This commit is contained in:
Ingy döt Net 2013-04-10 21:29:02 -07:00
parent 764da6cbbb
commit db842d013d
19005 changed files with 197040 additions and 7 deletions

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Provide code that produces a list of numbers which is the n-th order forward difference, given a non-negative integer (specifying the order) and a list of numbers. The first-order forward difference of a list of numbers (A) is a new list (B) where B<sub>n</sub> = A<sub>n+1</sub> - A<sub>n</sub>. List B should have one fewer element as a result. The second-order forward difference of A will be the same as the first-order forward difference of B. That new list will have two fewer elements than A and one less than B. The goal of this task is to repeat this process up to the desired order.
For a more formal description, see the related [http://mathworld.wolfram.com/ForwardDifference.html Mathworld article].
Algorithmic options:
*Iterate through all previous forward differences and re-calculate a new array each time.
*Use this formula (from [[wp:Forward difference|Wikipedia]]):
:<math>\Delta^n [f](x)= \sum_{k=0}^n {n \choose k} (-1)^{n-k} f(x+k)</math>
:([[Pascal's Triangle]] may be useful for this option)

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---
note: Arithmetic operations

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main:(
MODE LISTREAL = [1:0]REAL;
OP - = (LISTREAL a,b)LISTREAL: (
[UPB a]REAL out;
FOR i TO UPB out DO out[i]:=a[i]-b[i] OD;
out
);
FORMAT real fmt=$zzz-d.d$;
FORMAT repeat fmt = $n(UPB s-1)(f(real fmt)",")f(real fmt)$;
FORMAT list fmt = $"("f(UPB s=1|real fmt|repeat fmt)")"$;
FLEX [1:0] REAL s := (90, 47, 58, 29, 22, 32, 55, 5, 55, 73);
printf((list fmt,s,$";"l$));
TO UPB s-1 DO
s := s[2:] - s[:UPB s-1];
printf((list fmt,s,$";"l$))
OD
)

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list 90 47 58 29 22 32 55 5 55 73
fd {=0:(-1)(1)-(¯1)}
1 fd list
¯43 11 ¯29 ¯7 10 23 ¯50 50 18
2 fd list
54 ¯40 22 17 13 ¯73 100 ¯32

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#!/usr/bin/awk -f
BEGIN {
if (p<1) {p = 1};
}
function diff(s, p) {
n = split(s, a, " ");
for (j = 1; j <= p; j++) {
for(i = 1; i <= n-j; i++) {
a[i] = a[i+1] - a[i];
}
}
s = "";
for (i = 1; i <= n-p; i++) s = s" "a[i];
return s;
}
{
print diff($0, p);
}

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#!/usr/bin/awk -f
BEGIN {
if (p<1) {p = 1};
}
function diff(s, p) {
# pascal triangled with sign changes
b[1] = (p%2) ? 1 : -1;
for (j=1; j < p; j++) {
b[j+1] = -b[j]*(p-j)/j;
};
n = split(s, a, " ");
s = "";
for (j = 1; j <= n-p+1; j++) {
c = 0;
for(i = 1; i <= p; i++) {
c += b[i]*a[j+i-1];
}
s = s" "c;
}
return s;
}
{
print diff($0, p);
}

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with Ada.Text_Io;
with Ada.Float_Text_Io; use Ada.Float_Text_Io;
with Ada.containers.Vectors;
procedure Forward_Difference is
package Flt_Vect is new Ada.Containers.Vectors(Positive, Float);
use Flt_Vect;
procedure Print(Item : Vector) is
begin
if not Item.Is_Empty then
Ada.Text_IO.Put('[');
for I in 1..Item.Length loop
Put(Item => Item.Element(Positive(I)), Fore => 1, Aft => 1, Exp => 0);
if Positive(I) < Positive(Item.Length) then
Ada.Text_Io.Put(", ");
end if;
end loop;
Ada.Text_Io.Put_line("]");
else
Ada.Text_IO.Put_Line("Empty List");
end if;
end Print;
function Diff(Item : Vector; Num_Passes : Natural) return Vector is
A : Vector := Item;
B : Vector := Empty_Vector;
begin
if not A.Is_Empty then
for I in 1..Num_Passes loop
for I in 1..Natural(A.Length) - 1 loop
B.Append(A.Element(I + 1) - A.Element(I));
end loop;
Move(Target => A, Source => B);
end loop;
end if;
return A;
end Diff;
Values : array(1..10) of Float := (90.0, 47.0, 58.0, 29.0, 22.0, 32.0, 55.0, 5.0, 55.0, 73.0);
A : Vector;
begin
for I in Values'range loop
A.Append(Values(I)); -- Fill the vector
end loop;
Print(Diff(A, 1));
Print(Diff(A, 2));
Print(Diff(A, 9));
Print(Diff(A, 10));
print(Diff(A, 0));
end Forward_Difference;

