This commit is contained in:
Ingy döt Net 2013-04-10 21:29:02 -07:00
parent 764da6cbbb
commit db842d013d
19005 changed files with 197040 additions and 7 deletions

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Create a routine that, given a set of strings representing directory paths and a single character directory separator, will return a string representing that part of the directory tree that is common to all the directories.
Test your routine using the forward slash '/' character as the directory separator and the following three strings as input paths:
'/home/user1/tmp/coverage/test'
'/home/user1/tmp/covert/operator'
'/home/user1/tmp/coven/members'
Note: The resultant path should be the valid directory <code>'/home/user1/tmp'</code> and not the longest common string <code>'/home/user1/tmp/cove'</code>.<br>
If your language has a routine that performs this function (even if it does not have a changeable separator character), then mention it as part of the task.

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# Utilities code #
CHAR dir sep = "/"; # Assume POSIX #
PROC dir name = (STRING dir)STRING: (
STRING out;
FOR pos FROM UPB dir BY -1 TO LWB dir DO
IF dir[pos] = dir sep THEN
out := dir[:pos-1];
GO TO out exit
FI
OD;
# else: # out:="";
out exit: out
);
PROC shortest = ([]STRING string list)STRING: (
INT min := max int;
INT min key := LWB string list - 1;
FOR key FROM LWB string list TO UPB string list DO
IF UPB string list[key][@1] < min THEN
min := UPB string list[key][@1];
min key := key
FI
OD;
string list[min key]
);
# Actual code #
PROC common prefix = ([]STRING strings)STRING: (
IF LWB strings EQ UPB strings THEN
# exit: # strings[LWB strings]
ELSE
STRING prefix := shortest(strings);
FOR pos FROM LWB prefix TO UPB prefix DO
CHAR first = prefix[pos];
FOR key FROM LWB strings+1 TO UPB strings DO
IF strings[key][@1][pos] NE first THEN
prefix := prefix[:pos-1];
GO TO prefix exit
FI
OD
OD;
prefix exit: prefix
FI
);
# Test code #
test:(
[]STRING dir list = (
"/home/user1/tmp/coverage/test",
"/home/user1/tmp/covert/operator",
"/home/user1/tmp/coven/members"
);
print((dir name(common prefix(dir list)), new line))
)

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# Finds the longest common directory of paths[1], paths[2], ...,
# paths[count], where sep is a single-character directory separator.
function common_dir(paths, count, sep, b, c, f, i, j, p) {
if (count < 1)
return ""
p = "" # Longest common prefix
f = 0 # Final index before last sep
# Loop for c = each character of paths[1].
for (i = 1; i <= length(paths[1]); i++) {
c = substr(paths[1], i, 1)
# If c is not the same in paths[2], ..., paths[count]
# then break both loops.
b = 0
for (j = 2; j <= count; j++) {
if (c != substr(paths[j], i, 1)) {
b = 1
break
}
}
if (b)
break
# Append c to prefix. Update f.
p = p c
if (c == sep)
f = i - 1
}
# Return only f characters of prefix.
return substr(p, 1, f)
}
BEGIN {
a[1] = "/home/user1/tmp/coverage/test"
a[2] = "/home/user1/tmp/covert/operator"
a[3] = "/home/user1/tmp/coven/members"
print common_dir(a, 3, "/")
}

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with Ada.Text_IO; use Ada.Text_IO;
procedure Test_Common_Path is
function "rem" (A, B : String) return String is
Slash : Integer := A'First; -- At the last slash seen in A
At_A : Integer := A'first;
At_B : Integer := B'first;
begin
loop
if At_A > A'Last then
if At_B > B'Last or else B (At_B) = '/' then
return A;
else
return A (A'First..Slash - 1);
end if;
elsif At_B > B'Last then
if A (At_A) = '/' then -- A cannot be shorter than B here
return B;
else
return A (A'First..Slash - 1);
end if;
elsif A (At_A) /= B (At_B) then
return A (A'First..Slash - 1);
elsif A (At_A) = '/' then
Slash := At_A;
end if;
At_A := At_A + 1;
At_B := At_B + 1;
end loop;
end "rem";
begin
Put_Line
( "/home/user1/tmp/coverage/test" rem
"/home/user1/tmp/covert/operator" rem
"/home/user1/tmp/coven/members"
);
end Test_Common_Path;

