A-M baby

Task/Longest-common-subsequence/Python/longest-common-subsequence-1.py

@@ -0,0 +1,12 @@
+def lcs(xstr, ystr):
+    """
+    >>> lcs('thisisatest', 'testing123testing')
+    'tsitest'
+    """
+    if not xstr or not ystr:
+        return ""
+    x, xs, y, ys = xstr[0], xstr[1:], ystr[0], ystr[1:]
+    if x == y:
+        return x + lcs(xs, ys)
+    else:
+        return max(lcs(xstr, ys), lcs(xs, ystr), key=len)

Task/Longest-common-subsequence/Python/longest-common-subsequence-2.py

@@ -0,0 +1,2 @@
+if __name__=="__main__":
+    import doctest; doctest.testmod()

Task/Longest-common-subsequence/Python/longest-common-subsequence-3.py

@@ -0,0 +1,24 @@
+def lcs(a, b):
+    lengths = [[0 for j in range(len(b)+1)] for i in range(len(a)+1)]
+    # row 0 and column 0 are initialized to 0 already
+    for i, x in enumerate(a):
+        for j, y in enumerate(b):
+            if x == y:
+                lengths[i+1][j+1] = lengths[i][j] + 1
+            else:
+                lengths[i+1][j+1] = \
+                    max(lengths[i+1][j], lengths[i][j+1])
+    # read the substring out from the matrix
+    result = ""
+    x, y = len(a), len(b)
+    while x != 0 and y != 0:
+        if lengths[x][y] == lengths[x-1][y]:
+            x -= 1
+        elif lengths[x][y] == lengths[x][y-1]:
+            y -= 1
+        else:
+            assert a[x-1] == b[y-1]
+            result = a[x-1] + result
+            x -= 1
+            y -= 1
+    return result