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MsgBox % diff("2,3,4,3",1)
MsgBox % diff("2,3,4,3",2)
MsgBox % diff("2,3,4,3",3)
MsgBox % diff("2,3,4,3",4)
diff(list,ord) { ; high order forward differences of a list
Loop %ord% {
L =
Loop Parse, list, `, %A_Space%%A_Tab%
If (A_Index=1)
p := A_LoopField
Else
L .= "," A_LoopField-p, p := A_LoopField
list := SubStr(L,2)
}
Return list
}

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DIM A(9)
A() = 90.0, 47.0, 58.0, 29.0, 22.0, 32.0, 55.0, 5.0, 55.0, 73.0
PRINT "Original array: " FNshowarray(A())
PROCforward_difference(1, A(), B())
PRINT "Forward diff 1: " FNshowarray(B())
PROCforward_difference(2, A(), C())
PRINT "Forward diff 2: " FNshowarray(C())
PROCforward_difference(9, A(), D())
PRINT "Forward diff 9: " FNshowarray(D())
END
DEF PROCforward_difference(n%, a(), RETURN b())
LOCAL c%, i%, j%
DIM b(DIM(a(),1) - n%)
FOR i% = 0 TO DIM(b(),1)
b(i%) = a(i% + n%)
c% = 1
FOR j% = 1 TO n%
c% = -INT(c% * (n% - j% + 1) / j% + 0.5)
b(i%) += c% * a(i% + n% - j%)
NEXT
NEXT
ENDPROC
DEF FNshowarray(a())
LOCAL i%, a$
FOR i% = 0 TO DIM(a(),1)
a$ += STR$(a(i%)) + ", "
NEXT
= LEFT$(LEFT$(a$))

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#include <vector>
#include <iterator>
#include <algorithm>
// calculate first order forward difference
// requires:
// * InputIterator is an input iterator
// * OutputIterator is an output iterator
// * The value type of InputIterator is copy-constructible and assignable
// * The value type of InputIterator supports operator -
// * The result type of operator- is assignable to the value_type of OutputIterator
// returns: The iterator following the output sequence
template<typename InputIterator, typename OutputIterator>
OutputIterator forward_difference(InputIterator first, InputIterator last,
OutputIterator dest)
{
// special case: for empty sequence, do nothing
if (first == last)
return dest;
typedef typename std::iterator_traits<InputIterator>::value_type value_type;
value_type temp = *first++;
while (first != last)
{
value_type temp2 = *first++;
*dest++ = temp2 - temp;
temp = temp2;
}
return dest;
}
// calculate n-th order forward difference.
// requires:
// * InputIterator is an input iterator
// * OutputIterator is an output iterator
// * The value type of InputIterator is copy-constructible and assignable
// * The value type of InputIterator supports operator -
// * The result type of operator- is assignable to the value_type of InputIterator
// * The result type of operator- is assignable to the value_type of OutputIterator
// * order >= 0
// returns: The iterator following the output sequence
template<typename InputIterator, typename OutputIterator>
OutputIterator nth_forward_difference(int order,
InputIterator first, InputIterator last,
OutputIterator dest)
{
// special case: If order == 0, just copy input to output
if (order == 0)
return std::copy(first, last, dest);
// second special case: If order == 1, just forward to the first-order function
if (order == 1)
return forward_difference(first, last, dest);
// intermediate results are stored in a vector
typedef typename std::iterator_traits<InputIterator>::value_type value_type;
std::vector<value_type> temp_storage;
// fill the vector with the result of the first order forward difference
forward_difference(first, last, std::back_inserter(temp_storage));
// the next n-2 iterations work directly on the vector
typename std::vector<value_type>::iterator begin = temp_storage.begin(),
end = temp_storage.end();
for (int i = 1; i < order-1; ++i)
end = forward_difference(begin, end, begin);
// the final iteration writes directly to the output iterator
return forward_difference(begin, end, dest);
}
// example usage code
#include <iostream>
int main()
{
double array[10] = { 90.0, 47.0, 58.0, 29.0, 22.0, 32.0, 55.0, 5.0, 55.0, 73.0 };
// this stores the results in the vector dest
std::vector<double> dest;
nth_forward_difference(1, array, array+10, std::back_inserter(dest));
// outut dest
std::copy(dest.begin(), dest.end(), std::ostream_iterator<double>(std::cout, " "));
std::cout << std::endl;
// however, the results can also be output as they are calculated
nth_forward_difference(2, array, array+10, std::ostream_iterator<double>(std::cout, " "));
std::cout << std::endl;
nth_forward_difference(9, array, array+10, std::ostream_iterator<double>(std::cout, " "));
std::cout << std::endl;
nth_forward_difference(10, array, array+10, std::ostream_iterator<double>(std::cout, " "));
std::cout << std::endl;
nth_forward_difference(0, array, array+10, std::ostream_iterator<double>(std::cout, " "));
std::cout << std::endl;
// finally, the results can also be written into the original array
// (which of course destroys the original content)
double* end = nth_forward_difference(3, array, array+10, array);
for (double* p = array; p < end; ++p)
std::cout << *p << " ";
std::cout << std::endl;
return 0;
}