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Dir1 := "/home/user1/tmp/coverage/test"
Dir2 := "/home/user1/tmp/covert/operator"
Dir3 := "/home/user1/tmp/coven/members"
StringSplit, Dir1_, Dir1, /
StringSplit, Dir2_, Dir2, /
StringSplit, Dir3_, Dir3, /
Loop
If (Dir1_%A_Index% = Dir2_%A_Index%)
And (Dir1_%A_Index% = Dir3_%A_Index%)
Result .= (A_Index=1 ? "" : "/") Dir1_%A_Index%
Else Break
MsgBox, % Result

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DECLARE FUNCTION commonPath$ (paths() AS STRING, pathSep AS STRING)
DATA "/home/user2", "/home/user1/tmp/covert/operator", "/home/user1/tmp/coven/members"
DIM x(0 TO 2) AS STRING, n AS INTEGER
FOR n = 0 TO 2
READ x(n)
NEXT
PRINT "Common path is '"; commonPath$(x(), "/"); "'"
FUNCTION commonPath$ (paths() AS STRING, pathSep AS STRING)
DIM tmpint1 AS INTEGER, tmpint2 AS INTEGER, tmpstr1 AS STRING, tmpstr2 AS STRING
DIM L0 AS INTEGER, L1 AS INTEGER, lowerbound AS INTEGER, upperbound AS INTEGER
lowerbound = LBOUND(paths): upperbound = UBOUND(paths)
IF (lowerbound) = upperbound THEN 'Some quick error checking...
commonPath$ = paths(lowerbound)
ELSEIF lowerbound > upperbound THEN 'How in the...?
commonPath$ = ""
ELSE
tmpstr1 = paths(lowerbound)
FOR L0 = (lowerbound + 1) TO upperbound 'Find common strings.
tmpstr2 = paths(L0)
tmpint1 = LEN(tmpstr1)
tmpint2 = LEN(tmpstr2)
IF tmpint1 > tmpint2 THEN tmpint1 = tmpint2
FOR L1 = 1 TO tmpint1
IF MID$(tmpstr1, L1, 1) <> MID$(tmpstr2, L1, 1) THEN
tmpint1 = L1 - 1
EXIT FOR
END IF
NEXT
tmpstr1 = LEFT$(tmpstr1, tmpint1)
NEXT
IF RIGHT$(tmpstr1, 1) <> pathSep THEN
FOR L1 = tmpint1 TO 2 STEP -1
IF (pathSep) = MID$(tmpstr1, L1, 1) THEN
tmpstr1 = LEFT$(tmpstr1, L1 - 1)
EXIT FOR
END IF
NEXT
IF LEN(tmpstr1) = tmpint1 THEN tmpstr1 = ""
ELSEIF tmpint1 > 1 THEN
tmpstr1 = LEFT$(tmpstr1, tmpint1 - 1)
END IF
commonPath$ = tmpstr1
END IF
END FUNCTION

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DIM path$(3)
path$(1) = "/home/user1/tmp/coverage/test"
path$(2) = "/home/user1/tmp/covert/operator"
path$(3) = "/home/user1/tmp/coven/members"
PRINT FNcommonpath(path$(), "/")
END
DEF FNcommonpath(p$(), s$)
LOCAL I%, J%, O%
REPEAT
O% = I%
I% = INSTR(p$(1), s$, I%+1)
FOR J% = 2 TO DIM(p$(), 1)
IF LEFT$(p$(1), I%) <> LEFT$(p$(J%), I%) EXIT REPEAT
NEXT J%
UNTIL I% = 0
= LEFT$(p$(1), O%-1)

