RosettaCodeData/Task/Fibonacci-sequence/FunL/fibonacci-sequence-5.funl
2023-07-01 13:44:08 -04:00

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Text

import math.sqrt
def fib( n ) =
phi = (1 + sqrt( 5 ))/2
int( (phi^n - (-phi)^-n)/sqrt(5) + .5 )