RosettaCodeData/Task/Floyds-triangle/Mathematica/floyds-triangle.math
2023-07-01 13:44:08 -04:00

4 lines
211 B
Text

f=Function[n,
Most/@(Range@@@Partition[FindSequenceFunction[{1,2,4,7,11}]/@Range[n+1],2,1])]
TableForm[f@5,TableAlignments->Right,TableSpacing->{1,1}]
TableForm[f@14,TableAlignments->Right,TableSpacing->{1,1}]