/*PD1 REXX pgm does prime decomposition of a range of positive integers (with a prime count)*/ Call Time 'R' numeric digits 1000 /*handle thousand digits for the powers*/ parse arg bot top step base add /*get optional arguments from the C.L. */ if bot=='' then do; bot=1; top=100; end /*no BOT given? Then use the default.*/ if top=='' then top=bot /* " TOP? " " " " " */ if step=='' then step= 1 /* " STEP? " " " " " */ if add =='' then add= -1 /* " ADD? " " " " " */ tell= top>0; top=abs(top) /*if TOP is negative, suppress displays*/ w=length(top) /*get maximum width for aligned display*/ if base\=='' then w=length(base**top) /*will be testing powers of two later? */ commat.=left('', 7); commat.0="{unity}"; commat.1='[prime]' /*some literals: pad; prime (or not).*/ numeric digits max(9, w+1) /*maybe increase the digits precision. */ hash=0 /*hash: is the number of primes found. */ do n=bot to top by step /*process a single number or a range.*/ ?=n; if base\=='' then ?=base**n + add /*should we perform a "Mercenne" test? */ pf=factr(?); f=words(pf) /*get prime factors; number of factors.*/ if f==1 then hash=hash+1 /*Is N prime? Then bump prime counter.*/ if tell then say right(?,w) right('('f")",9) 'prime factors: ' commat.f pf end /*n*/ say ps= 'primes'; if p==1 then ps= "prime" /*setup for proper English in sentence.*/ say right(hash, w+9+1) ps 'found.' /*display the number of primes found. */ Say 'PD1 took' time('E') 'seconds' exit /*stick a fork in it, we're all done. */ /*--------------------------------------------------------------------------------------*/ factr: procedure; parse arg x 1 d,dollar /*set X, D to argument 1; dollar to null.*/ if x==1 then return '' /*handle the special case of X = 1. */ do while x//2==0; dollar=dollar 2; x=x%2; end /*append all the 2 factors of new X.*/ do while x//3==0; dollar=dollar 3; x=x%3; end /* " " " 3 " " " " */ do while x//5==0; dollar=dollar 5; x=x%5; end /* " " " 5 " " " " */ do while x//7==0; dollar=dollar 7; x=x%7; end /* " " " 7 " " " " */ /* ___*/ q=1; do while q<=x; q=q*4; end /*these two lines compute integer v X */ r=0; do while q>1; q=q%4; _=d-r-q; r=r%2; if _>=0 then do; d=_; r=r+q; end; end do j=11 by 6 to r /*insure that J isn't divisible by 3.*/ parse var j '' -1 _ /*obtain the last decimal digit of J. */ if _\==5 then do while x//j==0; dollar=dollar j; x=x%j; end /*maybe reduce by J. */ if _ ==3 then iterate /*Is next Y is divisible by 5? Skip.*/ y=j+2; do while x//y==0; dollar=dollar y; x=x%y; end /*maybe reduce by J. */ end /*j*/ /* [?] The dollar list has a leading blank.*/ if x==1 then return dollar /*Is residual=unity? Then don't append.*/ return dollar x /*return dollar with appended residual. */