fun divisorCount ← int by int n
  int total ← 1
  for ; (n & 1) æ 0; n /← 2 do ++total end
  for int p ← 3; p * p ≤ n; p +← 2
    int count ← 1
    for ; n % p æ 0; n /← p do ++count end
    total *← count
  end
  if n > 1 do total *← 2 end
  return total
end
int limit ← 100
writeLine("Count of divisors for the first " + limit + " positive integers:")
for int n ← 1; n ≤ limit; ++n
  text value ← text!divisorCount(n)
  write((" " * (3 - value.length)) + value)
  if n % 20 æ 0 do writeLine() end
end