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#include <iostream>
#include <numeric>
// Calculate the Forward Difference of a series if integers showing each order
//
// Nigel Galloway. August 20th., 2012
//
int main() {
int x[] = {NULL,-43,11,-29,-7,10,23,-50,50,18};
const int N = sizeof(x) / sizeof(int) - 1;
for (int ord = 0; ord < N - 1; ord++) {
std::adjacent_difference(x+1, x + N + 1 - ord, x);
for (int i = 1; i < N - ord; i++) std::cout << x[i] << ' ';
std::cout << std::endl;
}
return 0;
}

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#include <iostream>
#include <numeric>
// Calculate the Forward Difference of a series if integers
//
// Nigel Galloway. August 20th., 2012
//
int main() {
int x[] = {NULL,-43,11,-29,-7,10,23,-50,50,18};
const int N = sizeof(x) / sizeof(int) - 1;
for (int ord = 0; ord < N - 1; ord++) std::adjacent_difference(x+1, x + N + 1 - ord, x);
std::cout << x[1] << std::endl;
return 0;
}

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#include <iostream>
#include <algorithm>
// Calculate the Forward Difference of a series if integers using Pascal's Triangle
// For this example the 9th line of Pascal's Triangle is stored in P.
//
// Nigel Galloway. August 20th., 2012
//
int main() {
const int P[] = {1,-8,28,-56,70,-56,28,-8,1};
int x[] = {-43,11,-29,-7,10,23,-50,50,18};
std::transform(x, x + sizeof(x) / sizeof(int), P, x, std::multiplies<int>());
std::cout << std::accumulate(x, x + sizeof(x) / sizeof(int), 0) << std::endl;
return 0;
}

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using System;
using System.Collections.Generic;
using System.Linq;
class Program
{
static IEnumerable<int> ForwardDifference(IEnumerable<int> sequence, uint order = 1u)
{
switch (order)
{
case 0u:
return sequence;
case 1u:
return sequence.Skip(1).Zip(sequence, (next, current) => next - current);
default:
return ForwardDifference(ForwardDifference(sequence), order - 1u);
}
}
static void Main()
{
IEnumerable<int> sequence = new[] { 90, 47, 58, 29, 22, 32, 55, 5, 55, 73 };
do
{
Console.WriteLine(string.Join(", ", sequence));
} while ((sequence = ForwardDifference(sequence)).Any());
}
}

