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def createFoos1 = { n -> (0..<n).collect { new Foo() } }
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// Following fails, creates n references to same object
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def createFoos2 = {n -> [new Foo()] * n }
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[createFoos1, createFoos2].each { createFoos ->
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print "Objects distinct for n = "
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(2..<20).each { n ->
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def foos = createFoos(n)
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foos.eachWithIndex { here, i ->
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foos.eachWithIndex { there, j ->
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assert (here == there) == (i == j)
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}
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}
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print "${n} "
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}
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println()
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}
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