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#include <algorithm>
#include <iostream>
#include <string>
#include <vector>
std::string longestPath( const std::vector<std::string> & , char ) ;
int main( ) {
std::string dirs[ ] = {
"/home/user1/tmp/coverage/test" ,
"/home/user1/tmp/covert/operator" ,
"/home/user1/tmp/coven/members" } ;
std::vector<std::string> myDirs ( dirs , dirs + 3 ) ;
std::cout << "The longest common path of the given directories is "
<< longestPath( myDirs , '/' ) << "!\n" ;
return 0 ;
}
std::string longestPath( const std::vector<std::string> & dirs , char separator ) {
std::vector<std::string>::const_iterator vsi = dirs.begin( ) ;
int maxCharactersCommon = vsi->length( ) ;
std::string compareString = *vsi ;
for ( vsi = dirs.begin( ) + 1 ; vsi != dirs.end( ) ; vsi++ ) {
std::pair<std::string::const_iterator , std::string::const_iterator> p =
std::mismatch( compareString.begin( ) , compareString.end( ) , vsi->begin( ) ) ;
if (( p.first - compareString.begin( ) ) < maxCharactersCommon )
maxCharactersCommon = p.first - compareString.begin( ) ;
}
std::string::size_type found = compareString.rfind( separator , maxCharactersCommon ) ;
return compareString.substr( 0 , found ) ;
}

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#include <stdio.h>
int common_len(const char *const *names, int n, char sep)
{
int i, pos;
for (pos = 0; ; pos++) {
for (i = 0; i < n; i++) {
if (names[i][pos] != '\0' &&
names[i][pos] == names[0][pos])
continue;
/* backtrack */
while (pos > 0 && names[0][--pos] != sep);
return pos;
}
}
return 0;
}
int main()
{
const char *names[] = {
"/home/user1/tmp/coverage/test",
"/home/user1/tmp/covert/operator",
"/home/user1/tmp/coven/members",
};
int len = common_len(names, sizeof(names) / sizeof(const char*), '/');
if (!len) printf("No common path\n");
else printf("Common path: %.*s\n", len, names[0]);
return 0;
}

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Common path: /home/user1/tmp

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(use '[clojure.string :only [join,split]])
(defn common-prefix [sep paths]
(let [parts-per-path (map #(split % (re-pattern sep)) paths)
parts-per-position (apply map vector parts-per-path)]
(join sep
(for [parts parts-per-position :while (apply = parts)]
(first parts)))))
(println
(common-prefix "/"
["/home/user1/tmp/coverage/test"
"/home/user1/tmp/covert/operator"
"/home/user1/tmp/coven/members"]))

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import std.stdio, std.string, std.algorithm, std.path, std.array;
string commonDirPath(in string[] paths, in string sep = "/")
/*pure nothrow*/ {
if (paths.empty)
return null;
return paths.map!(p => p.split(sep)).reduce!commonPrefix.join(sep);
}
void main() {
auto paths = ["/home/user1/tmp/coverage/test",
"/home/user1/tmp/covert/operator",
"/home/user1/tmp/coven/members"];
writeln(`The common path is: "`, paths.commonDirPath, '"');
}

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: take-shorter ( seq1 seq2 -- shorter )
[ shorter? ] 2keep ? ;
: common-head ( seq1 seq2 -- head )
2dup mismatch [ nip head ] [ take-shorter ] if* ;
: common-prefix-1 ( file1 file2 separator -- prefix )
[ common-head ] dip '[ _ = not ] trim-tail ;
: common-prefix ( seq separator -- prefix )
[ ] swap '[ _ common-prefix-1 ] map-reduce ;

