Write functions to calculate the definite integral of a function {{math|1=''ƒ(x)''}} using ''all'' five of the following methods: :* [[wp:Rectangle_method|rectangular]] :** left :** right :** midpoint :* [[wp:Trapezoidal_rule|trapezium]] :* [[wp:Simpson%27s_rule|Simpson's]] :** composite Your functions should take in the upper and lower bounds ({{math|''a''}} and {{math|''b''}}), and the number of approximations to make in that range ({{math|''n''}}). Assume that your example already has a function that gives values for {{math|1=''ƒ(x)''}} . Simpson's method is defined by the following pseudo-code: {| class="mw-collapsible mw-collapsed" |+ Pseudocode: Simpson's method, composite |- | '''procedure''' quad_simpson_composite(f, a, b, n) h := (b - a) / n sum1 := f(a + h/2) sum2 := 0 loop on i from 1 to (n - 1) sum1 := sum1 + f(a + h * i + h/2) sum2 := sum2 + f(a + h * i)   ''answer'' := (h / 6) * (f(a) + f(b) + 4*sum1 + 2*sum2) |} Demonstrate your function by showing the results for: *   {{math|1=ƒ(x) = x3}},       where   '''x'''   is     [0,1],       with           100 approximations.   The exact result is     0.25               (or 1/4) *   {{math|1=ƒ(x) = 1/x}},     where   '''x'''   is   [1,100],     with        1,000 approximations.   The exact result is     4.605170+     (natural log of 100) *   {{math|1=ƒ(x) = x}},         where   '''x'''   is   [0,5000],   with 5,000,000 approximations.   The exact result is   12,500,000 *   {{math|1=ƒ(x) = x}},         where   '''x'''   is   [0,6000],   with 6,000,000 approximations.   The exact result is   18,000,000
;See also: *   [[Active object]] for integrating a function of real time. *   [[Special:PrefixIndex/Numerical integration]] for other integration methods.