RosettaCodeData/Task/Parallel-brute-force/Scala/parallel-brute-force-3.scala
2023-07-01 13:44:08 -04:00

34 lines
1.5 KiB
Scala

import java.security.MessageDigest
import scala.collection.parallel.immutable.ParVector
object EncryptionCracker {
def main(args: Array[String]): Unit = {
val hash1 = "1115dd800feaacefdf481f1f9070374a2a81e27880f187396db67958b207cbad"
val hash2 = "3a7bd3e2360a3d29eea436fcfb7e44c735d117c42d1c1835420b6b9942dd4f1b"
val hash3 = "74e1bb62f8dabb8125a58852b63bdf6eaef667cb56ac7f7cdba6d7305c50a22f"
val cracker: String => Option[String] = crackLazy('a' to 'z', 5, 1000000)
for(tmp <- Seq(hash2, hash1, hash3)){
println(s"$tmp")
cracker(tmp) match{
case Some(s) => println(s"String: $s\n")
case None => println("Failed\n")
}
}
}
def getHash(str: String): String = MessageDigest
.getInstance("SHA-256")
.digest(str.getBytes("UTF-8"))
.map("%02x".format(_)).mkString
def crackLazy(charSet: Seq[Char], len: Int, num: Int)(hash: String): Option[String] = charSet
.flatMap(Vector.fill(len)(_)) //Duplicate characters so they can be used any number of times
.combinations(len) //Generate distinct sets of characters
.flatMap(_.permutations.map(_.mkString)) //Generate all permutations for each character set
.grouped(num) //Partition into bite-size chunks
.map(_.to(ParVector).find(str => getHash(str) == hash)) //Convert each chunk into a ParVector and search it
.collectFirst{case Some(res) => res} //Get the first hit if one is found
}