15 lines
559 B
Text
15 lines
559 B
Text
V perms = [‘ABCD’, ‘CABD’, ‘ACDB’, ‘DACB’, ‘BCDA’, ‘ACBD’, ‘ADCB’, ‘CDAB’,
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‘DABC’, ‘BCAD’, ‘CADB’, ‘CDBA’, ‘CBAD’, ‘ABDC’, ‘ADBC’, ‘BDCA’,
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‘DCBA’, ‘BACD’, ‘BADC’, ‘BDAC’, ‘CBDA’, ‘DBCA’, ‘DCAB’]
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V missing = ‘’
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L(i) 0.<4
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V cnt = [0] * 4
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L(j) 0 .< perms.len
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cnt[perms[j][i].code - ‘A’.code]++
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L(j) 0.<4
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I cnt[j] != factorial(4-1)
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missing ‘’= Char(code' ‘A’.code + j)
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L.break
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print(missing)
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