2016 Update

Task/Call-a-function/Elixir/call-a-function.elixir

@@ -0,0 +1,57 @@
+# Anonymous function
+
+foo = fn() ->
+  IO.puts("foo")
+end
+
+foo()  #=> undefined function foo/0
+foo.() #=> "foo"
+
+# Using `def`
+
+defmodule Foo do
+  def foo do
+    IO.puts("foo")
+  end
+end
+
+Foo.foo    #=> "foo"
+Foo.foo()  #=> "foo"
+
+
+# Calling a function with a fixed number of arguments
+
+defmodule Foo do
+  def foo(x) do
+    IO.puts(x)
+  end
+end
+
+Foo.foo("foo") #=> "foo"
+
+# Calling a function with a default argument
+
+defmodule Foo do
+  def foo(x \\ "foo") do
+    IO.puts(x)
+  end
+end
+
+Foo.foo()      #=> "foo"
+Foo.foo("bar") #=> "bar"
+
+# There is no such thing as a function with a variable number of arguments. So in Elixir, you'd call the function with a list
+
+defmodule Foo do
+  def foo(args) when is_list(args) do
+    Enum.each(args, &(IO.puts(&1)))
+  end
+end
+
+# Calling a function with named arguments
+
+defmodule Foo do
+  def foo([x: x]) do
+    IO.inspect(x)
+  end
+end