Given M as a list of items and another list N of items chosen from M, create M' as a list with the ''first'' occurrences of items from N sorted to be in one of the set of indices of their original occurrence in M but in the order given by their order in N.
That is, items in N are taken from M without replacement, then the corresponding positions in M' are filled by successive items from N.
;For example:
:if M is 'the cat sat on the mat'
:And N is 'mat cat'
:Then the result M' is 'the mat sat on the cat'.
The words not in N are left in their original positions.
If there are duplications then only the first instances in M up to as many as are mentioned in N are potentially re-ordered.
;For example:
: M = 'A B C A B C A B C'
: N = 'C A C A'
Is ordered as:
: M' = 'C B A C B A A B C'
Show the output, here, for at least the following inputs:
Data M: 'the cat sat on the mat' Order N: 'mat cat'
Data M: 'the cat sat on the mat' Order N: 'cat mat'
Data M: 'A B C A B C A B C' Order N: 'C A C A'
Data M: 'A B C A B D A B E' Order N: 'E A D A'
Data M: 'A B' Order N: 'B'
Data M: 'A B' Order N: 'B A'
Data M: 'A B B A' Order N: 'B A'
;Cf:
* [[Sort disjoint sublist]]