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10 REM All GOTO statements can be replaced with EXIT FOR in newer BASICs.
110 X$ = "/home/user1/tmp/coverage/test"
120 Y$ = "/home/user1/tmp/covert/operator"
130 Z$ = "/home/user1/tmp/coven/members"
150 A = LEN(X$)
160 IF A > LEN(Y$) THEN A = LEN(Y$)
170 IF A > LEN(Z$) THEN A = LEN(Z$)
180 FOR L0 = 1 TO A
190 IF MID$(X$, L0, 1) <> MID$(Y$, L0, 1) THEN GOTO 210
200 NEXT
210 A = L0 - 1
230 FOR L0 = 1 TO A
240 IF MID$(X$, L0, 1) <> MID$(Z$, L0, 1) THEN GOTO 260
250 NEXT
260 A = L0 - 1
280 IF MID$(X$, L0, 1) <> "/" THEN
290 FOR L0 = A TO 1 STEP -1
300 IF "/" = MID$(X$, L0, 1) THEN GOTO 340
310 NEXT
320 END IF
340 REM Task description says no trailing slash, so...
350 A = L0 - 1
360 P$ = LEFT$(X$, A)
370 PRINT "Common path is '"; P$; "'"

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package main
import(
"fmt"
"path"
"strings"
)
func CommonPrefix(sep string, paths ...string) (string) {
// Handle special cases.
switch len(paths) {
case 0:
return ""
case 1:
return path.Clean(paths[0])
}
c := []byte(path.Clean(paths[0]))
// Ignore the first path since it's already in c.
for _, v := range(paths[1:]) {
// Clean up each path before testing it.
v = path.Clean(v)
// Get the length of the shorter slice.
shorter := len(v)
if len(v) > len(c) {
shorter = len(c)
}
// Find the first non-common character and copy up to it into c.
for i := 0; i < shorter; i++ {
if v[i] != c[i] {
c = c[0:i]
break
}
}
}
// Correct for problem caused by prepending the actual common path to the
// list of paths searched through.
for _, v := range(paths) {
if len(v) > len(c) {
if strings.HasPrefix(v, string(c)) {
if len(v) > len(c) + len(sep) {
if v[len(c):len(c)+len(sep)] == sep {
c = append(c, []byte(sep)...)
break
}
}
}
}
}
// Remove trailing non-seperator characters.
for i := len(c)-1; i >= 0; i-- {
if i + len(sep) > len(c) {
continue
}
if string(c[i:i+len(sep)]) == sep {
c = c[0:i]
break
}
}
return string(c)
}
func main() {
c := CommonPrefix("/",
"/home/user1/tmp/coverage/test",
"/home/user1/tmp/covert/operator",
"/home/user1/tmp/coven/members",
)
fmt.Printf("%v\n", c)
}

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def commonPath = { delim, Object[] paths ->
def pathParts = paths.collect { it.split(delim) }
pathParts.transpose().inject([match:true, commonParts:[]]) { aggregator, part ->
aggregator.match = aggregator.match && part.every { it == part [0] }
if (aggregator.match) { aggregator.commonParts << part[0] }
aggregator
}.commonParts.join(delim)
}

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println commonPath('/',
'/home/user1/tmp/coverage/test',
'/home/user1/tmp/covert/operator',
'/home/user1/tmp/coven/members')
println commonPath('/',
'/home/user1/tmp/coverage/test',
'/home/user1/tmp/covert/test',
'/home/user1/tmp/coven/test',
'/home/user1/tmp/covers/test')

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import Data.List
-- Return the common prefix of two lists.
commonPrefix2 (x:xs) (y:ys) | x == y = x : commonPrefix2 xs ys
commonPrefix2 _ _ = []
-- Return the common prefix of zero or more lists.
commonPrefix (xs:xss) = foldr commonPrefix2 xs xss
commonPrefix _ = []
-- Split a string into path components.
splitPath = groupBy (\_ c -> c /= '/')
-- Return the common prefix of zero or more paths.
-- Note that '/' by itself is not considered a path component,
-- so "/" and "/foo" are treated as having nothing in common.
commonDirPath = concat . commonPrefix . map splitPath
main = putStrLn $ commonDirPath [
"/home/user1/tmp/coverage/test",
"/home/user1/tmp/covert/operator",
"/home/user1/tmp/coven/members"
]