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#include <stdlib.h>
#include <string.h>
#include <stdio.h>
double* fwd_diff(double* x, unsigned int len, unsigned int order)
{
unsigned int i, j;
double* y;
/* handle two special cases */
if (order >= len) return 0;
y = malloc(sizeof(double) * len);
if (!order) {
memcpy(y, x, sizeof(double) * len);
return y;
}
/* first order diff goes from x->y, later ones go from y->y */
for (j = 0; j < order; j++, x = y)
for (i = 0, len--; i < len; i++)
y[i] = x[i + 1] - x[i];
y = realloc(y, sizeof(double) * len);
return y;
}
int main(void)
{
double *y, x[] = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73};
int i, len = sizeof(x) / sizeof(x[0]);
y = fwd_diff(x, len, 1);
for (i = 0; i < len - 1; i++)
printf("%g ", y[i]);
putchar('\n');
return 0;
}

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#include <stdio.h>
int* binomCoeff(int n) {
int *b = calloc(n+1,sizeof(int));
int j;
b[0] = n%2 ? -1 : 1;
for (j=1 ; j<=n; j++)
b[j] = -b[j-1]*(n+1-j)/j;
return(b);
};
main () {
double array[] = { 90, 47, 58, 29, 22, 32, 55, 5, 55, 73 };
size_t lenArray = sizeof(array)/sizeof(array[0]);
int p = 4; // order
int *b = binomCoeff(p); // pre-compute binomial coefficients for order p
int j, k;
// compute p-th difference
for (k=0 ; k < lenArray; k++)
for (array[k] *= b[0], j=1 ; j<=p; j++)
array[k] += b[j] * array[k+j];
free(b);
// resulting series is shorter by p elements
lenArray -= p;
for (k=0 ; k < lenArray; k++) printf("%f ",array[k]);
printf("\n");
}

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(defn fwd-diff [nums order]
(nth (iterate #(map - (next %) %) nums) order))

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forward_difference = (arr, n) ->
# Find the n-th order forward difference for arr using
# a straightforward recursive algorithm.
# Assume arr is integers and n <= arr.length.
return arr if n == 0
arr = forward_difference(arr, n-1)
(arr[i+1] - arr[i] for i in [0...arr.length - 1])
arr = [-1, 0, 1, 8, 27, 64, 125, 216]
for n in [0..arr.length]
console.log n, forward_difference arr, n

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(defun forward-difference (list)
(mapcar #'- (rest list) list))
(defun nth-forward-difference (list n)
(setf list (copy-list list))
(loop repeat n do (map-into list #'- (rest list) list))
(subseq list 0 (- (length list) n)))

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import std.stdio;
T[] forwardDifference(T)(in T[] data, in int level) pure nothrow
in {
assert(level >= 0 && level < data.length);
} body {
//auto result = data.dup; // not nothrow
auto result = data ~ []; // slower
foreach (i; 0 .. level)
foreach (j, ref el; result[0 .. $ - i - 1])
el = result[j + 1] - el;
result.length -= level;
return result;
}
void main() {
auto data = [90.5, 47, 58, 29, 22, 32, 55, 5, 55, 73.5];
foreach (level; 0 .. data.length)
writeln(forwardDifference(data, level));
}

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import std.stdio, std.algorithm, std.range, std.array;
auto forwardDifference(Range)(Range d, in int level) {
foreach (_; 0 .. level)
d = zip(d[1 .. $], d).map!q{ a[0] - a[1] }().array();
return d;
}
void main() {
auto data = [90.5, 47, 58, 29, 22, 32, 55, 5, 55, 73.5];
foreach (level; 0 .. data.length)
writeln(forwardDifference(data, level));
}

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import std.stdio;
T[] forwardDifference(T)(T[] s, in int n) pure {
foreach (_; 0 .. n)
s[] -= s[1 .. $];
return s[0 .. $ - n];
}
void main() {
immutable A = [90.5, 47, 58, 29, 22, 32, 55, 5, 55, 73.5];
foreach (level; 0 .. A.length)
writeln(forwardDifference(A.dup, level));
}

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import std.stdio, std.range;
void main() {
auto D = [90.5, 47, 58, 29, 22, 32, 55, 5, 55, 73.5];
auto R = recurrence!q{(a[n-1].dup[] -= a[n-1][1..$])[0..$-1]}(D);
foreach (di; take(R, D.length))
writeln(di);
}

