(s, i, 1) = "1")
Next i
s12 = t = 4
End Function
Public Sub twelve_statements()
For i = 0 To 2 ^ 12 - 1
s = Right(CStr(WorksheetFunction.Dec2Bin(64 + i \ 128)), 5) _
& Right(CStr(WorksheetFunction.Dec2Bin(256 + i Mod 128)), 7)
For b = 1 To 12
Select Case b
Case 1: If s1 <> (Mid(s, b, 1) = "1") Then Exit For
Case 2: If s2 <> (Mid(s, b, 1) = "1") Then Exit For
Case 3: If s3 <> (Mid(s, b, 1) = "1") Then Exit For
Case 4: If s4 <> (Mid(s, b, 1) = "1") Then Exit For
Case 5: If s5 <> (Mid(s, b, 1) = "1") Then Exit For
Case 6: If s6 <> (Mid(s, b, 1) = "1") Then Exit For
Case 7: If s7 <> (Mid(s, b, 1) = "1") Then Exit For
Case 8: If s8 <> (Mid(s, b, 1) = "1") Then Exit For
Case 9: If s9 <> (Mid(s, b, 1) = "1") Then Exit For
Case 10: If s10 <> (Mid(s, b, 1) = "1") Then Exit For
Case 11: If s11 <> (Mid(s, b, 1) = "1") Then Exit For
Case 12: If s12 <> (Mid(s, b, 1) = "1") Then Exit For
End Select
If b = 12 Then Debug.Print s
Next
Next
End Sub

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import "/fmt" for Conv, Fmt
var predicates = [
Fn.new { |s| s.count == 13 }, // indexing starts at 0 but first bit ignored
Fn.new { |s| (7..12).count { |i| s[i] == "1" } == 3 },
Fn.new { |s| [2, 4, 6, 8, 10, 12].count { |i| s[i] == "1" } == 2 },
Fn.new { |s| s[5] == "0" || (s[6] == "1" && s[7] == "1") },
Fn.new { |s| s[2] == "0" && s[3] == "0" && s[4] == "0" },
Fn.new { |s| [1, 3, 5, 7, 9, 11].count { |i| s[i] == "1" } == 4 },
Fn.new { |s| Conv.itob(Conv.btoi(s[2] == "1") ^ Conv.btoi(s[3] == "1")) },
Fn.new { |s| s[7] == "0" || (s[5] == "1" && s[6] == "1") },
Fn.new { |s| (1..6).count { |i| s[i] == "1" } == 3 },
Fn.new { |s| s[11] == "1" && s[12] == "1" },
Fn.new { |s| (7..9).count { |i| s[i] == "1" } == 1 },
Fn.new { |s| (1..11).count { |i| s[i] == "1" } == 4 }
]
var show = Fn.new { |s, indent|
if (indent) System.write(" ")
for (i in 0...s.count) if (s[i] == "1") System.write("%(i) ")
System.print()
}
System.print("Exact hits:")
for (i in 0..4095) {
var s = Fmt.swrite("$013b", i)
var j = 1
if (predicates.all { |pred|
var res = pred.call(s) == (s[j] == "1")
j = j + 1
return res
}) show.call(s, true)
}
System.print("\nNear misses:")
for (i in 0..4095) {
var s = Fmt.swrite("$013b", i)
var j = 1
var c = predicates.count { |pred|
var res = pred.call(s) == (s[j] == "1")
j = j + 1
return res
}
if (c == 11) {
var k = 1
for (pred in predicates) {
if (pred.call(s) != (s[k] == "1") ) break
k = k + 1
}
Fmt.write(" (Fails at statement $2d) ", k)
show.call(s, false)
}
}

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\We have 12 statements to determine the truth/falsehood of (see task).