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CHARACTER a='/home/user1/tmp/coverage/test', b='/home/user1/tmp/covert/operator', c='/home/user1/tmp/coven/members'
minLength = MIN( LEN(a), LEN(b), LEN(c) )
lastSlash = 0
DO i = 1, minLength
IF( (a(i) == b(i)) * (b(i) == c(i)) ) THEN
IF(a(i) == "/") lastSlash = i
ELSEIF( lastSlash ) THEN
WRITE(Messagebox) "Common Directory = ", a(1:lastSlash-1)
ELSE
WRITE(Messagebox, Name) "No common directory for", a, b, c
ENDIF
ENDDO

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procedure main()
write(lcdsubstr(["/home/user1/tmp/coverage/test","/home/user1/tmp/covert/operator","/home/user1/tmp/coven/members"]))
end
procedure lcdsubstr(sL,d) #: return the longest common sub-string of strings in the list sL delimited by d
local ss
/d := "/"
reverse(sL[1]) ? {
if tab(find(d)+*d) || allmatch(ss := reverse(tab(0)),sL) then
return ss
}
end
procedure allmatch(s,L) #: retrun s if it matches all strings in L
local x
every x := !L do
if not match(s,x) then fail
return s
end

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parseDirs =: = <;.2 ]
getCommonPrefix =: {. ;@{.~ 0 i.~ *./@(="1 {.)
getCommonDirPath=: [: getCommonPrefix parseDirs&>

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paths=: '/home/user1/tmp/coverage/test';'/home/user1/tmp/covert/operator';'/home/user1/tmp/coven/members'
getCommonPrefix >paths
/home/user1/tmp/cove
'/' getCommonDirPath paths
/home/user1/tmp/

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parseDirs =: (PATHSEP_j_&= <;.2 ])@jhostpath

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public class CommonPath {
public static String commonPath(String... paths){
String commonPath = "";
String[][] folders = new String[paths.length][];
for(int i = 0; i < paths.length; i++){
folders[i] = paths[i].split("/"); //split on file separator
}
for(int j = 0; j < folders[0].length; j++){
String thisFolder = folders[0][j]; //grab the next folder name in the first path
boolean allMatched = true; //assume all have matched in case there are no more paths
for(int i = 1; i < folders.length && allMatched; i++){ //look at the other paths
if(folders[i].length < j){ //if there is no folder here
allMatched = false; //no match
break; //stop looking because we've gone as far as we can
}
//otherwise
allMatched &= folders[i][j].equals(thisFolder); //check if it matched
}
if(allMatched){ //if they all matched this folder name
commonPath += thisFolder + "/"; //add it to the answer
}else{//otherwise
break;//stop looking
}
}
return commonPath;
}
public static void main(String[] args){
String[] paths = { "/home/user1/tmp/coverage/test",
"/home/user1/tmp/covert/operator",
"/home/user1/tmp/coven/members"};
System.out.println(commonPath(paths));
String[] paths2 = { "/hame/user1/tmp/coverage/test",
"/home/user1/tmp/covert/operator",
"/home/user1/tmp/coven/members"};
System.out.println(commonPath(paths2));
}
}

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path$(1) = "/home/user1/tmp/coverage/test"
path$(2) = "/home/user1/tmp/covert/operator"
path$(3) = "/home/user1/tmp/coven/members"
print samepath$(3,"/")
end
function samepath$(paths,sep$)
d = 1 'directory depth
n = 2 'path$(number)
while 1
if word$(path$(1),d,sep$) <> word$(path$(n),d,sep$) or word$(path$(1),d,sep$) = "" then exit while
n = n + 1
if n > paths then
if right$(samepath$,1) <> sep$ and d<>1 then
samepath$ = samepath$ + sep$ + word$(path$(1),d,sep$)
else
samepath$ = samepath$ + word$(path$(1),d,sep$)
end if
n = 2
d = d + 1
end if
wend
end function