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pragma.enable("accumulator")
/** Single step. */
def forwardDifference(seq :List) {
return accum [] for i in 0..(seq.size() - 2) {
_.with(seq[i + 1] - seq[i])
}
}
/** Iterative implementation of the goal. */
def nthForwardDifference1(var seq :List, n :(int >= 0)) {
for _ in 1..n { seq := forwardDifference(seq) }
return seq
}
/** Imperative implementation of the goal. */
def nthForwardDifference2(seq :List, n :(int >= 0)) {
def buf := seq.diverge()
def finalSize := seq.size() - n
for lim in (finalSize..!seq.size()).descending() {
for i in 0..!lim {
buf[i] := buf[i + 1] - buf[i]
}
}
return buf.run(0, finalSize)
}
? def sampleData := [90, 47, 58, 29, 22, 32, 55, 5, 55, 73]
> for n in 0..10 {
> def r1 := nthForwardDifference1(sampleData, n)
> require(r1 == nthForwardDifference2(sampleData, n))
> println(r1)
> }

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USING: kernel math math.vectors sequences ;
IN: rosetacode
: 1-order ( seq -- seq' )
[ rest-slice ] keep v- ;
: n-order ( seq n -- seq' )
dup 0 <=
[ drop ] [ [ 1-order ] times ] if ;

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: forward-difference
dup 0
?do
swap rot over i 1+ - 0
?do dup i cells + dup cell+ @ over @ - swap ! loop
swap rot
loop -
;
create a
90 , 47 , 58 , 29 , 22 , 32 , 55 , 5 , 55 , 73 ,
: test a 10 9 forward-difference bounds ?do i ? loop ;
test

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MODULE DIFFERENCE
IMPLICIT NONE
CONTAINS
SUBROUTINE Fdiff(a, n)
INTEGER, INTENT(IN) :: a(:), n
INTEGER :: b(SIZE(a))
INTEGER :: i, j, arraysize
b = a
arraysize = SIZE(b)
DO i = arraysize-1, arraysize-n, -1
DO j = 1, i
b(j) = b(j+1) - b(j)
END DO
END DO
WRITE (*,*) b(1:arraysize-n)
END SUBROUTINE Fdiff
END MODULE DIFFERENCE

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PROGRAM TEST
USE DIFFERENCE
IMPLICIT NONE
INTEGER :: array(10) = (/ 90, 47, 58, 29, 22, 32, 55, 5, 55, 73 /)
INTEGER :: i
DO i = 1, 9
CALL Fdiff(array, i)
END DO
END PROGRAM TEST

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package main
import "fmt"
func main() {
a := []int{90, 47, 58, 29, 22, 32, 55, 5, 55, 73}
fmt.Println(a)
fmt.Println(fd(a, 9))
}
func fd(a []int, ord int) []int {
for i := 0; i < ord; i++ {
for j := 0; j < len(a)-i-1; j++ {
a[j] = a[j+1] - a[j]
}
}
return a[:len(a)-ord]
}

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forwardDifference xs = zipWith (-) (tail xs) xs
nthForwardDifference xs n = iterate forwardDifference xs !! n
> take 10 (iterate forwardDifference [90, 47, 58, 29, 22, 32, 55, 5, 55, 73])
[[90,47,58,29,22,32,55,5,55,73],
[-43,11,-29,-7,10,23,-50,50,18],
[54,-40,22,17,13,-73,100,-32],
[-94,62,-5,-4,-86,173,-132],
[156,-67,1,-82,259,-305],
[-223,68,-83,341,-564],
[291,-151,424,-905],
[-442,575,-1329],
[1017,-1904],
[-2921]]

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REAL :: n=10, list(n)
list = ( 90, 47, 58, 29, 22, 32, 55, 5, 55, 73 )
WRITE(Format='i1, (i6)') 0, list
DO i = 1, n-1
ALIAS(list,1, diff,n-i) ! rename list(1 ... n-i) with diff
diff = list($+1) - diff ! $ is the running left hand array index
WRITE(Format='i1, (i6)') i, diff
ENDDO
END

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0 90 47 58 29 22 32 55 5 55 73
1 -43 11 -29 -7 10 23 -50 50 18
2 54 -40 22 17 13 -73 100 -32
3 -94 62 -5 -4 -86 173 -132
4 156 -67 1 -82 259 -305
5 -223 68 -83 341 -564
6 291 -151 424 -905
7 -442 575 -1329
8 1017 -1904
9 -2921

