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Ingy döt Net 2023-07-01 11:58:00 -04:00
parent 7387c8f97b
commit cb5bb5e222
199093 changed files with 3378972 additions and 0 deletions

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immutable TProblem{T<:Integer,U<:String}
sd::Array{Array{T,1},1}
toc::Array{T,2}
labels::Array{Array{U,1},1}
tsort::Array{Array{T,2}, 1}
end
function TProblem{T<:Integer,U<:String}(s::Array{T,1},
d::Array{T,1},
toc::Array{T,2},
slab::Array{U,1},
dlab::Array{U,1})
scnt = length(s)
dcnt = length(d)
size(toc) = (scnt,dcnt) || error("Supply, Demand, TOC Size Mismatch")
length(slab) == scnt || error("Supply Label Size Labels")
length(dlab) == dcnt || error("Demand Label Size Labels")
0 <= minimum(s) || error("Negative Supply Value")
0 <= minimum(d) || error("Negative Demand Value")
sd = Array{T,1}[]
push!(sd, s)
push!(sd, d)
labels = Array{U,1}[]
push!(labels, slab)
push!(labels, dlab)
tsort = Array{T,2}[]
push!(tsort, mapslices(sortperm, toc, 2))
push!(tsort, mapslices(sortperm, toc, 1))
TProblem(sd, toc, labels, tsort)
end
isbalanced(tp::TProblem) = sum(tp.sd[1]) == sum(tp.sd[2])
type Resource{T<:Integer}
dim::T
i::T
quant::T
l::T
m::T
p::T
q::T
end
function Resource{T<:Integer}(dim::T, i::T, quant::T)
zed = zero(T)
Resource(dim, i, quant, zed, zed, zed, zed)
end
isavailable(r::Resource) = 0 < r.quant
Base.isless(a::Resource, b::Resource) = a.p < b.p || (a.p == b.p && b.q < a.q)

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function penalize!{T<:Integer,U<:String}(sd::Array{Array{Resource{T},1},1},
tp::TProblem{T,U})
avail = BitArray{1}[]
for dim in 2:-1:1
push!(avail, bitpack(map(isavailable, sd[dim])))
end
for dim in 1:2, r in sd[dim]
if r.quant == 0
r.l = r.m = r.p = r.q = 0
continue
end
r.l == 0 || !avail[dim][r.l] || !avail[dim][r.m] || continue
rsort = filter(x->avail[dim][x], vec(slicedim(tp.tsort[dim],dim,r.i)))
rcost = vec(slicedim(tp.toc, dim, r.i))[rsort]
if length(rsort) == 1
r.l = r.m = rsort[1]
r.p = r.q = rcost[1]
else
r.l, r.m = rsort[1:2]
r.p = rcost[2] - rcost[1]
r.q = rcost[1]
end
end
nothing
end
function vogel{T<:Integer,U<:String}(tp::TProblem{T,U})
sdcnt = collect(size(tp.toc))
sol = spzeros(T, sdcnt[1], sdcnt[2])
sd = Array{Resource{T},1}[]
for dim in 1:2
push!(sd, [Resource(dim, i, tp.sd[dim][i]) for i in 1:sdcnt[dim]])
end
while any(map(isavailable, sd[1])) && any(map(isavailable, sd[2]))
penalize!(sd, tp)
a = maximum([sd[1], sd[2]])
b = sd[rem1(a.dim+1,2)][a.l]
if a.dim == 2 # swap to make a supply and b demand
a, b = b, a
end
expend = min(a.quant, b.quant)
sol[a.i, b.i] = expend
a.quant -= expend
b.quant -= expend
end
return sol
end

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using Printf
sup = [50, 60, 50, 50]
slab = ["W", "X", "Y", "Z"]
dem = [30, 20, 70, 30, 60]
dlab = ["A", "B", "C", "D", "E"]
c = [16 16 13 22 17;
14 14 13 19 15;
19 19 20 23 50;
50 12 50 15 11]
tp = TProblem(sup, dem, c, slab, dlab)
sol = vogel(tp)
cost = sum(tp.toc .* sol)
println("The solution is:")
print(" ")
for s in tp.labels[2]
print(@sprintf "%4s" s)
end
println()
for i in 1:size(tp.toc)[1]
print(@sprintf " %4s" tp.labels[1][i])
for j in 1:size(tp.toc)[2]
print(@sprintf "%4d" sol[i,j])
end
println()
end
println("The total cost is: ", cost)