integer Stmt( 1+12 ), Expected( 1+12 );
\Logical-to-integer utility procedure
function ToInteger; int V ; return if V # 0 then 1 else 0;
\Procedure to determine whether the statements are true or not
procedure FindExpectedValues;
begin
Expected( 1 ) := true;
Expected( 2 ) := 3 = ( ToInteger( Stmt( 7 ) ) + ToInteger( Stmt( 8 ) )
+ ToInteger( Stmt( 9 ) ) + ToInteger( Stmt( 10 ) )
+ ToInteger( Stmt( 11 ) ) + ToInteger( Stmt( 12 ) )
);
Expected( 3 ) := 2 = ( ToInteger( Stmt( 2 ) ) + ToInteger( Stmt( 4 ) )
+ ToInteger( Stmt( 6 ) ) + ToInteger( Stmt( 8 ) )
+ ToInteger( Stmt( 10 ) ) + ToInteger( Stmt( 12 ) )
);
Expected( 4 ) := ( not Stmt( 5 ) ) or ( Stmt( 6 ) and Stmt( 7 ) );
Expected( 5 ) := not ( Stmt( 2 ) or Stmt( 3 ) or Stmt( 4 ) );
Expected( 6 ) := 4 = ( ToInteger( Stmt( 1 ) ) + ToInteger( Stmt( 3 ) )
+ ToInteger( Stmt( 5 ) ) + ToInteger( Stmt( 7 ) )
+ ToInteger( Stmt( 9 ) ) + ToInteger( Stmt( 11 ) )
);
Expected( 7 ) := Stmt( 2 ) # Stmt( 3 );
Expected( 8 ) := ( not Stmt( 7 ) ) or ( Stmt( 5 ) and Stmt( 6 ) );
Expected( 9 ) := 3 = ( ToInteger( Stmt( 1 ) ) + ToInteger( Stmt( 2 ) )
+ ToInteger( Stmt( 3 ) ) + ToInteger( Stmt( 4 ) )
+ ToInteger( Stmt( 5 ) ) + ToInteger( Stmt( 6 ) )
);
Expected( 10 ) := Stmt( 11 ) and Stmt( 12 );
Expected( 11 ) := 1 = ( ToInteger( Stmt( 7 ) )
+ ToInteger( Stmt( 8 ) )
+ ToInteger( Stmt( 9 ) )
);
Expected( 12 ) := 4 = ( ToInteger( Stmt( 1 ) ) + ToInteger( Stmt( 2 ) )
+ ToInteger( Stmt( 3 ) ) + ToInteger( Stmt( 4 ) )
+ ToInteger( Stmt( 5 ) ) + ToInteger( Stmt( 6 ) )
+ ToInteger( Stmt( 7 ) ) + ToInteger( Stmt( 8 ) )
+ ToInteger( Stmt( 9 ) ) + ToInteger( Stmt( 10 ) )
+ ToInteger( Stmt( 11 ) )
);
end; \FindExpectedValues
\Clearly, statement 1 is true. However to enumerate the near
\ solutions, we need to consider "solutions" where statement 1 is false.
\We iterate through the possibilities for the statements,
\ looking for a non-contradictory set of values.