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print,(x = randomu(seed,8)*100)
15.1473 58.0953 82.7465 16.8637 97.7182 59.7856 17.7699 74.9154
print,ts_diff(x,1)
-42.9479 -24.6513 65.8828 -80.8545 37.9326 42.0157 -57.1455 0.000000
print,ts_diff(x,2)
-18.2967 -90.5341 146.737 -118.787 -4.08316 99.1613 0.000000 0.000000
print,ts_diff(x,3)
72.2374 -237.271 265.524 -114.704 -103.244 0.000000 0.000000 0.000000

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procedure main(A) # Compute all forward difference orders for argument list
every order := 1 to (*A-1) do showList(order, fdiff(A, order))
end
procedure fdiff(A, order)
every 1 to order do {
every put(B := [], A[i := 2 to *A] - A[i-1])
A := B
}
return A
end
procedure showList(order, L)
writes(right(order,3),": ")
every writes(!L," ")
write()
end

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fd=: 2&(-~/\)

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fd=:}.-}:^:

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list =: 90 47 58 29 22 32 55 5 55 73 NB. Some numbers
1 fd list
_43 11 _29 _7 10 23 _50 50 18
2 fd list
54 _40 22 17 13 _73 100 _32

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1 2 3 fd list NB. First, second, and third forward differences (simultaneously)
43 _11 29 7 _10 _23 50 _50 _18
54 _40 22 17 13 _73 100 _32 0
94 _62 5 4 86 _173 132 0 0
a: fd list NB. All forward differences
90 47 58 29 22 32 55 5 55 73
43 _11 29 7 _10 _23 50 _50 _18 0
54 _40 22 17 13 _73 100 _32 0 0
94 _62 5 4 86 _173 132 0 0 0
156 _67 1 _82 259 _305 0 0 0 0
223 _68 83 _341 564 0 0 0 0 0
291 _151 424 _905 0 0 0 0 0 0
442 _575 1329 0 0 0 0 0 0 0
1017 _1904 0 0 0 0 0 0 0 0
2921 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0

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import java.util.Arrays;
public class FD {
public static void main(String args[]) {
double[] a = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73};
System.out.println(Arrays.toString(dif(a, 1)));
System.out.println(Arrays.toString(dif(a, 2)));
System.out.println(Arrays.toString(dif(a, 9)));
System.out.println(Arrays.toString(dif(a, 10))); //let's test
System.out.println(Arrays.toString(dif(a, 11)));
System.out.println(Arrays.toString(dif(a, -1)));
System.out.println(Arrays.toString(dif(a, 0)));
}
public static double[] dif(double[] a, int n) {
if (n < 0)
return null; // if the programmer was dumb
for (int i = 0; i < n && a.length > 0; i++) {
double[] b = new double[a.length - 1];
for (int j = 0; j < b.length; j++){
b[j] = a[j+1] - a[j];
}
a = b; //"recurse"
}
return a;
}
}

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to fwd.diff :l
if empty? :l [output []]
if empty? bf :l [output []]
output fput (first bf :l)-(first :l) fwd.diff bf :l
end
to nth.fwd.diff :n :l
if :n = 0 [output :l]
output nth.fwd.diff :n-1 fwd.diff :l
end
show nth.fwd.diff 9 [90 47 58 29 22 32 55 5 55 73]
[-2921]

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function dif(a, b, ...)
if(b) then return b-a, dif(b, ...) end
end
function dift(t) return {dif(unpack(t))} end
print(unpack(dift{1,3,6,10,15}))

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Y = diff(X,n);

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diff([1 2 3 4 5])
ans =
1 1 1 1

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i={3,5,12,1,6,19,6,2,4,9};
Differences[i]

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{2, 7, -11, 5, 13, -13, -4, 2, 5}

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i={3,5,12,1,6,19,6,2,4,9};
Differences[i,n]

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ldiff(u, n) := block([m: length(u)], for j thru n do u: makelist(u[i + 1] - u[i], i, 1, m - j), u);

