RosettaCodeData/Task/Perfect-numbers/Python/perfect-numbers-3.py
2023-07-01 13:44:08 -04:00

6 lines
124 B
Python

def perf2(n):
return n == sum(i for i in range(1, n) if n % i == 0)
print (
list(filter(perf2, range(1, 10001)))
)