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FCD
NEW D,SEP,EQ,LONG,DONE,I,J,K,RETURN
SET D(1)="/home/user1/tmp/coverage/test"
SET D(2)="/home/user1/tmp/covert/operator"
SET D(3)="/home/user1/tmp/coven/members"
SET SEP="/"
SET LONG=D(1)
SET DONE=0
FOR I=1:1:$LENGTH(LONG,SEP) QUIT:DONE SET EQ(I)=1 FOR J=2:1:3 SET EQ(I)=($PIECE(D(J),SEP,I)=$PIECE(LONG,SEP,I))&EQ(I) SET DONE='EQ(I) QUIT:'EQ(I)
SET RETURN=""
FOR K=1:1:I-1 Q:'EQ(K) SET:EQ(K) $PIECE(RETURN,SEP,K)=$PIECE(LONG,SEP,K)
WRITE !,"For the paths:" FOR I=1:1:3 WRITE !,D(I)
WRITE !,"The longest common directory is: ",RETURN
KILL D,SEP,EQ,LONG,DONE,I,J,K,RETURN
QUIT

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FindCommonDirectory[x_] := If[StringTake[#, -1] != "/", StringTake[#, Max[StringPosition[#, "/"]]], #] &
[Fold[LongestCommonSubsequence, First[x] , Rest[x]]]
FindCommonDirectory[{"/home/user1/tmp/coverage/test", "/home/user1/tmp/covert/operator", "/home/user1/tmp/coven/members"}]
->"/home/user1/tmp/"

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scommon(a, b) := block([n: min(slength(a), slength(b))],
substring(a, 1, catch(for i thru n do (
if not cequal(charat(a, i), charat(b, i)) then throw(i)), n + 1)))$
commonpath(u, [l]) := block([s: lreduce(scommon, u), c, n],
n: sposition(if length(l) = 0 then "/" else l[1], sreverse(s)),
if integerp(n) then substring(s, 1, slength(s) - n) else ""
)$
commonpath(["c:/files/banister.jpg", "c:/files/bank.xls", "c:/files/banana-recipes.txt"]);
"c:/files"

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<?php
/*
This works with dirs and files in any number of combinations.
*/
function _commonPath($dirList)
{
$arr = array();
foreach($dirList as $i => $path)
{
$dirList[$i] = explode('/', $path);
unset($dirList[$i][0]);
$arr[$i] = count($dirList[$i]);
}
$min = min($arr);
for($i = 0; $i < count($dirList); $i++)
{
while(count($dirList[$i]) > $min)
{
array_pop($dirList[$i]);
}
$dirList[$i] = '/' . implode('/' , $dirList[$i]);
}
$dirList = array_unique($dirList);
while(count($dirList) !== 1)
{
$dirList = array_map('dirname', $dirList);
$dirList = array_unique($dirList);
}
reset($dirList);
return current($dirList);
}
/* TEST */
$dirs = array(
'/home/user1/tmp/coverage/test',
'/home/user1/tmp/covert/operator',
'/home/user1/tmp/coven/members',
);
if('/home/user1/tmp' !== common_path($dirs))
{
echo 'test fail';
} else {
echo 'test success';
}
?>

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<?php
/* A more compact string-only version, which I assume would be much faster */
/* If you want the trailing /, return $common; */
function getCommonPath($paths) {
$lastOffset = 1;
$common = '/';
while (($index = strpos($paths[0], '/', $lastOffset)) !== FALSE) {
$dirLen = $index - $lastOffset + 1; // include /
$dir = substr($paths[0], $lastOffset, $dirLen);
foreach ($paths as $path) {
if (substr($path, $lastOffset, $dirLen) != $dir)
return $common;
}
$common .= $dir;
$lastOffset = $index + 1;
}
return substr($common, 0, -1);
}
?>

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use List::Util qw(max reduce);
sub compath {
my ($sep, @paths, %hash) = @_;
# Tokenize and tally subpaths
foreach (@paths) {
my @tok = split $sep, substr($_,1);
++$hash{join $sep, @tok[0..$_]} for (0..$#tok); }
# Return max length subpath or null
my $max = max values %hash;
return '' unless $max == @paths;
my @res = grep {$hash{$_} == $max} keys %hash;
return $sep . reduce { length $a > length $b ? $a : $b } @res;
}
# Test and display
my @paths = qw(/home/user1/tmp/coverage/test
/home/user1/tmp/covert/operator
/home/user1/tmp/coven/members);
print compath('/', @paths), "\n";