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<?php
function forwardDiff($anArray, $times = 1) {
if ($times <= 0) { return $anArray; }
for ($accumilation = array(), $i = 1, $j = count($anArray); $i < $j; ++$i) {
$accumilation[] = $anArray[$i] - $anArray[$i - 1];
}
if ($times === 1) { return $accumilation; }
return forwardDiff($accumilation, $times - 1);
}
class ForwardDiffExample extends PweExample {
function _should_run_empty_array_for_single_elem() {
$expected = array($this->rand()->int());
$this->spec(forwardDiff($expected))->shouldEqual(array());
}
function _should_give_diff_of_two_elem_as_single_elem() {
$twoNums = array($this->rand()->int(), $this->rand()->int());
$expected = array($twoNums[1] - $twoNums[0]);
$this->spec(forwardDiff($twoNums))->shouldEqual($expected);
}
function _should_compute_correct_forward_diff_for_longer_arrays() {
$diffInput = array(10, 2, 9, 6, 5);
$expected = array(-8, 7, -3, -1);
$this->spec(forwardDiff($diffInput))->shouldEqual($expected);
}
function _should_apply_more_than_once_if_specified() {
$diffInput = array(4, 6, 9, 3, 4);
$expectedAfter1 = array(2, 3, -6, 1);
$expectedAfter2 = array(1, -9, 7);
$this->spec(forwardDiff($diffInput, 1))->shouldEqual($expectedAfter1);
$this->spec(forwardDiff($diffInput, 2))->shouldEqual($expectedAfter2);
}
function _should_return_array_unaltered_if_no_times() {
$this->spec(forwardDiff($expected = array(1,2,3), 0))->shouldEqual($expected);
}
}

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sub dif {
my @s = @_;
map { $s[$_+1] - $s[$_] } 0 .. $#s-1
}
sub difn {
my ($n, @s) = @_;
@s = dif @s foreach 1..$n;
@s
}

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(de fdiff (Lst)
(mapcar - (cdr Lst) Lst) )
(for (L (90 47 58 29 22 32 55 5 55 73) L (fdiff L))
(println L) )

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>>> dif = lambda s: [x-s[i] for i,x in enumerate(s[1:])]
>>> # or, dif = lambda s: [x-y for x,y in zip(s[1:],s)]
>>> difn = lambda s, n: difn(dif(s), n-1) if n else s
>>> s = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73]
>>> difn(s, 0)
[90, 47, 58, 29, 22, 32, 55, 5, 55, 73]
>>> difn(s, 1)
[-43, 11, -29, -7, 10, 23, -50, 50, 18]
>>> difn(s, 2)
[54, -40, 22, 17, 13, -73, 100, -32]
>>> from pprint import pprint
>>> pprint( [difn(s, i) for i in xrange(10)] )
[[90, 47, 58, 29, 22, 32, 55, 5, 55, 73],
[-43, 11, -29, -7, 10, 23, -50, 50, 18],
[54, -40, 22, 17, 13, -73, 100, -32],
[-94, 62, -5, -4, -86, 173, -132],
[156, -67, 1, -82, 259, -305],
[-223, 68, -83, 341, -564],
[291, -151, 424, -905],
[-442, 575, -1329],
[1017, -1904],
[-2921]]

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forwarddif <- function(a, n) {
if ( n == 1 )
a[2:length(a)] - a[1:length(a)-1]
else {
r <- forwarddif(a, 1)
forwarddif(r, n-1)
}
}
fdiff <- function(a, n) {
r <- a
for(i in 1:n) {
r <- r[2:length(r)] - r[1:length(r)-1]
}
r
}
v <- c(90, 47, 58, 29, 22, 32, 55, 5, 55, 73)
print(forwarddif(v, 9))
print(fdiff(v, 9))

