RosettaCodeData/Task/EKG-sequence-convergence/EasyLang/ekg-sequence-convergence.easy
2025-08-11 18:05:26 -07:00

22 lines
416 B
Text

func contains a[] b .
for a in a[] : if a = b : return 1
return 0
.
func gcd a b .
if b = 0 : return a
return gcd b (a mod b)
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starts[] = [ 2 5 7 9 10 ]
len ekg[][] 5
for s to 5
ekg[s][] = [ 1 starts[s] ]
for n = 2 to 10
for i = 2 to 1 / 0
if contains ekg[s][] i = 0 and gcd ekg[s][n], i > 1
ekg[s][] &= i
break 1
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.
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print ekg[s][]
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