RosettaCodeData/Task/Operator-precedence/Lambdatalk/operator-precedence.lambdatalk
2023-07-01 13:44:08 -04:00

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As with Common Lisp and Scheme, Lambdatalk uses s-expressions so there is no need for operator precedence.
Such an expression "1+2*3+4" is written {+ 1 {* 2 3} 4}