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/*REXX program to compute the forward difference of a list of numbers.*/
/* ┌───────────────────────────────────────────────────────────────────┐
/\ n n n-k
{delta} / \ n [ƒ] (x) Σ Ç (-1) ƒ(x+k)
/____\ k=0 k
{n=order} {Ç=comb or binomial coeff.}
*/
numeric digits 100 /*ensure enough accuracy. */
arg numbers ',' ord /*input: x1 x2 x3 x4 ... ,ORD */
if numbers=='' then numbers='90 47 58 29 22 32 55 5 55 73' /*default?*/
w=words(numbers) /*set W to # of numbers in list.*/
do i=1 for w /*validate input (valid numbers?)*/
@.i=word(numbers,i) /*assign the next # in the list. */
if \datatype(@.i,'N') then call ser @.i "isn't a valid number"
@.i=@.i/1 /*normalize the #, prettify the #*/
end /*i*/
/*═════════════════════════════════════════process the (optional) input.*/
if w==0 then call ser 'no numbers were specified'
if ord\=='' & ord<0 then call ser ord "(ner) can't be negative"
if ord\=='' & ord>w then call ser ord "(ner) can't be greater than" w
say right(w 'numbers: ' numbers,64) /*sloppy way to do a header, ... */
say right(copies('',length(numbers)),64) /* and the header fence.*/
if ord=='' then do; bot=0; top=w; end /*define default ners.*/
else do; bot=n; top=n; end /*just a specific ner?*/
/*═════════════════════════════════════════where da rubber meets da road*/
do order=bot to top; do r=1 for w; !.r=@.r; end; $=
do j=1 for order; d=!.j; do k=j+1 to w /*order diff.*/
parse value !.k !.k-d with d !.k
end /*k*/
end /*j*/
do i=order+1 to w /*build list.*/
$=$ !.i/1 /*append it. */
end /*i*/
if $=='' then $='[null]' /*pretty null*/
what=right(order,length(w))th(order)'-order' /*nice format*/
say what 'forward difference vector = ' strip($) /*display it.*/
end /*o*/
exit /*stick a fork in it, we're done.*/
/*──────────────────────────────────SER subroutine──────────────────────*/
ser: say; say '*** error! ***'; say arg(1); say; exit 13
/*──────────────────────────────────TH subroutine───────────────────────*/
th: parse arg ?; return word('th st nd rd',1+?//10*(?//100%10\==1)*(?//10<4))

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/* REXX ***************************************************************
* Forward differences
* 18.08.2012 Walter Pachl derived from PL/I
**********************************************************************/
Do n=-1 To 11
Call differences '90 47 58 29 22 32 55 5 55 73',n
End
Exit
differences: Procedure
Parse Arg a,n
m=words(a)
Select
When n<0 Then Say 'n is negative:' n '<' 0
When n>m Then Say 'n is too large:' n '>' m
Otherwise Do
Do i=1 By 1 while a<>''
Parse Var a a.i a
End
Do i = 1 to n;
t = a.i;
Do j = i+1 to m;
u = a.j
a.j = a.j-t;
t = u;
end;
end;
ol=''
Do k=n+1 to m
ol=ol a.k
End
Say n ol
End
End
Return

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def dif(s)
s.each_cons(2).collect { |x, y| y - x }
end
def difn(s, n)
n.times.inject(s) { |s, | dif(s) }
end

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p dif([1, 23, 45, 678]) # => [22, 22, 633]
p difn([1, 23, 45, 678], 2) # => [0, 611]

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def fdiff(xs: List[Int]) = (xs.tail, xs).zipped.map(_ - _)
def fdiffn(i: Int, xs: List[Int]): List[Int] = if (i == 1) fdiff(xs) else fdiffn(i - 1, fdiff(xs))

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val l=List(90,47,58,29,22,32,55,5,55,73)
(1 to 9)foreach(x=>println(fdiffn(x,l)))

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(define (forward-diff lst)
(if (or (null? lst) (null? (cdr lst)))
'()
(cons (- (cadr lst) (car lst))
(forward-diff (cdr lst)))))
(define (nth-forward-diff n xs)
(if (= n 0)
xs
(nth-forward-diff (- n 1)
(forward-diff xs))))

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Array extend [
difference [
^self allButFirst with: self allButLast collect: [ :a :b | a - b ]
]
nthOrderDifference: n [
^(1 to: n) inject: self into: [ :old :unused | old difference ]
]
]
s := #(90 47 58 29 22 32 55 5 55 73)
1 to: s size - 1 do: [ :i |
(s nthOrderDifference: i) printNl ]

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proc do_fwd_diff {list} {
set previous [lindex $list 0]
set new [list]
foreach current [lrange $list 1 end] {
lappend new [expr {$current - $previous}]
set previous $current
}
return $new
}
proc fwd_diff {list order} {
while {$order >= 1} {
set list [do_fwd_diff $list]
incr order -1
}
return $list
}
set a {90.5 47 58 29 22 32 55 5 55 73.5}
for {set order 0} {$order <= 10} {incr order} {
puts [format "%d\t%s" $order [fwd_diff $a $order]]
}