Imports System.Numerics Module Program Function chowla(n As Integer) As Integer chowla = 0 : Dim j As Integer, i As Integer = 2 While i * i <= n If n Mod i = 0 Then j = n / i : chowla += i : If i <> j Then chowla += j i += 1 End While End Function Function chowla1(ByRef n As BigInteger, x As Integer) As BigInteger chowla1 = 1 : Dim j As BigInteger, lim As BigInteger = BigInteger.Pow(2, x - 1) For i As BigInteger = 2 To lim If n Mod i = 0 Then j = n / i : chowla1 += i : If i <> j Then chowla1 += j Next End Function Function sieve(ByVal limit As Integer) As Boolean() Dim c As Boolean() = New Boolean(limit - 1) {}, i As Integer = 3 While i * 3 < limit If Not c(i) AndAlso (chowla(i) = 0) Then Dim j As Integer = 3 * i While j < limit : c(j) = True : j += 2 * i : End While End If : i += 2 End While Return c End Function Sub Main(args As String()) For i As Integer = 1 To 37 Console.WriteLine("chowla({0}) = {1}", i, chowla(i)) Next Dim count As Integer = 1, limit As Integer = CInt((10000000.0)), power As Integer = 100, c As Boolean() = sieve(limit) For i As Integer = 3 To limit - 1 Step 2 If Not c(i) Then count += 1 If i = power - 1 Then Console.WriteLine("Count of primes up to {0,10:n0} = {1:n0}", power, count) power = power * 10 End If Next count = 0 Dim p As BigInteger, k As BigInteger = 2, kk As BigInteger = 3 For i As Integer = 2 To 31 ' if you dare, change the 31 to 61 or 89 If {2, 3, 5, 7, 13, 17, 19, 31, 61, 89}.Contains(i) Then p = k * kk If chowla1(p, i) = p Then Console.WriteLine("{0,25:n0} is a number that is perfect", p) st = DateTime.Now count += 1 End If End If k = kk + 1 : kk += k Next Console.WriteLine("There are {0} perfect numbers <= {1:n0}", count, 25 * BigInteger.Pow(10, 18)) If System.Diagnostics.Debugger.IsAttached Then Console.ReadKey() End Sub End Module