RosettaCodeData/Task/Pythagorean-triples/Mathematica/pythagorean-triples-1.math
2023-07-01 13:44:08 -04:00

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pythag[n_]:=Block[{soln=Solve[{a^2+b^2==c^2,a+b+c<=n,0<a<b<c},{a,b,c},Integers]},{Length[soln],Count[GCD[a,b]/.soln,1]}]