22 lines
613 B
JavaScript
22 lines
613 B
JavaScript
function is_palindrome(n) {
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return n == Number([...String(n)].toReversed().join(""));
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}
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function is_gapful(n) {
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const digits = [...String(n)].map(Number);
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const div = 10 * digits.shift() + digits.pop();
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return Number.isInteger(n / div);
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}
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for (let d = 2; d <= 9; d++) {
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console.log(`|Palindromic gapful numbers ending in ${d}|`);
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let nums = [], n = 100 + d;
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while (nums.length < 100) {
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if (is_gapful(n) && is_palindrome(n)) {
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nums.push(n);
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}
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n += 10;
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}
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console.log(`First 20: ${nums.slice(0, 20).join(" ")}`);
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console.log(`86th-100th: ${nums.slice(85, 100).join(" ")}`);
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}
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