\We print the solutions with allowedContradictions contradictions
procedure PrintSolutions ( AllowedContradictions, Heading ) ;
integer AllowedContradictions, Heading;
integer Wrong( 1+12 );
integer Solution, N, Incorrect, DPos, S;
begin
Text(0, Heading ); CrLf(0);
Text(0, " 1 2 3 4 5 6 7 8 9 10 11 12^m^j" );
Text(0, " ====================================^m^j" );
\There are 12 statements, so we have 2^12 possible combinations
for Solution := 1 to 4096 do begin
\Convert the number to the set of true/false values
N := Solution;
for DPos := 1 to 12 do begin
Stmt( DPos ) := (N & 1) # 0; \very odd
N := N / 2;
end; \for_DPos
\Get the expected values of the statements based on suggested values
FindExpectedValues;
\Count contradictions. If the required number, print solution
Incorrect := 0;
for DPos := 1 to 12 do begin
Wrong( DPos ) := Expected( DPos ) # Stmt( DPos );
Incorrect := Incorrect + ToInteger( Wrong( DPos ) );
end; \for_DPos
if Incorrect = AllowedContradictions then begin
\Have a solution
Text(0, " " );
for S := 1 to 12 do begin
Text(0, " ");
Text(0, if Stmt( S ) then "T" else "-");
Text(0, if Wrong( S ) then "*" else " ");
end;
CrLf(0);
end;
end; \for_solution
end; \PrintSolutions
begin
\Find complete solutions
PrintSolutions( 0, "Solutions" );
\Find near solutions
PrintSolutions( 1, "Near solutions (incorrect values marked ^"*^")" );
end

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sub s1() return len(s$)=12 end sub
sub s2() local t, i : t=0 : for i=7 to 12 : t = t + (mid$(s$, i, 1) <> "0") : next : return t=3 end sub
sub s3() local t, i : t=0 : for i=2 to 12 step 2 : t = t + (mid$(s$, i, 1) <> "0") : next : return t=2 end sub
sub s4() return mid$(s$, 5, 1) = "0" or (mid$(s$, 6, 1) <> "0" and mid$(s$, 7, 1) <> "0") end sub
sub s5() return mid$(s$, 2, 1) = "0" and mid$(s$, 3, 1) = "0" and mid$(s$, 4, 1) = "0" end sub
sub s6() local t, i : t=0 : for i=1 to 12 step 2 : t = t + mid$(s$, i, 1) <> "0" : next : return t=4 end sub
sub s7() return mid$(s$, 2, 1) <> mid$(s$, 3, 1) end sub
sub s8() return mid$(s$, 7, 1) = "0" or (mid$(s$, 5, 1) <> "0" and mid$(s$, 6, 1) <> "0") end sub
sub s9() local t, i : t=0 : for i=1 to 6 : t = t + mid$(s$, i, 1) <> "0" : next : return t=3 end sub
sub s10() return mid$(s$, 11, 1) <> "0" and mid$(s$, 12, 1) <> "0" end sub
sub s11() local t, i : t=0 : for i=7 to 9 : t = t + mid$(s$, i, 1) <> "0" : next : return t=1 end sub
sub s12() local t, i : t=0 : for i=1 to 11 : t = t + mid$(s$, i, 1) <> "0" : next : return t=4 end sub
dim r$(12)
for b=1 to 12
r$(b) = "s"+str$(b)
next
for i=0 to 2^12-1
s$ = right$("000000000000" + bin$(i), 12)
for b=1 to 12
if execute(r$(b)) <> (mid$(s$, b, 1) <> "0") break
if b=12 print s$
next
next

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var statements; // list of 13 Bools, statements[0] is garbage to make 1 based
fcn s0 { False } // dummy for padding
fcn s1 { True }
fcn s2 { statements[-6,*].filter().len()==3 }
fcn s3 { [2..12,2].apply(statements.get).filter().len()==2 }
fcn s4 { if(statements[5]) statements[6]==statements[7]==True else True }
fcn s5 { statements[2,3].filter().len()==0 }
fcn s6 { [1..12,2].apply(statements.get).filter().len()==4 }
fcn s7 { statements[2]!=statements[3] }
fcn s8 { if(statements[7]) statements[5]==statements[6]==True else True }
fcn s9 { statements[1,6].filter().len()==3 }
fcn s10{ statements[11]==statements[12]==True }
fcn s11{ statements[7,3].filter().len()==1 }
fcn s12{ statements[1,11].filter().len()==4 }
filters:=T(s0,s1,s2,s3,s4,s5,s6,s7,s8,s9,s10,s11,s12);
foreach n in ((2).pow(12)){ // 4k
// 5-->"0000000000101"-->("0","0"..."1")-->(F,F,...T)
statements="%013.2B".fmt(n).split("").apply('==("1"));
r:=filters.run(True); // and return list of results
if(r==statements) print("<<<<<<<<<<<<<<<<Solution");
else{
diff:=r.zipWith('!=,statements);
if(diff.sum(0)==1) print("Diff @",diff.filter1n());
}
}
fcn print(msg){
(12).pump(List,'wrap(n){ statements[n] and n or Void.Skip })
.concat(",").println(" : ",vm.pasteArgs());
}