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Ingy döt Net 2023-07-01 11:58:00 -04:00
parent 72d218235f
commit f23f22d71c
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import Data.List (permutations)
import Control.Monad (guard)
dinesman :: [(Int,Int,Int,Int,Int)]
dinesman = do
-- baker, cooper, fletcher, miller, smith are integers representing
-- the floor that each person lives on, from 1 to 5
-- Baker, Cooper, Fletcher, Miller, and Smith live on different floors
-- of an apartment house that contains only five floors.
[baker, cooper, fletcher, miller, smith] <- permutations [1..5]
-- Baker does not live on the top floor.
guard $ baker /= 5
-- Cooper does not live on the bottom floor.
guard $ cooper /= 1
-- Fletcher does not live on either the top or the bottom floor.
guard $ fletcher /= 5 && fletcher /= 1
-- Miller lives on a higher floor than does Cooper.
guard $ miller > cooper
-- Smith does not live on a floor adjacent to Fletcher's.
guard $ abs (smith - fletcher) /= 1
-- Fletcher does not live on a floor adjacent to Cooper's.
guard $ abs (fletcher - cooper) /= 1
-- Where does everyone live?
return (baker, cooper, fletcher, miller, smith)
main :: IO ()
main = do
print $ head dinesman -- print first solution: (3,2,4,5,1)
print dinesman -- print all solutions (only one): [(3,2,4,5,1)]

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import Data.List (permutations)
main :: IO ()
main =
print
[ ( "Baker lives on " <> show b,
"Cooper lives on " <> show c,
"Fletcher lives on " <> show f,
"Miller lives on " <> show m,
"Smith lives on " <> show s
)
| [b, c, f, m, s] <- permutations [1 .. 5],
b /= 5,
c /= 1,
f /= 1,
f /= 5,
m > c,
abs (s - f) > 1,
abs (c - f) > 1
]