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(de commonPath (Lst Chr)
(glue Chr
(make
(apply find
(mapcar '((L) (split (chop L) Chr)) Lst)
'(@ (or (pass <>) (nil (link (next))))) ) ) ) )

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>>> import os
>>> os.path.commonprefix(['/home/user1/tmp/coverage/test',
'/home/user1/tmp/covert/operator', '/home/user1/tmp/coven/members'])
'/home/user1/tmp/cove'

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>>> def commonprefix(*args, sep='/'):
return os.path.commonprefix(*args).rpartition(sep)[0]
>>> commonprefix(['/home/user1/tmp/coverage/test',
'/home/user1/tmp/covert/operator', '/home/user1/tmp/coven/members'])
'/home/user1/tmp'

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>>> from itertools import takewhile
>>> def allnamesequal(name):
return all(n==name[0] for n in name[1:])
>>> def commonprefix(paths, sep='/'):
bydirectorylevels = zip(*[p.split(sep) for p in paths])
return sep.join(x[0] for x in takewhile(allnamesequal, bydirectorylevels))
>>> commonprefix(['/home/user1/tmp/coverage/test',
'/home/user1/tmp/covert/operator', '/home/user1/tmp/coven/members'])
'/home/user1/tmp'
>>> # And also
>>> commonprefix(['/home/user1/tmp', '/home/user1/tmp/coverage/test',
'/home/user1/tmp/covert/operator', '/home/user1/tmp/coven/members'])
'/home/user1/tmp'
>>>

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get_common_dir <- function(paths, delim = "/")
{
path_chunks <- strsplit(paths, delim)
i <- 1
repeat({
current_chunk <- sapply(path_chunks, function(x) x[i])
if(any(current_chunk != current_chunk[1])) break
i <- i + 1
})
paste(path_chunks[[1]][seq_len(i - 1)], collapse = delim)
}
# Example Usage:
paths <- c(
'/home/user1/tmp/coverage/test',
'/home/user1/tmp/covert/operator',
'/home/user1/tmp/coven/members')
get_common_dir(paths) # "/home/user1/tmp"

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/*REXX program finds common directory path for a list of files. */
@.= /*define all file lists to null. */
@.1 = '/home/user1/tmp/coverage/test'
@.2 = '/home/user1/tmp/covert/operator'
@.3 = '/home/user1/tmp/coven/members'
L=length(@.1)
do j=2 while @.j\=='' /*start with the second string. */
_ = compare(@.j,@.1); if _==0 then iterate /*equal.*/
L = min(L,_) /*find the minimum equal strings.*/
end /*j*/
common = left(@.1,lastpos('/',@.1,L)) /*find the shortest DIR string.*/
if right(common,1)=='/' then common=left(common, max(0,length(common)-1))
say 'common directory path: ' common /*[↑] handle trailing / delimiter*/
/*stick a fork in it, we're done.*/

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require 'abbrev'
dirs = %w( /home/user1/tmp/coverage/test /home/user1/tmp/covert/operator /home/user1/tmp/coven/members )
common_prefix = dirs.abbrev.keys.min_by {|key| key.length}.chop # => "/home/user1/tmp/cove"
common_directory = common_prefix.sub(%r{/[^/]*$}, '') # => "/home/user1/tmp"

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separator = '/'
paths = dirs.collect {|dir| dir.split(separator)}
uncommon_idx = paths.transpose.each_with_index.find {|dirnames, idx| dirnames.uniq.length > 1}.last
common_directory = paths[0][0 ... uncommon_idx].join(separator) # => "/home/user1/tmp"

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package require Tcl 8.5
proc pop {varname} {
upvar 1 $varname var
set var [lassign $var head]
return $head
}
proc common_prefix {dirs {separator "/"}} {
set parts [split [pop dirs] $separator]
while {[llength $dirs]} {
set r {}
foreach cmp $parts elt [split [pop dirs] $separator] {
if {$cmp ne $elt} break
lappend r $cmp
}
set parts $r
}
return [join $parts $separator]
}